regexp @ operator

[puzzlecracker]

I understand that the following would split the line in words space
separated: string[] words = Regex.Split(tex t, @"\W+"); Why do we need
@ before regular expression?
Thanks

[Stanimir Stoyanov]

In C# the backslash (\) serves for escaping characters, and when you want to
include the literal backslash you have to escape it in one of two ways:

1) using the @ prefix which escapes all backslashes, or
2) by escaping the backslash using another one, e.g. "\\W+"

I personally prefer and recommend the @ prefix because I don't have to do it
for further slashes.
--
Stanimir Stoyanov
http://stoyanoff.info

"puzzlecrac ker" <ir*********@gm ail.comwrote in message
news:9d******** *************** ***********@o40 g2000prn.google groups.com...

>I understand that the following would split the line in words space
separated: string[] words = Regex.Split(tex t, @"\W+"); Why do we need
@ before regular expression?
Thanks

[puzzlecracker]

On Nov 3, 9:09*am, "Stanimir Stoyanov" <stoya...@REMOV ETHIS.live.com>
wrote:

In C# the backslash (\) serves for escaping characters, and when you wantto
include the literal backslash you have to escape it in one of two ways:

1) using the @ prefix which escapes all backslashes, or
2) by escaping the backslash using another one, e.g. "\\W+"

I personally prefer and recommend the @ prefix because I don't have to doit
for further slashes.
--
Stanimir Stoyanovhttp://stoyanoff.info

"puzzlecrac ker" <ironsel2...@gm ail.comwrote in message

news:9d******** *************** ***********@o40 g2000prn.google groups.com...

I understand that the following would split the line in words space
separated: string[] words = Regex.Split(tex t, @"\W+"); Why do we need
@ before regular expression?

Thanks

I see, I use @ to escape line-breaks, that seems another useful
application.

Thanks

[Stanimir Stoyanov]

One thing to note though, if you use the @ prefix line breaks will not work.
This is, essentially, because the line break is escaped and the string is
interpreted as 'slash, r, slash, n' and not 'carriage return, line break'.
--
Stanimir Stoyanov
http://stoyanoff.info

"puzzlecrac ker" <ir*********@gm ail.comwrote in message
news:8b******** *************** ***********@s9g 2000prg.googleg roups.com...
On Nov 3, 9:09 am, "Stanimir Stoyanov" <stoya...@REMOV ETHIS.live.com>
wrote:

In C# the backslash (\) serves for escaping characters, and when you want
to
include the literal backslash you have to escape it in one of two ways:

1) using the @ prefix which escapes all backslashes, or
2) by escaping the backslash using another one, e.g. "\\W+"

I personally prefer and recommend the @ prefix because I don't have to do
it
for further slashes.
--
Stanimir Stoyanovhttp://stoyanoff.info

"puzzlecrac ker" <ironsel2...@gm ail.comwrote in message

news:9d******** *************** ***********@o40 g2000prn.google groups.com...

I understand that the following would split the line in words space
separated: string[] words = Regex.Split(tex t, @"\W+"); Why do we need
@ before regular expression?

Thanks

I see, I use @ to escape line-breaks, that seems another useful
application.

Thanks

[Ben Voigt [C++ MVP]]

Stanimir Stoyanov wrote:

One thing to note though, if you use the @ prefix line breaks will
not work. This is, essentially, because the line break is escaped and
the string is interpreted as 'slash, r, slash, n' and not 'carriage
return, line break'.

Line breaks work fine.

But they look like this:

string s = @"
";

not this:

string s = @"\r\n";

>
"puzzlecrac ker" <ir*********@gm ail.comwrote in message
news:8b******** *************** ***********@s9g 2000prg.googleg roups.com...
On Nov 3, 9:09 am, "Stanimir Stoyanov" <stoya...@REMOV ETHIS.live.com>
wrote:

>In C# the backslash (\) serves for escaping characters, and when you
want to
include the literal backslash you have to escape it in one of two
ways: 1) using the @ prefix which escapes all backslashes, or
2) by escaping the backslash using another one, e.g. "\\W+"

I personally prefer and recommend the @ prefix because I don't have
to do it
for further slashes.
--
Stanimir Stoyanovhttp://stoyanoff.info

"puzzlecracker " <ironsel2...@gm ail.comwrote in message

news:9d******* *************** ************@o4 0g2000prn.googl egroups.com...

>>I understand that the following would split the line in words space
separated: string[] words = Regex.Split(tex t, @"\W+"); Why do we
need @ before regular expression?

>>Thanks

I see, I use @ to escape line-breaks, that seems another useful
application.

Thanks

[Stanimir Stoyanov]

Thanks for pointing this out, Ben.

"Ben Voigt [C++ MVP]" <rb*@nospam.nos pamwrote in message
news:et******** ******@TK2MSFTN GP04.phx.gbl...

Stanimir Stoyanov wrote:

>One thing to note though, if you use the @ prefix line breaks will
not work. This is, essentially, because the line break is escaped and
the string is interpreted as 'slash, r, slash, n' and not 'carriage
return, line break'.

Line breaks work fine.

But they look like this:

string s = @"
";

not this:

string s = @"\r\n";

>>
"puzzlecracker " <ir*********@gm ail.comwrote in message
news:8b******* *************** ************@s9 g2000prg.google groups.com...
On Nov 3, 9:09 am, "Stanimir Stoyanov" <stoya...@REMOV ETHIS.live.com>
wrote:

>>In C# the backslash (\) serves for escaping characters, and when you
want to
include the literal backslash you have to escape it in one of two
ways: 1) using the @ prefix which escapes all backslashes, or
2) by escaping the backslash using another one, e.g. "\\W+"

I personally prefer and recommend the @ prefix because I don't have
to do it
for further slashes.
--
Stanimir Stoyanovhttp://stoyanoff.info

"puzzlecracke r" <ironsel2...@gm ail.comwrote in message

news:9d****** *************** *************@o 40g2000prn.goog legroups.com...

I understand that the following would split the line in words space
separated: string[] words = Regex.Split(tex t, @"\W+"); Why do we
need @ before regular expression?

Thanks

I see, I use @ to escape line-breaks, that seems another useful
application.

Thanks