Hi, Everyone!
Does anyone know how to initialize an int array with a non-zero number?
Thank You Very Much.
Truly Yours, Simon Dexter
Jul 23 '05
13 27172
"Rick N. Backer" <ke********@NsO hSaPw.cAaM> wrote in message
news:72******** *************** *********@4ax.c om On Wed, 13 Jul 2005 15:46:54 +1000, "John Carson" <jc************ ****@netspace.n et.au> did courageously avow:
"Rick N. Backer" <ke********@NsO hSaPw.cAaM> wrote in message news:if******** *************** *********@4ax.c om On 12 Jul 2005 21:46:19 -0700, si******@yahoo. com did courageously avow:
Hi, Everyone!
Does anyone know how to initialize an int array with a non-zero number?
int intArr[n1] = {x1}; // declaration and initialization
n1 can be any positive integer value and x1 can be any legitimate value; number, char, pointer to another array, etc.. I believe you don't need to specify all the elements in the list. That said, I trust I will be corrected if I'm wrong Your code has the effect of initializing the first element of the array to x1 and the rest to zero. You also can't use pointer values without a cast.
Where is this pointer you speak of?
You say: "x1 can be any legitimate value; number, char, pointer to another
array, etc". Thus the "pointer to another array" is the pointer that I speak
of. x1 cannot be a pointer without using a cast.
I see an int array being initialized to hold n1 elements of which the first will be x1 and the rest zero as you say. If you had all my post here, you would see I also explained how to declare all the members at once if the OP so wished, how to declare an array without initialization and then initialize a single element later, and also suggest how it could be done in a for loop. Why are you centering on one item and not the whole post?
The OP asked how to initialize an array with a non-zero number. I took this
to mean initialize the *whole* array with a non-zero number and so I took
your answer to be a claim that
int intArr[n1] = {x1};
initialized each element in the array to x1. The fact that you also gave
alternative methods of initialization was not inconsistent with this
interpretation.
If my interpretation was incorrect, I apologize.
--
John Carson
upashu2 wrote: how to initialize an int array with a non-zero number? John Carson ..... first element of the array to x1 and the rest to zero
if we write, int a[20]; it leaves the whole array uninintialized. It doesn't initalize array with 0's at all. after all it is c++, not java or vb.
That's true, but not what John presented. He initialized the first
value. The rest of the array will be default initialized.
if we write int a[20]={ 1,2}; then it will initialize only first two elements, and leave all others uninitialized.
You are incorrect. The rest of the array will be filled with 0.
Still if you want to initialize an array with 0's, you have to write it expilicitly.
Wrong.
Brian
[some further thoughts]
"Rick N. Backer" <ke********@NsO hSaPw.cAaM> wrote in message
news:72******** *************** *********@4ax.c om On Wed, 13 Jul 2005 15:46:54 +1000, "John Carson" <jc************ ****@netspace.n et.au> did courageously avow:
"Rick N. Backer" <ke********@NsO hSaPw.cAaM> wrote in message news:if******** *************** *********@4ax.c om On 12 Jul 2005 21:46:19 -0700, si******@yahoo. com did courageously avow:
Hi, Everyone!
Does anyone know how to initialize an int array with a non-zero number?
int intArr[n1] = {x1}; // declaration and initialization
n1 can be any positive integer value and x1 can be any legitimate value; number, char, pointer to another array, etc.. I believe you don't need to specify all the elements in the list. That said, I trust I will be corrected if I'm wrong Your code has the effect of initializing the first element of the array to x1 and the rest to zero. You also can't use pointer values without a cast.
Where is this pointer you speak of? I see an int array being initialized to hold n1 elements of which the first will be x1 and the rest zero as you say. If you had all my post here, you would see I also explained how to declare all the members at once if the OP so wished, how to declare an array without initialization and then initialize a single element later, and also suggest how it could be done in a for loop.
You didn't say at *any* point in your post that
int intArr[n1] = {x1};
would set all elements after the first to zero, so it was surely worth
pointing it out so the OP would know what to expect.
Why are you centering on one item and not the whole post?
I was not writing a review. It is perfectly legitimate to focus on the one
part of a post that is in need of clarification.
--
John Carson
On Thu, 14 Jul 2005 03:25:54 +1000, "John Carson"
<jc************ ****@netspace.n et.au> did courageously avow: [some further thoughts]
"Rick N. Backer" <ke********@NsO hSaPw.cAaM> wrote in message news:72******* *************** **********@4ax. com On Wed, 13 Jul 2005 15:46:54 +1000, "John Carson" <jc************ ****@netspace.n et.au> did courageously avow:
"Rick N. Backer" <ke********@NsO hSaPw.cAaM> wrote in message news:if******** *************** *********@4ax.c om On 12 Jul 2005 21:46:19 -0700, si******@yahoo. com did courageously avow:
> Hi, Everyone! > > Does anyone know how to initialize an int array with a non-zero > number?
int intArr[n1] = {x1}; // declaration and initialization
n1 can be any positive integer value and x1 can be any legitimate value; number, char, pointer to another array, etc.. I believe you don't need to specify all the elements in the list. That said, I trust I will be corrected if I'm wrong
Your code has the effect of initializing the first element of the array to x1 and the rest to zero. You also can't use pointer values without a cast. Where is this pointer you speak of? I see an int array being initialized to hold n1 elements of which the first will be x1 and the rest zero as you say. If you had all my post here, you would see I also explained how to declare all the members at once if the OP so wished, how to declare an array without initialization and then initialize a single element later, and also suggest how it could be done in a for loop.
You didn't say at *any* point in your post that
int intArr[n1] = {x1};
would set all elements after the first to zero, so it was surely worth pointing it out so the OP would know what to expect.
I have no problem and readily concede that point and, truthfully,
hadn't considered that aspect. I may have boiled the question down to
much in trying to simplify it and my response. Why are you centering on one item and not the whole post?
I was not writing a review. It is perfectly legitimate to focus on the one part of a post that is in need of clarification.
Oh how I hate first encounters :-). I am used to people only
applying to one point and will concede this also and stand now
unoffended. I am just used to people interjecting in line and
returning the original document intact so context of the discussion
can be maintained. In this instance I ass-u-me'd, incorrectly, that
you hadn't paid attention to the rest of the post. My apologies.
Ken Wilson
Amer. Dlx. Tele, Gary Moore LP, LP DC Classic w/P90s,
Jeff Beck Strat, Morgan OM Acoustic,
Rick 360/12, Std. Strat (MIM), Mesa 100 Nomad,
Mesa F-30
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