I am trying to write a recursive version of Power(x,n) that works by
breaking n down into halves(where half of n=n/2), squaring
Power(x,n/2), and multiplying by x again if n was odd, and to find a
suitable base case to stop the recursion. Can someone give me an
example of this?
Thanks!
Nov 13 '05
64 7332
On Mon, 27 Oct 2003, Eric Sosman wrote: "E. Robert Tisdale" wrote: dmattis wrote: I am trying to write a recursive version of Power(x,n) that works by breaking n down into halves(where half of n=n/2), squaring Power(x,n/2), and multiplying by x again if n was odd, and to find a suitable base case to stop the recursion. Can someone give me an example of this?
double Power(double x, unsigned int n) { return (0 < n)? Power(x, n/2)*Power(x, n - n/2): 1.0; }
I confess that I considered suggesting this method, but then decided that wanton cruelty was not (yet) justified.
Well, either that or the interpretation of "suitable base case to
stop the recursion" might need some clarification.
On Tue, 28 Oct 2003, Jarno A Wuolijoki wrote: On Mon, 27 Oct 2003, Eric Sosman wrote: "E. Robert Tisdale" wrote: double Power(double x, unsigned int n) { return (0 < n)? Power(x, n/2)*Power(x, n - n/2): 1.0; }
I confess that I considered suggesting this method, but then decided that wanton cruelty was not (yet) justified.
Well, either that or the interpretation of "suitable base case to stop the recursion" might need some clarification.
In particular, where is it guaranteed that the base case (n <= 0)
is ever reached? I admit I'm not conversant in the details of
C floating point, but it seems like an unwarrantedly dubious
assumption to be making. What's to say that 1e-100/2 != 1e-100 ?
-Arthur
"Arthur J. O'Dwyer" <aj*@nospam.and rew.cmu.edu> wrote: On Tue, 28 Oct 2003, Jarno A Wuolijoki wrote: On Mon, 27 Oct 2003, Eric Sosman wrote: > "E. Robert Tisdale" wrote: > > > > double Power(double x, unsigned int n) { > > return (0 < n)? Power(x, n/2)*Power(x, n - n/2): 1.0; > > } > > I confess that I considered suggesting this method, but > then decided that wanton cruelty was not (yet) justified.
Well, either that or the interpretation of "suitable base case to stop the recursion" might need some clarification.
In particular, where is it guaranteed that the base case (n <= 0) is ever reached? I admit I'm not conversant in the details of C floating point, but it seems like an unwarrantedly dubious assumption to be making. What's to say that 1e-100/2 != 1e-100 ?
Err, n is of type unsigned int, thus all divisions are integer
divisions...
Regards
--
Irrwahn
(ir*******@free net.de)
On Tue, 28 Oct 2003, Irrwahn Grausewitz wrote: "Arthur J. O'Dwyer" <aj*@nospam.and rew.cmu.edu> wrote:> > "E. Robert Tisdale" wrote: > > > > double Power(double x, unsigned int n) { > > return (0 < n)? Power(x, n/2)*Power(x, n - n/2): 1.0; > > }
In particular, where is it guaranteed that the base case (n <= 0) is ever reached? I admit I'm not conversant in the details of C floating point, but it seems like an unwarrantedly dubious assumption to be making. What's to say that 1e-100/2 != 1e-100 ?
Err, n is of type unsigned int, thus all divisions are integer divisions...
Oops. I was thrown by the use of 'double' everywhere else.
Seems silly to use 'double' for the first operand if you're only
going to allow positive integers for the second operand...
plus, in this case Tisdale's solution does exponentially more
work than it really has to. There should be only one call
to Power() within the function itself.
(Proper solution left as an exercise for the OP.)
-Arthur
In article
<Pi************ *************** ********@unix47 .andrew.cmu.edu >,
"Arthur J. O'Dwyer" <aj*@nospam.and rew.cmu.edu> wrote: On Tue, 28 Oct 2003, Irrwahn Grausewitz wrote: "Arthur J. O'Dwyer" <aj*@nospam.and rew.cmu.edu> wrote: >> > "E. Robert Tisdale" wrote: > > > > > > double Power(double x, unsigned int n) { > > > return (0 < n)? Power(x, n/2)*Power(x, n - n/2): 1.0; > > > }
In particular, where is it guaranteed that the base case (n <= 0) is ever reached? I admit I'm not conversant in the details of C floating point, but it seems like an unwarrantedly dubious assumption to be making. What's to say that 1e-100/2 != 1e-100 ?
Err, n is of type unsigned int, thus all divisions are integer divisions...
Oops. I was thrown by the use of 'double' everywhere else. Seems silly to use 'double' for the first operand if you're only going to allow positive integers for the second operand... plus, in this case Tisdale's solution does exponentially more work than it really has to. There should be only one call to Power() within the function itself.
I think it does more than exponentially more work than needed...
What is n - n/2 if n is equal to 1?
Irrwahn Grausewitz <ir*******@free net.de> wrote in message news:<p8******* *************** **********@4ax. com>... "Arthur J. O'Dwyer" <aj*@nospam.and rew.cmu.edu> wrote:On Tue, 28 Oct 2003, Jarno A Wuolijoki wrote: On Mon, 27 Oct 2003, Eric Sosman wrote: > "E. Robert Tisdale" wrote: > > > > double Power(double x, unsigned int n) { > > return (0 < n)? Power(x, n/2)*Power(x, n - n/2): 1.0; > > } > > I confess that I considered suggesting this method, but > then decided that wanton cruelty was not (yet) justified.
Well, either that or the interpretation of "suitable base case to stop the recursion" might need some clarification.
