How to code a sin curve???? HELP!

[reagan]

I am trying to get a program(in visual C++) to draw a sine curve (from
0 to 2pi). It takes 8 lines to draw the complete curve. However, the
user can choose to use up to 100 lines to make the curve smoother. How
do I get the program to calculate that? I thought of using a counter
to count through until it gets to the number of user chosen lines
(m_iSample), but then I don't know how to calculate it. I just
finished trig too, darn it.

for (count = 0; count<=m_iSampl e; ++count) {
double iSinValue=sin(c ount * PI);//do the sin calculation
int iFinalSinValue= iSinValue * 200;//convert result so that it will
display correctly
pDC->LineTo( ??? , iFinalSinValue) ;//draw the line
}

[adbarnet]

Forgive me if my maths is not up to scratch - but isn't the value of the y
axis a function of the x axis, where x is the angle being 'sin'ed?
If so - your x-axis should be divided by the number of lines you want to
draw:

Point point(0,0);
Point newPoint(0,0);
for (int iPointIndex = 0; iPointIndex < m_iSample; ++iPointIndex)
{
x = 360/m_iSample; // You can do this relative to PI yourself...;-)

y = sin(x);

newPoint = (x,y)
drawLine (point, newPoint);
point = newPoint;
}
"reagan" <ma************ *****@hotmail.c om> wrote in message
news:d3******** *************** ***@posting.goo gle.com...

I am trying to get a program(in visual C++) to draw a sine curve (from
0 to 2pi). It takes 8 lines to draw the complete curve. However, the
user can choose to use up to 100 lines to make the curve smoother. How
do I get the program to calculate that? I thought of using a counter
to count through until it gets to the number of user chosen lines
(m_iSample), but then I don't know how to calculate it. I just
finished trig too, darn it.

for (count = 0; count<=m_iSampl e; ++count) {
double iSinValue=sin(c ount * PI);//do the sin calculation
int iFinalSinValue= iSinValue * 200;//convert result so that it will
display correctly
pDC->LineTo( ??? , iFinalSinValue) ;//draw the line
}

Posted Via Usenet.com Premium Usenet Newsgroup Services
----------------------------------------------------------
** SPEED ** RETENTION ** COMPLETION ** ANONYMITY **
----------------------------------------------------------
http://www.usenet.com

[Jeremy A. Smith]

your math is right, Y is a function of X
"adbarnet" <ad@dontmailmet hx> wrote in message
news:41******** **@127.0.0.1...

Forgive me if my maths is not up to scratch - but isn't the value of the y
axis a function of the x axis, where x is the angle being 'sin'ed?
If so - your x-axis should be divided by the number of lines you want to
draw:

Point point(0,0);
Point newPoint(0,0);
for (int iPointIndex = 0; iPointIndex < m_iSample; ++iPointIndex)
{
x = 360/m_iSample; // You can do this relative to PI yourself...;-)

y = sin(x);

newPoint = (x,y)
drawLine (point, newPoint);
point = newPoint;
}
"reagan" <ma************ *****@hotmail.c om> wrote in message
news:d3******** *************** ***@posting.goo gle.com...

I am trying to get a program(in visual C++) to draw a sine curve (from
0 to 2pi). It takes 8 lines to draw the complete curve. However, the
user can choose to use up to 100 lines to make the curve smoother. How
do I get the program to calculate that? I thought of using a counter
to count through until it gets to the number of user chosen lines
(m_iSample), but then I don't know how to calculate it. I just
finished trig too, darn it.

for (count = 0; count<=m_iSampl e; ++count) {
double iSinValue=sin(c ount * PI);//do the sin calculation
int iFinalSinValue= iSinValue * 200;//convert result so that it will
display correctly
pDC->LineTo( ??? , iFinalSinValue) ;//draw the line
}

Posted Via Usenet.com Premium Usenet Newsgroup Services
----------------------------------------------------------
** SPEED ** RETENTION ** COMPLETION ** ANONYMITY **
----------------------------------------------------------
http://www.usenet.com

[reagan]

Not exactly sure what you mean by Point. Are point and newPoint
objects? Sorry, dumb newbie questions, I know.

adbarnet wrote:

Forgive me if my maths is not up to scratch - but isn't the value of the y axis a function of the x axis, where x is the angle being 'sin'ed?
If so - your x-axis should be divided by the number of lines you want to draw:

Point point(0,0);
Point newPoint(0,0);
for (int iPointIndex = 0; iPointIndex < m_iSample; ++iPointIndex)
{
x = 360/m_iSample; // You can do this relative to PI yourself...;-)
y = sin(x);

newPoint = (x,y)
drawLine (point, newPoint);
point = newPoint;
}
"reagan" <ma************ *****@hotmail.c om> wrote in message
news:d3******** *************** ***@posting.goo gle.com...

