how to fix decimal places?

[Ron]

Greetings,

int i = 1, j = 6;
double k = (double)i/j;
Console.WriteLi ne(k.ToString() );
Console.WriteLi ne(string.Forma t(k.ToString(), "0.00"));

both yield 0.1666666666666 67

how can I make it yield 0.17? I know there is some
method, I just can't think of it.
Thanks,
Ron

[Ron]

I found this so far, is there a more correct method?

int i = 1, j = 6;
double k = (double)i/j;
decimal rounded = decimal.Round(( decimal)k, 2);
Console.WriteLi ne(rounded.ToSt ring());

yields 0.17

-----Original Message-----
Greetings,

int i = 1, j = 6;
double k = (double)i/j;
Console.WriteL ine(k.ToString( ));
Console.WriteL ine(string.Form at(k.ToString() , "0.00"));

both yield 0.1666666666666 67

how can I make it yield 0.17? I know there is some
method, I just can't think of it.
Thanks,
Ron
.

[Zoury]

Hi Ron! :O)

you should take a look at String.Format() method's help.. it is not the same
as the Format$() method of VB.

ToString() is the method you were looking for (sooo close ;O):
//***
Console.WriteLi ne(((double)5.2 345345).ToStrin g("0.00"));
Console.ReadLin e();
//***

--
Best Regards
Yanick
"Ron" <an*******@disc ussions.microso ft.com> a écrit dans le message de
news:15******** *************** *****@phx.gbl.. .

Greetings,

int i = 1, j = 6;
double k = (double)i/j;
Console.WriteLi ne(k.ToString() );
Console.WriteLi ne(string.Forma t(k.ToString(), "0.00"));

both yield 0.1666666666666 67

how can I make it yield 0.17? I know there is some
method, I just can't think of it.
Thanks,
Ron

[Zoury]

the decimal.Round() method (and some others i guess) uses a algorithm named
"Banker's Rounding" which might not give you the result you expect..

ex :
//***
Console.WriteLi ne(decimal.Roun d(((decimal)0.5 ), 0).ToString());
Console.WriteLi ne(decimal.Roun d(((decimal)1.5 ), 0).ToString());
Console.WriteLi ne(decimal.Roun d(((decimal)2.5 ), 0).ToString());
Console.ReadLin e();
//***

returns :
0
2
2

see this link for more information about this topic
http://support.microsoft.com/kb/196652/en-us
besides, as you might know, there is a huge difference between Rounding a
value (loosing precision) and Formatting a value (showing a value in a human
readable format), thus ToString() is the way go.
//***
Console.WriteLi ne(((double)0.5 ).ToString("0") );
Console.WriteLi ne(((double)1.5 ).ToString("0") );
Console.WriteLi ne(((double)2.5 ).ToString("0") );
Console.ReadLin e();
//***

returns :
1
2
3

--
Best Regards
Yanick
"Ron" <an*******@disc ussions.microso ft.com> a écrit dans le message de
news:0b******** *************** *****@phx.gbl.. .

I found this so far, is there a more correct method?

int i = 1, j = 6;
double k = (double)i/j;
decimal rounded = decimal.Round(( decimal)k, 2);
Console.WriteLi ne(rounded.ToSt ring());

yields 0.17

-----Original Message-----
Greetings,

int i = 1, j = 6;
double k = (double)i/j;
Console.WriteL ine(k.ToString( ));
Console.WriteL ine(string.Form at(k.ToString() , "0.00"));

both yield 0.1666666666666 67

how can I make it yield 0.17? I know there is some
method, I just can't think of it.
Thanks,
Ron
.

[Ron]

Yes, thank you. That is what I was looking for.

Thanks.

-----Original Message-----
Hi Ron! :O)

you should take a look at String.Format() method's help.. it is not the sameas the Format$() method of VB.

ToString() is the method you were looking for (sooo close ;O)://***
Console.WriteL ine(((double)5. 2345345).ToStri ng("0.00"));
Console.ReadLi ne();
//***

--
Best Regards
Yanick
"Ron" <an*******@disc ussions.microso ft.com> a écrit dans le message denews:15******* *************** ******@phx.gbl. ..

Greetings,

int i = 1, j = 6;
double k = (double)i/j;
Console.WriteLi ne(k.ToString() );
Console.WriteLi ne(string.Forma t(k.ToString(), "0.00"));

both yield 0.1666666666666 67

how can I make it yield 0.17? I know there is some
method, I just can't think of it.
Thanks,
Ron

.