John Harrison wrote:
"Alex Vinokur" <al****@big-foot.com> wrote in message
news:2u******** *****@uni-berlin.de...
vector<int> v;
erase() requires (as input parameter) and returns vector<int>::it erator,
rbegin() returnsvectorin treverse_iterat or.
So, a compiler doesn't accept v.erase(v.rbegi n()).
Do we have to writ
ev.eraseOrthe reexistssomethi ngelse
reverse_iterato rs have a member function called base() which returns the
equivalent iterator. Use that.
john
From TC++PL 3:
"A reverse_iterato r is implemented using an iterator called current.
That iterator can (only) point to the elements of its sequence plus its
one-past-the-end element. However, the reverse_iterato r’s
one-past-the-end element is the original sequence’s (inaccessible)
one-before-the-beginning element.
Thus, to avoid access violations, current points to the element after
the one the reverse_iterato r refers to. This implies that * returns the
value *(current-1) and that ++ is implemented using -- on current".
In other words the base() of reverse_iterato r returns current, which is
one after the element that reverse_iterato r points, under the regular
iterator point of view.
So if you want to point to the same element with reverse_iterato r,
provided that reverse_iterato r does not point at "one past the end"
element of its view, you can do for example:
vector<int>::re verse_iterator rp = whatever;
// Not to be used for a reverse_iterato r pointing to "one past the end"
// element under its point of view.
vector<int>::it erator p = rp.base()-1;
--
Ioannis Vranos
http://www23.brinkster.com/noicys 
