Friends,
I come across a resent thread describes the differences between
getc() vs fgetc().
There some body stated the sentence "evaluate its parameter more than
once".
I cannot understand the word ‘evaluate' in the message. The poster
also gives a
Example for the sentence, which is hard for me to understand. I
searched the FAQ
and I think I have missed it. The thread's link is: http://groups.google.com/groups?hl=e...c2c8e1d&rnum=1
Thanks 2  1407  da***********@y ahoo.com wrote:
Friends,
I come across a resent thread describes the differences between
getc() vs fgetc().
There some body stated the sentence
"evaluate its parameter more than once".
I cannot understand the word ‘evaluate' in the message.
The sizeof operator does *not* evaluate it's operand.
The printf function *does* evaluate it's arguments.
If you have
char x = 0;
and then also
printf("%u, ", (unsigned)sizeo f ++x); /* x is not incremented */
printf("%d, ", x); /* x is not incremented */
printf("%d\n", ++x); /* x is incremented */
.... then the output will be:
1, 0, 1
--
pete
pete <pf*****@mindsp ring.com> wrote in message news:<40******* ****@mindspring .com>... da***********@y ahoo.com wrote:
Friends,
I come across a resent thread describes the differences between
getc() vs fgetc().
There some body stated the sentence
"evaluate its parameter more than once".
I cannot understand the word ?evaluate' in the message.
The sizeof operator does *not* evaluate it's operand.
The printf function *does* evaluate it's arguments.
If you have
char x = 0;
and then also
printf("%u, ", (unsigned)sizeo f ++x); /* x is not incremented */
printf("%d, ", x); /* x is not incremented */
printf("%d\n", ++x); /* x is incremented */
... then the output will be:
1, 0, 1
To whatever value (within SCHAR_MAX and MIN)'x' initialized to - the
first printf always prints *1*
- Ravi This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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