replace special characters in string

[mr h q]

Hi all,

i want to replace $ to \$ so linux can work with paths and filenames
that contain $.
I wrote the following code

for(string::siz e_type i = s.find(exist, 0); i != string::npos; i =
s.find(foo, i))
{
s.replace(i, foo.size(), bar);
}

It's logical that this creates a loop that never ends, because i don't
replace the $, so my question is how to replace $ with \$ and then
jump to the next, instead of replacing \$ again..

tia...

[Karl Heinz Buchegger]

mr h q wrote:

Hi all,

i want to replace $ to \$ so linux can work with paths and filenames
that contain $.
I wrote the following code

for(string::siz e_type i = s.find(exist, 0); i != string::npos; i =
s.find(foo, i))
{
s.replace(i, foo.size(), bar);
}

It's logical that this creates a loop that never ends, because i don't
replace the $, so my question is how to replace $ with \$ and then
jump to the next, instead of replacing \$ again..

Well. If the $ happend to be at eg position 5 and you replace
$ with \$, then you know that the $ will move to position 6. Thus
if you continue searching at position 7, you will not interfere
with the text you replaced :-)

--
Karl Heinz Buchegger
kb******@gascad .at

[Rolf Magnus]

mr h q wrote:

Hi all,

i want to replace $ to \$ so linux can work with paths and filenames
that contain $.
I wrote the following code

for(string::siz e_type i = s.find(exist, 0); i != string::npos; i =
s.find(foo, i))
{
s.replace(i, foo.size(), bar);
}

It's logical that this creates a loop that never ends, because i don't
replace the $, so my question is how to replace $ with \$ and then
jump to the next, instead of replacing \$ again..

You have to start your following find() calls _after_ the replaced
string, not at the same location again. So try something like:

for(string::siz e_type i = s.find(exist, 0); i != string::npos;
i = s.find(foo, i + bar.size()))
{
s.replace(i, foo.size(), bar);
}

This should be save, since after the replacement, the string will be at
least i + bar.size() long.

[Brad Marts]

On Mon, 24 Nov 2003 15:53:52 +0100, Karl Heinz Buchegger wrote:

mr h q wrote:

Hi all,

i want to replace $ to \$ so linux can work with paths and filenames

Well. If the $ happend to be at eg position 5 and you replace
$ with \$, then you know that the $ will move to position 6. Thus
if you continue searching at position 7, you will not interfere
with the text you replaced :-)

In this case wouldn't the character that was originally at position 6 be
overwritten with $? I think he also needs to be careful to copy everything
after the $ to one position later in the string.

[mr h q]

Rolf Magnus <ra******@t-online.de> wrote in message news:<bp******* ******@news.t-online.com>...

mr h q wrote:

Hi all,

i want to replace $ to \$ so linux can work with paths and filenames
that contain $.
I wrote the following code

for(string::siz e_type i = s.find(exist, 0); i != string::npos; i =
s.find(foo, i))
{
s.replace(i, foo.size(), bar);
}

It's logical that this creates a loop that never ends, because i don't
replace the $, so my question is how to replace $ with \$ and then
jump to the next, instead of replacing \$ again..

You have to start your following find() calls _after_ the replaced
string, not at the same location again. So try something like:

for(string::siz e_type i = s.find(exist, 0); i != string::npos;
i = s.find(foo, i + bar.size()))
{
s.replace(i, foo.size(), bar);
}

This should be save, since after the replacement, the string will be at
least i + bar.size() long.

It works now...thanks!!

[Karl Heinz Buchegger]

Brad Marts wrote:

On Mon, 24 Nov 2003 15:53:52 +0100, Karl Heinz Buchegger wrote:

mr h q wrote:

Hi all,

i want to replace $ to \$ so linux can work with paths and filenames

Well. If the $ happend to be at eg position 5 and you replace
$ with \$, then you know that the $ will move to position 6. Thus
if you continue searching at position 7, you will not interfere
with the text you replaced :-)

In this case wouldn't the character that was originally at position 6 be
overwritten with $?

No, the test is *inserted*, meaning all text right to that position
gets shifted to the right.

If you replace $ with \$ in
abcd$efg

you get
abcd\$efg

The string got longer!
I think he also needs to be careful to copy everything
after the $ to one position later in the string.

std::string.rep lace does that already.
The OP's question turns around the find function used to find the next occurence
of the text to replace:

abc$def$ghi

find finds the first $ at position 3. Replacing that with the replacement text
leads to

abc\$def$ghi

Now if the find is restarted at position 4, it immediatly will find another $
at position 4. Doing the replacement leads to

abc\\$def$ghi

and so on and so on. The solution of course is to start the next find at the
end of the replaced text.

--
Karl Heinz Buchegger
kb******@gascad .at