In particular, where is it guaranteed that the base case (n <= 0) is ever reached? I admit I'm not conversant in the details of C floating point, but it seems like an unwarrantedly dubious assumption to be making. What's to say that 1e-100/2 != 1e-100 ?
Err, n is of type unsigned int, thus all divisions are integer divisions...
The floating point reference is a red herring. Think about what the
function will do when n is 1.
--
Peter
"James Hu" <jx*@despammed. com> wrote in message
news:x9******** ************@co mcast.com... On 2003-10-27, dmattis <dm*****@yahoo. com> wrote: I am trying to write a recursive version of Power(x,n) that works by breaking n down into halves(where half of n=n/2), squaring Power(x,n/2), and multiplying by x again if n was odd, and to find a suitable base case to stop the recursion. Can someone give me an example of this? This is not a C question... but the C answer is use pow() (unless you are purposefully avoiding floating point, in which case a table lookup is in order).
The algorithm described, in non-recursive form, is commonly used in
languages that supply an integer exponentiation operator. A table
dimensioned INT_MAX-INT_MIN+1 will take up a lot of memory.
<DYOHW> Rewrite your word problem into a recurrence relationship. Use induction to prove this recurrence correctly calculates x to the nth power. It should be obvious at that point what your function should look like and what your base case is. </DYOHW>
Yes, he should do that.
-- glen
On 2003-10-28, Glen Herrmannsfeldt <ga*@ugcs.calte ch.edu> wrote: "James Hu" <jx*@despammed. com> wrote in message news:x9******** ************@co mcast.com... On 2003-10-27, dmattis <dm*****@yahoo. com> wrote: > I am trying to write a recursive version of Power(x,n) that works by > breaking n down into halves(where half of n=n/2), squaring > Power(x,n/2), and multiplying by x again if n was odd, and to find a > suitable base case to stop the recursion. Can someone give me an > example of this? This is not a C question... but the C answer is use pow() (unless you are purposefully avoiding floating point, in which case a table lookup is in order).
The algorithm described, in non-recursive form, is commonly used in languages that supply an integer exponentiation operator.
Yes, but those typically take a floating point type for the x argument,
and an int type for the n argument.
A table dimensioned INT_MAX-INT_MIN+1 will take up a lot of memory.
That is an imaginative approach, but not what I had in mind.
#include <stdint.h>
static int8_t hbit[256] =
{-1
,0
,1,1
,2,2,2,2
,3,3,3,3,3,3,3, 3
,4,4,4,4,4,4,4, 4,4,4,4,4,4,4,4 ,4
,5,5,5,5,5,5,5, 5,5,5,5,5,5,5,5 ,5,5,5,5,5,5,5, 5,5,5,5,5,5,5,5 ,5,5
,6,6,6,6,6,6,6, 6,6,6,6,6,6,6,6 ,6,6,6,6,6,6,6, 6,6,6,6,6,6,6,6 ,6,6
,6,6,6,6,6,6,6, 6,6,6,6,6,6,6,6 ,6,6,6,6,6,6,6, 6,6,6,6,6,6,6,6 ,6,6
,7,7,7,7,7,7,7, 7,7,7,7,7,7,7,7 ,7,7,7,7,7,7,7, 7,7,7,7,7,7,7,7 ,7,7
,7,7,7,7,7,7,7, 7,7,7,7,7,7,7,7 ,7,7,7,7,7,7,7, 7,7,7,7,7,7,7,7 ,7,7
,7,7,7,7,7,7,7, 7,7,7,7,7,7,7,7 ,7,7,7,7,7,7,7, 7,7,7,7,7,7,7,7 ,7,7
,7,7,7,7,7,7,7, 7,7,7,7,7,7,7,7 ,7,7,7,7,7,7,7, 7,7,7,7,7,7,7,7 ,7,7
};
int int_pow(int x, uint8_t n)
{
int t = 1;
if (n == 0) return 1;
if (x == 0) return 0;
switch (hbit[n]) {
case 7: if (n & 1) t *= x; n >>= 1; x *= x;
case 6: if (n & 1) t *= x; n >>= 1; x *= x;
case 5: if (n & 1) t *= x; n >>= 1; x *= x;
case 4: if (n & 1) t *= x; n >>= 1; x *= x;
case 3: if (n & 1) t *= x; n >>= 1; x *= x;
case 2: if (n & 1) t *= x; n >>= 1; x *= x;
case 1: if (n & 1) t *= x; n >>= 1; x *= x;
default: if (n & 1) t *= x;
}
return t;
}
-- James
Christian Bau <ch***********@ cbau.freeserve. co.uk> wrote: "Arthur J. O'Dwyer" <aj*@nospam.and rew.cmu.edu> wrote:
> >> > "E. Robert Tisdale" wrote: > >> > > > >> > > double Power(double x, unsigned int n) { > >> > > return (0 < n)? Power(x, n/2)*Power(x, n - n/2): 1.0; > >> > > }
<snip> plus, in this case Tisdale's solution does exponentially more work than it really has to. There should be only one call to Power() within the function itself.
I think it does more than exponentially more work than needed...
What is n - n/2 if n is equal to 1?
Arrgh, Trollsdale did it again!
And on first glance I thought he actually posted valid code; stupid me.
--
Irrwahn
(ir*******@free net.de)
Maybe it's just me but doesn't the contrived nature of the function scream
out "Homework Assignment?" Maybe I'm missing something but I just can't see
why you'd ever want to compute this value..
Alea iacta
"Julian V. Noble" Here is tested C code for raising an integer to an integer power, recursively. (I hope this isn't a HW assignment but a legitimate query.) This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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