Hi, Everyone!
Does anyone know how to initialize an int array with a non-zero number?
Thank You Very Much.
Truly Yours, Simon Dexter
13  27163 
<si******@yahoo .com> wrote in message
news:11******** **************@ g47g2000cwa.goo glegroups.com Hi, Everyone!
Does anyone know how to initialize an int array with a non-zero
number?
Thank You Very Much.
Truly Yours, Simon Dexter
Int is not int. C++ is case sensitive.
The only way to do this at the point of declaration is to repeat the number
as many times as you need it, e.g.,
int array[5] = {9,9,9,9,9};
Alternatively, you can do it in a loop after the declaration.
Vectors allow you to avoid repeating the number:
std::vector<int > array(5, 9);
--
John Carson
On 12 Jul 2005 21:46:19 -0700, si******@yahoo. com did courageously
avow: Hi, Everyone!
Does anyone know how to initialize an int array with a non-zero number?
int intArr[n1] = {x1}; // declaration and initialization
n1 can be any positive integer value and x1 can be any legitimate
value; number, char, pointer to another array, etc.. I believe you
don't need to specify all the elements in the list. That said, I
trust I will be corrected if I'm wrong
-- OR --
int intArr[n1]; // declaration
intArr[0] = x1; // initialization
It all depends on how far you want to go. You can give it a completer
list in the first example if you want. Or, you can use a for loop
that runs through the array index until it has filled the last
element, using the second statement inside the loop, substituting your
index variable for the zero and applying whatever number you
application feels is appropriate for the array.
Thank You Very Much.
You're welcome.
Ken Wilson
Amer. Dlx. Tele, Gary Moore LP, LP DC Classic w/P90s,
Jeff Beck Strat, Morgan OM Acoustic,
Rick 360/12, Std. Strat (MIM), Mesa 100 Nomad,
Mesa F-30
"Goodnight Austin, Texas, wherever you are."
"Rick N. Backer" <ke********@NsO hSaPw.cAaM> wrote in message
news:if******** *************** *********@4ax.c om On 12 Jul 2005 21:46:19 -0700, si******@yahoo. com did courageously
avow:
Hi, Everyone!
Does anyone know how to initialize an int array with a non-zero
number?
int intArr[n1] = {x1}; // declaration and initialization
n1 can be any positive integer value and x1 can be any legitimate
value; number, char, pointer to another array, etc.. I believe you
don't need to specify all the elements in the list. That said, I
trust I will be corrected if I'm wrong
Your code has the effect of initializing the first element of the array to
x1 and the rest to zero. You also can't use pointer values without a cast.
--
John Carson
>> how to initialize an int array with a non-zero number? John Carson .....
first element of the array to x1 and the rest to zero
if we write, int a[20]; it leaves the whole array uninintialized. It
doesn't initalize array with 0's at all. after all it is c++, not java
or vb.
if we write int a[20]={ 1,2};
then it will initialize only first two elements, and leave all others
uninitialized.
Still if you want to initialize an array with 0's, you have to write it
expilicitly.
int a[3]={0,0,0}; or use std::vector, std::vector<int > a(size,0);
The answer is whether u want to initialize array with zero or non-zero
value , you have to explicitly initialize them.
> Does anyone know how to initialize an int array with a non-zero number?
did anyone mention memset?
like, int * pi = new int (123);
memset(pi, <some byte here>, 123*sizeof(int) );
pity you'd have pretty limited initial values set to choose from.
On Wed, 13 Jul 2005 11:44:15 +0400, upashu2 <up*****@rediff mail.com> wrote: how to initialize an int array with a non-zero number?
John Carson .....
first element of the array to x1 and the rest to zero
if we write, int a[20]; it leaves the whole array uninintialized. It
doesn't initalize array with 0's at all. after all it is c++, not java
or vb.
if we write int a[20]={ 1,2};
then it will initialize only first two elements, and leave all others
uninitialized.
This is wrong.
[dcl.init.aggr] 8.5.1 Aggregates
....
7 If there are fewer initializers in the list than there are members in
the aggregate, then each member not explicitly initialized shall be
value-initialized (8.5).
[Example:
struct S { int a; char* b; int c; };
S ss = { 1, "asdf" };
initializes ss.a with 1, ss.b with "asdf", and ss.c with the value of an
expression of the form int(), that is, 0. ]
--
Maxim Yegorushkin
<fi************ ****@gmail.com>
On Wed, 13 Jul 2005 08:46:19 +0400, <si******@yahoo .com> wrote: Does anyone know how to initialize an int array with a non-zero number?
Just iterate over the array and initialize its members with any values you
like.
The standard library provides some basic function templates for filling
arrays as well as ranges:
fill/fill_n
generate
Example:
int a[10];
fill_n(a, sizeof(a) / sizeof(*a), 1); // fill with ones
--
Maxim Yegorushkin
<fi************ ****@gmail.com>
<ma************ @gmail.com> wrote in message
news:11******** **************@ g44g2000cwa.goo glegroups.com Does anyone know how to initialize an int array with a non-zero
number?
did anyone mention memset?
like, int * pi = new int (123);
That should be
int *pi = new int[123];
memset(pi, <some byte here>, 123*sizeof(int) );
This does byte by byte initialisation, which is viable for the very small
fraction of integers which have the same number in each byte.
pity you'd have pretty limited initial values set to choose from.
Small and obsure. You cannot do this:
memset(pi, 5, 123*sizeof(int) );
and initialise all integers to 5. You initialise all integers to whatever
number consists of a 5 in each byte.
--
John Carson
On Wed, 13 Jul 2005 15:46:54 +1000, "John Carson"
<jc************ ****@netspace.n et.au> did courageously avow: "Rick N. Backer" <ke********@NsO hSaPw.cAaM> wrote in message
news:if******* *************** **********@4ax. com On 12 Jul 2005 21:46:19 -0700, si******@yahoo. com did courageously
avow:
Hi, Everyone!
Does anyone know how to initialize an int array with a non-zero
number?
int intArr[n1] = {x1}; // declaration and initialization
n1 can be any positive integer value and x1 can be any legitimate
value; number, char, pointer to another array, etc.. I believe you
don't need to specify all the elements in the list. That said, I
trust I will be corrected if I'm wrong
Your code has the effect of initializing the first element of the array to
x1 and the rest to zero. You also can't use pointer values without a cast.
Where is this pointer you speak of?
I see an int array being initialized to hold n1 elements of which the
first will be x1 and the rest zero as you say. If you had all my post
here, you would see I also explained how to declare all the members at
once if the OP so wished, how to declare an array without
initialization and then initialize a single element later, and also
suggest how it could be done in a for loop. Why are you centering on
one item and not the whole post?
Ken Wilson
Amer. Dlx. Tele, Gary Moore LP, LP DC Classic w/P90s,
Jeff Beck Strat, Morgan OM Acoustic,
Rick 360/12, Std. Strat (MIM), Mesa 100 Nomad,
Mesa F-30
"Goodnight Austin, Texas, wherever you are." This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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