I have a for loop and i want to do different things depending on whether
the counter is even or odd.
I know there is probably some really simple math thing that can do this
but my maths is a bit hazy. I did check the MS C# library site but had
no luck.
Any help appreciated.
--
Eps http://ukcomment.blogspot.com/
A UK political Blog 8  39203 
Hi,
You can use System.Math.Div Rem method. It takes numbers as input and
returns quotient and gives remainder as out parameter.
Reshma
"Eps" <ep*@mailinator .com> wrote in message
news:d3******** **@domitilla.ai oe.org... I have a for loop and i want to do different things depending on whether
the counter is even or odd.
I know there is probably some really simple math thing that can do this
but my maths is a bit hazy. I did check the MS C# library site but had no
luck.
Any help appreciated.
--
Eps
http://ukcomment.blogspot.com/
A UK political Blog
The other suggestions for using a modulus operator certainly work, but I've
always done it with a bitwise operation, since any odd number will have the
low order bit set:
if ( (n & 1) == 0 )
Console.WriteLi ne( "Odd" );
else
Console.WriteLi ne( "Even" );
Looked at objectively, the bitwise operation is probably more obscure than
the modulus operation, but to me it has always been one of those common
idioms that every (by which I mean everyone I work with) C programmer has in
common.
"Eps" <ep*@mailinator .com> wrote in message
news:d3******** **@domitilla.ai oe.org... I have a for loop and i want to do different things depending on whether
the counter is even or odd.
I know there is probably some really simple math thing that can do this
but my maths is a bit hazy. I did check the MS C# library site but had
no luck.
Any help appreciated.
--
Eps
http://ukcomment.blogspot.com/
A UK political Blog
"Joe Fromm" <Jo*******@Pear son.com> schrieb im Newsbeitrag
news:ep******** ******@TK2MSFTN GP14.phx.gbl... The other suggestions for using a modulus operator certainly work, but
I've
always done it with a bitwise operation, since any odd number will have
the
low order bit set:
if ( (n & 1) == 0 )
Console.WriteLi ne( "Odd" );
else
Console.WriteLi ne( "Even" );
Little but fatal error in your code :-)
The number is odd, if the low order bit is set:
Right version:
if ( (n & 1) == 0 )
Console.WriteLi ne( "Even" );
else
Console.WriteLi ne( "Odd" );
Or rather, test for 1 or swap the "Odd" and "Even" :)
if ( (n & 1) == 1 ) // Odd
if ( (n & 1) == 0 ) // Even
On Thu, 14 Apr 2005 08:36:23 -0500, Joe Fromm <Jo*******@Pear son.com>
wrote: The other suggestions for using a modulus operator certainly work, but
I've
always done it with a bitwise operation, since any odd number will have
the
low order bit set:
if ( (n & 1) == 0 )
Console.WriteLi ne( "Odd" );
else
Console.WriteLi ne( "Even" );
Looked at objectively, the bitwise operation is probably more obscure
than
the modulus operation, but to me it has always been one of those common
idioms that every (by which I mean everyone I work with) C programmer
has in
common.
"Eps" <ep*@mailinator .com> wrote in message
news:d3******** **@domitilla.ai oe.org... I have a for loop and i want to do different things depending on whether
the counter is even or odd.
I know there is probably some really simple math thing that can do this
but my maths is a bit hazy. I did check the MS C# library site but had
no luck.
Any help appreciated.
--
Eps
http://ukcomment.blogspot.com/
A UK political Blog
--
Happy Coding!
Morten Wennevik [C# MVP]
Hmmm... instead of:
for (int i = 0; i < 10; ++i)
{
if (i % 2 ==0 )
Console.Write(" {0} is Even", i);
else
Console.Write(" {0} is Odd", i);
}
how 'bout we try:
for (int i = 0; i < 10; i = i + 2)
{
Console.Write(" {0} is Even", i);
Console.Write(" {0} is Odd", i+1);
}
--
--
Truth,
James Curran
[erstwhile VC++ MVP]
Home: www.noveltheory.com Work: www.njtheater.com
Blog: www.honestillusion.com Day Job: www.partsearch.com
"Eps" <ep*@mailinator .com> wrote in message
news:d3******** **@domitilla.ai oe.org... I have a for loop and i want to do different things depending on whether
the counter is even or odd.
I know there is probably some really simple math thing that can do this
but my maths is a bit hazy. I did check the MS C# library site but had
no luck.
Any help appreciated.
--
Eps
http://ukcomment.blogspot.com/
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