I am trying to get a program(in visual C++) to draw a sine curve (from 0 to 2pi). It takes 8 lines to draw the complete curve. However, the user can choose to use up to 100 lines to make the curve smoother. How do I get the program to calculate that? I thought of using a counter to count through until it gets to the number of user chosen lines
(m_iSample), but then I don't know how to calculate it. I just
finished trig too, darn it.

for (count = 0; count<=m_iSampl e; ++count) {
double iSinValue=sin(c ount * PI);//do the sin calculation
int iFinalSinValue= iSinValue * 200;//convert result so that it will
display correctly
pDC->LineTo( ??? , iFinalSinValue) ;//draw the line
}

Posted Via Usenet.com Premium Usenet Newsgroup Services
----------------------------------------------------------
** SPEED ** RETENTION ** COMPLETION ** ANONYMITY **
----------------------------------------------------------
http://www.usenet.com

[reagan]

Not exactly sure what you mean by Point. Are point and newPoint
objects? Sorry, dumb newbie questions, I know.

adbarnet wrote:

Forgive me if my maths is not up to scratch - but isn't the value of the y axis a function of the x axis, where x is the angle being 'sin'ed?
If so - your x-axis should be divided by the number of lines you want to draw:

Point point(0,0);
Point newPoint(0,0);
for (int iPointIndex = 0; iPointIndex < m_iSample; ++iPointIndex)
{
x = 360/m_iSample; // You can do this relative to PI yourself...;-)
y = sin(x);

newPoint = (x,y)
drawLine (point, newPoint);
point = newPoint;
}
"reagan" <ma************ *****@hotmail.c om> wrote in message
news:d3******** *************** ***@posting.goo gle.com...

I am trying to get a program(in visual C++) to draw a sine curve (from 0 to 2pi). It takes 8 lines to draw the complete curve. However, the user can choose to use up to 100 lines to make the curve smoother. How do I get the program to calculate that? I thought of using a counter to count through until it gets to the number of user chosen lines
(m_iSample), but then I don't know how to calculate it. I just
finished trig too, darn it.

for (count = 0; count<=m_iSampl e; ++count) {
double iSinValue=sin(c ount * PI);//do the sin calculation
int iFinalSinValue= iSinValue * 200;//convert result so that it will
display correctly
pDC->LineTo( ??? , iFinalSinValue) ;//draw the line
}

Posted Via Usenet.com Premium Usenet Newsgroup Services
----------------------------------------------------------
** SPEED ** RETENTION ** COMPLETION ** ANONYMITY **
----------------------------------------------------------
http://www.usenet.com

[reagan]

Not exactly sure what you mean by Point. Are point and newPoint
objects? Sorry, dumb newbie questions, I know.

adbarnet wrote:

Forgive me if my maths is not up to scratch - but isn't the value of the y axis a function of the x axis, where x is the angle being 'sin'ed?
If so - your x-axis should be divided by the number of lines you want to draw:

Point point(0,0);
Point newPoint(0,0);
for (int iPointIndex = 0; iPointIndex < m_iSample; ++iPointIndex)
{
x = 360/m_iSample; // You can do this relative to PI yourself...;-)
y = sin(x);

newPoint = (x,y)
drawLine (point, newPoint);
point = newPoint;
}
"reagan" <ma************ *****@hotmail.c om> wrote in message
news:d3******** *************** ***@posting.goo gle.com...

I am trying to get a program(in visual C++) to draw a sine curve (from 0 to 2pi). It takes 8 lines to draw the complete curve. However, the user can choose to use up to 100 lines to make the curve smoother. How do I get the program to calculate that? I thought of using a counter to count through until it gets to the number of user chosen lines
(m_iSample), but then I don't know how to calculate it. I just
finished trig too, darn it.

for (count = 0; count<=m_iSampl e; ++count) {
double iSinValue=sin(c ount * PI);//do the sin calculation
int iFinalSinValue= iSinValue * 200;//convert result so that it will
display correctly
pDC->LineTo( ??? , iFinalSinValue) ;//draw the line
}

Posted Via Usenet.com Premium Usenet Newsgroup Services
----------------------------------------------------------
** SPEED ** RETENTION ** COMPLETION ** ANONYMITY **
----------------------------------------------------------
http://www.usenet.com