On a note related to my question about logical XOR, I'm trying to
think of a non-obfuscated way to condense the following code block
(which, as usual, I did not write):
switch( int_val_1 ) {
case 0:
switch( int_val_2 ) {
case enum_val_1: return( num1 == num2 );
case enum_val_2: return( num1 <= num2 );
case enum_val_3: return( num1 >= num2 );
default: return( true );
}
case 1:
switch( int_val_2 ) {
case enum_val_1: return( num1 != num2 );
case enum_val_2: return( num1 > num2 );
case enum_val_3: return( num1 < num2 );
default: return( true );
}
default:
return true;
}
Any suggestions?
--
Christopher Benson-Manica | I *should* know what I'm talking about - if I
ataru(at)cybers pace.org | don't, I need to know. Flames welcome.
19  15181 
Christopher Benson-Manica <at***@nospam.c yberspace.org> wrote: switch( int_val_1 ) {
case 0:
switch( int_val_2 ) {
case enum_val_1: return( num1 == num2 );
case enum_val_2: return( num1 <= num2 );
case enum_val_3: return( num1 >= num2 );
default: return( true );
}
case 1:
switch( int_val_2 ) {
case enum_val_1: return( num1 != num2 );
case enum_val_2: return( num1 > num2 );
case enum_val_3: return( num1 < num2 );
default: return( true );
}
default:
return true;
}
Any suggestions?
Yes: why? This code isn't really obfuscated. Ok, the _design_ probably
isn't all that hot, with the two different control variables, but
there's little you can do about that without changing the semantics.
Richard
Christopher Benson-Manica wrote: On a note related to my question about logical XOR, I'm trying to
think of a non-obfuscated way to condense the following code block
(which, as usual, I did not write):
switch( int_val_1 ) {
case 0:
switch( int_val_2 ) {
case enum_val_1: return( num1 == num2 );
case enum_val_2: return( num1 <= num2 );
case enum_val_3: return( num1 >= num2 );
default: return( true );
}
case 1:
switch( int_val_2 ) {
case enum_val_1: return( num1 != num2 );
case enum_val_2: return( num1 > num2 );
case enum_val_3: return( num1 < num2 );
default: return( true );
}
default:
return true;
}
Any suggestions?
You can condense it, but I don't consider the following to be an improvement
(hopefully, I haven't changed the semantics either):
int ret;
if ( int_val_1 != !!int_val_1 ) return true;
switch ( int_val_2 ) {
case enum_val_1: ret = (num1 == num2); break;
case enum_val_2: ret = (num1 <= num2); break;
case enum_val_3: ret = (num1 >= num2); break;
default: return true;
}
return ret ^ int_val_1;
Less readable, less flexible, more error-prone. Wow!! If job security was a
priority, I wouldn't hesitate to incorporate this "improvemen t" :-)
-nrk.
--
Remove devnull for email
Christopher Benson-Manica wrote:
On a note related to my question about logical XOR, I'm trying to
think of a non-obfuscated way to condense the following code block
(which, as usual, I did not write):
switch( int_val_1 ) {
case 0:
switch( int_val_2 ) {
case enum_val_1: return( num1 == num2 );
case enum_val_2: return( num1 <= num2 );
case enum_val_3: return( num1 >= num2 );
default: return( true );
}
case 1:
switch( int_val_2 ) {
case enum_val_1: return( num1 != num2 );
case enum_val_2: return( num1 > num2 );
case enum_val_3: return( num1 < num2 );
default: return( true );
}
default:
return true;
}
Any suggestions?
int result;
switch (int_val_2) {
case enum_val_1: result = num1 == num2;
case enum_val_2: result = num1 <= num2;
case enum_val_3: result = num1 >= num2;
default: return true; /* sounds ridiculous */
}
if (1 == int_val1) result = !result;
else if (0 != int_val1) result = true;
/* else use_result for 0 */
return result;
--
Chuck F (cb********@yah oo.com) (cb********@wor ldnet.att.net)
Available for consulting/temporary embedded and systems.
<http://cbfalconer.home .att.net> USE worldnet address!
Christopher Benson-Manica <at***@nospam.c yberspace.org> wrote in
news:bv******** **@chessie.cirr .com: On a note related to my question about logical XOR, I'm trying to
think of a non-obfuscated way to condense the following code block
(which, as usual, I did not write):
switch( int_val_1 ) {
case 0:
switch( int_val_2 ) {
case enum_val_1: return( num1 == num2 );
case enum_val_2: return( num1 <= num2 );
case enum_val_3: return( num1 >= num2 );
default: return( true );
}
case 1:
switch( int_val_2 ) {
case enum_val_1: return( num1 != num2 );
case enum_val_2: return( num1 > num2 );
case enum_val_3: return( num1 < num2 );
default: return( true );
}
default:
return true;
}
Any suggestions?
Get rid of the default cases?
switch (int_val_1)
{
case 0:
switch (int_val_2)
{
case enum_val_1: return num1 == num2;
case enum_val_2: return num1 <= num2;
case enum_val_3: return num1 >= num2;
}
break;
case 1:
switch (int_val_2)
{
case enum_val_1: return num1 != num2;
case enum_val_2: return num1 > num2;
case enum_val_3: return num1 < num2;
}
break;
}
return true; /* factor this out */
It's not much, admittedly.
