Simple XML parsing question..

[Ivan Demkovitch]

Hi!

I'm trying to parse RSS news feed with code as simple as possible.

Simple XML:
<?xml version="1.0"?>
<rss version="2.0">
<channel>

<item>
<title>The situation of F1 in Russia</title>
<link>http://www.grandprix.c om/ns/ns12094.html</link>
<description> R-Fast, the Russian Federation of Autosport and Tourism, the
national sporting authority of Russia, has been giving details of its plans
to increase motor racing activities in Russia. These date back to 1998 when
R-FAST began working with the Moscow City Government on the idea of an
international racing circuit in the city. </description>
<guid>http://www.grandprix.c om/ns/ns12094.html</guid>
<pubDate>Tue, 28 Oct 2003 8:36:40 GMT</pubDate>
</item>

<item>
<title>Massa at Sauber - it's official</title>
<link>http://www.grandprix.c om/ns/ns12096.html</link>
<description>Th e long-awaited announcement from Sauber that Felipe Massa
will be driving of the team in 2004 is no surprise. Massa has agreed a
two-year deal with the Swiss team but it is expected that he will have a
get-out clause to move to Ferrari in 2005 if a drive is
available.</description>
<guid>http://www.grandprix.c om/ns/ns12096.html</guid>
<pubDate>Tue, 28 Oct 2003 14:43:20 GMT</pubDate>
</item>

</channel>
</rss>

Now I'm writing code:

void XMLParse(string xmldata) {

//using Microsoft XML Parser
XmlTextReader xml_read = new XmlTextReader(n ew
StringReader(xm ldata));

xml_read.Whites paceHandling = WhitespaceHandl ing.None;

//Get all Items into node list...
XmlNodeList items = oXML.GetElement sByTagName("ite m");

foreach(XmlNode node in items){

//What's here???
}


QUESTION??

When in foreach I need simply get values of title, link, guid and pubDate

How do I do it?

[Nicholas Paldino [.NET/C# MVP]]

Ivan,

For each node in the foreach statement ("node"), you can call the
SelectSingleNod e method and pass the name of the decendant element, like so:

XmlNode pobjTitleNode = node.SelectSing leNode("title") ;
XmlNode pobjLinkNode = node.SelectSing leNode("link");

And so on. From there, you can use the properties of the node to get
the text.

Hope this helps.
--
- Nicholas Paldino [.NET/C# MVP]
- mv*@spam.guard. caspershouse.co m

"Ivan Demkovitch" <i@a.b> wrote in message
news:ev******** ******@TK2MSFTN GP11.phx.gbl...

Hi!

I'm trying to parse RSS news feed with code as simple as possible.

Simple XML:
<?xml version="1.0"?>
<rss version="2.0">
<channel>

<item>
<title>The situation of F1 in Russia</title>
<link>http://www.grandprix.c om/ns/ns12094.html</link>
<description> R-Fast, the Russian Federation of Autosport and Tourism, the
national sporting authority of Russia, has been giving details of its plans to increase motor racing activities in Russia. These date back to 1998 when R-FAST began working with the Moscow City Government on the idea of an
international racing circuit in the city. </description>
<guid>http://www.grandprix.c om/ns/ns12094.html</guid>
<pubDate>Tue, 28 Oct 2003 8:36:40 GMT</pubDate>
</item>

<item>
<title>Massa at Sauber - it's official</title>
<link>http://www.grandprix.c om/ns/ns12096.html</link>
<description>Th e long-awaited announcement from Sauber that Felipe Massa
will be driving of the team in 2004 is no surprise. Massa has agreed a
two-year deal with the Swiss team but it is expected that he will have a
get-out clause to move to Ferrari in 2005 if a drive is
available.</description>
<guid>http://www.grandprix.c om/ns/ns12096.html</guid>
<pubDate>Tue, 28 Oct 2003 14:43:20 GMT</pubDate>
</item>

</channel>
</rss>

Now I'm writing code:

void XMLParse(string xmldata) {

//using Microsoft XML Parser
XmlTextReader xml_read = new XmlTextReader(n ew
StringReader(xm ldata));

xml_read.Whites paceHandling = WhitespaceHandl ing.None;

//Get all Items into node list...
XmlNodeList items = oXML.GetElement sByTagName("ite m");

foreach(XmlNode node in items){

//What's here???
}


QUESTION??

When in foreach I need simply get values of title, link, guid and pubDate

How do I do it?

[Ivan Demkovitch]

Actually is was simpler (just got it)
Let me know if this could present problems:

node.SelectSing leNode("title") .InnerText

returned what I needed saving some lines of code...
"Nicholas Paldino [.NET/C# MVP]" <mv*@spam.guard .caspershouse.c om> wrote in
message news:%2******** *******@TK2MSFT NGP09.phx.gbl.. .

Ivan,

For each node in the foreach statement ("node"), you can call the
SelectSingleNod e method and pass the name of the decendant element, like so:
XmlNode pobjTitleNode = node.SelectSing leNode("title") ;
XmlNode pobjLinkNode = node.SelectSing leNode("link");

And so on. From there, you can use the properties of the node to get
the text.

Hope this helps.
--
- Nicholas Paldino [.NET/C# MVP]
- mv*@spam.guard. caspershouse.co m

"Ivan Demkovitch" <i@a.b> wrote in message
news:ev******** ******@TK2MSFTN GP11.phx.gbl...

Hi!

I'm trying to parse RSS news feed with code as simple as possible.

Simple XML:
<?xml version="1.0"?>
<rss version="2.0">
<channel>

<item>
<title>The situation of F1 in Russia</title>
<link>http://www.grandprix.c om/ns/ns12094.html</link>
<description> R-Fast, the Russian Federation of Autosport and Tourism, the national sporting authority of Russia, has been giving details of its

plans

to increase motor racing activities in Russia. These date back to 1998

when

R-FAST began working with the Moscow City Government on the idea of an
international racing circuit in the city. </description>
<guid>http://www.grandprix.c om/ns/ns12094.html</guid>
<pubDate>Tue, 28 Oct 2003 8:36:40 GMT</pubDate>
</item>

<item>
<title>Massa at Sauber - it's official</title>
<link>http://www.grandprix.c om/ns/ns12096.html</link>
<description>Th e long-awaited announcement from Sauber that Felipe Massa
will be driving of the team in 2004 is no surprise. Massa has agreed a
two-year deal with the Swiss team but it is expected that he will have a
get-out clause to move to Ferrari in 2005 if a drive is
available.</description>
<guid>http://www.grandprix.c om/ns/ns12096.html</guid>
<pubDate>Tue, 28 Oct 2003 14:43:20 GMT</pubDate>
</item>

</channel>
</rss>

Now I'm writing code:

void XMLParse(string xmldata) {

//using Microsoft XML Parser
XmlTextReader xml_read = new XmlTextReader(n ew
StringReader(xm ldata));

xml_read.Whites paceHandling = WhitespaceHandl ing.None;

//Get all Items into node list...
XmlNodeList items = oXML.GetElement sByTagName("ite m");

foreach(XmlNode node in items){

//What's here???
}


QUESTION??

When in foreach I need simply get values of title, link, guid and pubDate
How do I do it?