Rick,
That won't work, because you can end up with more than one of any of the
numbers (with the exception of 9) in the array elements. I believe the OP
wanted to have the values 1-10 randomized in an array.
This is how I would do it:
// Generate the array.
int[] arr = new int[10]{1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
// Cycle through the array, swapping out the current element with a random
element.
// Create the random number generator first.
Random random = new Random();
// A temp value.
int temp = 0;
// The new index.
int newIndex = 0;
// Cycle through the elements.
for (int index = 0; index < arr.Length; ++index)
{
// Swap element index out with another element. Get
// the new index first.
newIndex = random.Next(arr .Length);
// Store the element.
temp = arr[newIndex];
// Store the current element in the new index.
arr[newIndex] = arr[index];
// Swap the element back.
arr[index] = temp;
}
Hope this helps.
--
- Nicholas Paldino [.NET/C# MVP]
-
mv*@spam.guard. caspershouse.co m
"Rick Lones" <Wr******@Ychar terZ.net> wrote in message
news:_w******** **********@fe02 .lga...
James wrote: Just learning C#.
What's the easiest way to assign numbers 1-10 randomly to an array?
Basically I just want to take the numbers 1-10 and arrange them randomly
in
slots 0-9 of an array.
This isn't a C# question, but . . .
1) Assign the numbers 1 - 10 to array slots 0 - 9, respectively.
2) Do a random shuffle of the array.
Random shuffle:
- Generate a random # n0 between 0 and 9. Swap array[n0] with array[9].
- Generate a random # n1 between 0 and 8. Swap array[n1] with array[8].
. . .
- Generate a random # n8 between 0 and 1. Swap array[n8] with array[1].
HTH,
-rick-