--
- Mark ->
--
CBFalconer wrote: Christopher Benson-Manica wrote:
On a note related to my question about logical XOR, I'm trying to
think of a non-obfuscated way to condense the following code block
(which, as usual, I did not write):
switch( int_val_1 ) {
case 0:
switch( int_val_2 ) {
case enum_val_1: return( num1 == num2 );
case enum_val_2: return( num1 <= num2 );
case enum_val_3: return( num1 >= num2 );
default: return( true );
}
case 1:
switch( int_val_2 ) {
case enum_val_1: return( num1 != num2 );
case enum_val_2: return( num1 > num2 );
case enum_val_3: return( num1 < num2 );
default: return( true );
}
default:
return true;
}
Any suggestions?
int result;
switch (int_val_2) {
case enum_val_1: result = num1 == num2;
case enum_val_2: result = num1 <= num2;
case enum_val_3: result = num1 >= num2;
default: return true; /* sounds ridiculous */
}
if (1 == int_val1) result = !result;
else if (0 != int_val1) result = true;
/* else use_result for 0 */
return result;
Your incantations have invoked the demons that reside in fall-thru hell :-)
I believe this is also known as the devil's device.
-nrk.
--
Remove devnull for email
On Tue, 3 Feb 2004 15:42:07 +0000 (UTC), Christopher Benson-Manica
<at***@nospam.c yberspace.org> wrote: On a note related to my question about logical XOR, I'm trying to
think of a non-obfuscated way to condense the following code block
(which, as usual, I did not write):
switch( int_val_1 ) {
case 0:
switch( int_val_2 ) {
case enum_val_1: return( num1 == num2 );
case enum_val_2: return( num1 <= num2 );
case enum_val_3: return( num1 >= num2 );
default: return( true );
}
case 1:
switch( int_val_2 ) {
case enum_val_1: return( num1 != num2 );
case enum_val_2: return( num1 > num2 );
case enum_val_3: return( num1 < num2 );
default: return( true );
}
default:
return true;
}
Any suggestions?
Not counting the default cases you have 6 = 2*3 distinct results. So
you will definitely need 6 distinct cases. What's wrong with the code?
--
Horst
CBFalconer wrote:
Christopher Benson-Manica wrote:
On a note related to my question about logical XOR, I'm trying to
think of a non-obfuscated way to condense the following code block
(which, as usual, I did not write):
switch( int_val_1 ) {
case 0:
switch( int_val_2 ) {
case enum_val_1: return( num1 == num2 );
case enum_val_2: return( num1 <= num2 );
case enum_val_3: return( num1 >= num2 );
default: return( true );
}
case 1:
switch( int_val_2 ) {
case enum_val_1: return( num1 != num2 );
case enum_val_2: return( num1 > num2 );
case enum_val_3: return( num1 < num2 );
default: return( true );
}
default:
return true;
}
Any suggestions?
int result;
switch (int_val_2) {
case enum_val_1: result = num1 == num2;
case enum_val_2: result = num1 <= num2;
case enum_val_3: result = num1 >= num2;
default: return true; /* sounds ridiculous */
}
if (1 == int_val1) result = !result;
else if (0 != int_val1) result = true;
/* else use_result for 0 */
return result;
Woops! - Each case is missing a "break;" statement.
--
Chuck F (cb********@yah oo.com) (cb********@wor ldnet.att.net)
Available for consulting/temporary embedded and systems.
<http://cbfalconer.home .att.net> USE worldnet address!
begin followup to Christopher Benson-Manica: switch( int_val_1 ) {
case 0:
switch( int_val_2 ) {
case enum_val_1: return( num1 == num2 );
case enum_val_2: return( num1 <= num2 );
case enum_val_3: return( num1 >= num2 );
default: return( true );
}
case 1:
switch( int_val_2 ) {
case enum_val_1: return( num1 != num2 );
case enum_val_2: return( num1 > num2 );
case enum_val_3: return( num1 < num2 );
default: return( true );
}
default:
return true;
}
Well, if the values of int_val_2 are contiguous then there is one
obvious solution. Replace "- 0" with the actual minimum value.
switch(int_val_ 1 * 3 + int_val_2 - 0)
{
case 0: return( num1 == num2 );
case 1: return( num1 <= num2 );
case 2: return( num1 >= num2 );
case 3: return( num1 != num2 );
case 4: return( num1 > num2 );
case 5: return( num1 < num2 );
default: return true;
}
--
Für Google, Tux und GPL!
Horst Kraemer <ho***********@ epost.de> spoke thus: switch( int_val_1 ) {
case 0:
switch( int_val_2 ) {
case enum_val_1: return( num1 == num2 );
case enum_val_2: return( num1 <= num2 );
case enum_val_3: return( num1 >= num2 );
default: return( true );
}
case 1:
switch( int_val_2 ) {
case enum_val_1: return( num1 != num2 );
case enum_val_2: return( num1 > num2 );
case enum_val_3: return( num1 < num2 );
default: return( true );
}
default:
return true;
}
Not counting the default cases you have 6 = 2*3 distinct results. So
you will definitely need 6 distinct cases. What's wrong with the code?
6 distinct results, yes, but notice that they are related. After
reading replies to my other question, I gather that something like
switch( int_val_1 ) {
case 0:
case 1:
switch( int_val_2 ) {
case enum_val_1: return( (num1 == num2) ^ int_val_1 );
case enum_val_2: return( (num1 <= num2) ^ int_val_1 );
case enum_val_3: return( (num1 >= num2) ^ int_val_1 );
}
}
return 1;
would work, at the cost of some clarity.
(Sorry for the true's - I forgot to un-C++ my code...)
--
Christopher Benson-Manica | I *should* know what I'm talking about - if I
ataru(at)cybers pace.org | don't, I need to know. Flames welcome. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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