Regex.Validate Date and Time

[shapper]

Hello,

What is the Regex expression to validate a date time format as
follows:

dd-mm-yyyy hh:mm:ss

An example:
20-10-2008 10:32:45

There should be a space between date and time.

Thanks,
Miguel

[Mythran]

"shapper" <md*****@gmail. comwrote in message
news:c9******** *************** ***********@c58 g2000hsc.google groups.com...

Hello,

What is the Regex expression to validate a date time format as
follows:

dd-mm-yyyy hh:mm:ss

An example:
20-10-2008 10:32:45

There should be a space between date and time.

Thanks,
Miguel

\d\d-\d\d-\d{4} \d\d:\d\d:\d\d

Matches for me....although I would probably use the DateTime.TryPar se method
instead so you don't have to limit the input to a single format.

HTH,
Mythran

[Duggi]

On Jun 19, 2:38*am, shapper <mdmo...@gmail. comwrote:

Hello,

What is the Regex expression to validate a date time format as
follows:

dd-mm-yyyy hh:mm:ss

An example:
20-10-2008 10:32:45

There should be a space between date and time.

Thanks,
Miguel

Instead of RegEx, Try using DateTime.TryPar se, that should be the
better approach.

-Cnu

[=?ISO-8859-1?Q?G=F6ran_Andersson?=]

shapper wrote:

Hello,

What is the Regex expression to validate a date time format as
follows:

dd-mm-yyyy hh:mm:ss

An example:
20-10-2008 10:32:45

There should be a space between date and time.

Thanks,
Miguel

If you use a regular expression, you can only validate the format of the
date, you can not validate that it's actually a valid date.

For example, a simple regular expression would allow a date like
"42-18-2008 29:63:81". A more advanced regular expression could catch
that, but it can still not tell that "29-02-2007 10:32:45" is not a
valid date.

Use the DateTime.TryPar seExact method with a format like
"dd'-'MM'-'yyyy' 'HH':'mm':'ss" to validate the string.

--
Göran Andersson
_____
http://www.guffa.com

[shapper]

On Jun 19, 9:47*am, Göran Andersson <[e-mail] mwrote:

shapper wrote:

Hello,

What is the Regex expression to validate a date time format as
follows:

dd-mm-yyyy hh:mm:ss

An example:
20-10-2008 10:32:45

There should be a space between date and time.

Thanks,
Miguel

If you use a regular expression, you can only validate the format of the
date, you can not validate that it's actually a valid date.

For example, a simple regular expression would allow a date like
"42-18-2008 29:63:81". A more advanced regular expression could catch
that, but it can still not tell that "29-02-2007 10:32:45" is not a
valid date.

Use the DateTime.TryPar seExact method with a format like
"dd'-'MM'-'yyyy' 'HH':'mm':'ss" to validate the string.

--
Göran Andersson
_____http://www.guffa.com

Hi,

I was able to do it using:

^([0-9]{4})-([0-1][0-9])-([0-3][0-9])\s([0-1][0-9]|[2][0-3]):([0-5]
[0-9]):([0-5][0-9])$

But this does no accept empty values.

Can I create a RegEx that accepts empty values and when the value is
not empty then it validates?

Thanks,
Miguel

[=?ISO-8859-1?Q?G=F6ran_Andersson?=]

shapper wrote:

On Jun 19, 9:47 am, Göran Andersson <[e-mail] mwrote:

>shapper wrote:

>>Hello,
What is the Regex expression to validate a date time format as
follows:
dd-mm-yyyy hh:mm:ss
An example:
20-10-2008 10:32:45
There should be a space between date and time.
Thanks,
Miguel

If you use a regular expression, you can only validate the format of the
date, you can not validate that it's actually a valid date.

For example, a simple regular expression would allow a date like
"42-18-2008 29:63:81". A more advanced regular expression could catch
that, but it can still not tell that "29-02-2007 10:32:45" is not a
valid date.

Use the DateTime.TryPar seExact method with a format like
"dd'-'MM'-'yyyy' 'HH':'mm':'ss" to validate the string.

--
Göran Andersson
_____http://www.guffa.com

Hi,

I was able to do it using:

^([0-9]{4})-([0-1][0-9])-([0-3][0-9])\s([0-1][0-9]|[2][0-3]):([0-5]
[0-9]):([0-5][0-9])$

That would accept a date like 2008-19-39...

This will get you a bit closer:

^\d{4}-(0[1-9]|1[0-2])-(0[1-9]|[1-2]\d|3[0-1])\s([0-1]\d|2[0-3])(:[0-5]\d){2}$

But still it has no idea about the different number of days in months. A
date like 2008-02-31 is still accepted.

But this does no accept empty values.

Can I create a RegEx that accepts empty values and when the value is
not empty then it validates?

You can just add ()? around the expression to make it conditional:

^(\d{4}-(0[1-9]|1[0-2])-(0[1-9]|[1-2]\d|3[0-1])\s([0-1]\d|2[0-3])(:[0-5]\d){2})?$

--
Göran Andersson
_____
http://www.guffa.com