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vector: erase() and rbegin()

vector<int> v;

erase() requires (as input parameter) and returns vector<int>::it erator,
rbegin() returns vector<int>::re verse_iterator.

So, a compiler doesn't accept v.erase(v.rbegi n()).
Do we have to write v.erase(v.end() - 1)? Or there exists something else?

--
Alex Vinokur
email: alex DOT vinokur AT gmail DOT com
http://mathforum.org/library/view/10978.html
http://sourceforge.net/users/alexvn

Jul 22 '05
10 4587
"Alex Vinokur" <al****@big-foot.com> wrote in message
news:2u******** *****@uni-berlin.de...
So, a compiler doesn't accept v.erase(v.rbegi n()).
Do we have to write v.erase(v.end() - 1)? Or there exists something
else?


How about v.pop_back()?
Jul 22 '05 #11

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