It says invalid expression term &&
protected void GridView1_RowDa taBound(object sender,
GridViewRowEven tArgs e)
{
if
((Convert.ToInt 32(e.Row.Cells[2].Text)>=15))&&( Convert.ToInt32 (e.Row.Cells[2].Text)>=17);
{
e.Row.Cells[0].CssClass = "sdgStatusOrang e";
}
It says invalid expression term &&
14  1415 
On Thu, 21 Jun 2007 13:19:41 -0700, bb****@yahoo.co m wrote:
It says invalid expression term &&
protected void GridView1_RowDa taBound(object sender,
GridViewRowEve ntArgs e)
{
if
((Convert.ToIn t32(e.Row.Cells[2].Text)>=15))&&( Convert.ToInt32 (e.Row.Cells[2].Text)>=17);
{
e.Row.Cells[0].CssClass = "sdgStatusOrang e";
}
It says invalid expression term &&
Check the parens ( maybe):
if
((Convert.ToInt 32(e.Row.Cells[2].Text)>=15)&& (Convert.ToInt3 2(e.Row.Cells[2].Text)>=17)) ;
{
e.Row.Cells[0].CssClass = "sdgStatusOrang e";
}
<bb****@yahoo.c omwrote in message
news:11******** *************@e 9g2000prf.googl egroups.com...
It says invalid expression term &&
protected void GridView1_RowDa taBound(object sender,
GridViewRowEven tArgs e)
{
if
((Convert.ToInt 32(e.Row.Cells[2].Text)>=15))&&( Convert.ToInt32 (e.Row.Cells[2].Text)>=17);
{
e.Row.Cells[0].CssClass = "sdgStatusOrang e";
}
It says invalid expression term &&
You've got your parentheses slightly confused:
if((Convert.ToI nt32(e.Row.Cell s[2].Text)>=15)&&(C onvert.ToInt32( e.Row.Cells[2].Text)>=17))
-- http://www.markrae.net
re:
((Convert.ToInt 32(e.Row.Cells[2].Text)>=15))&&( Convert.ToInt32 (e.Row.Cells[2].Text)>=17);
You need to use the "regular" AND operator.
Try :
((Convert.ToInt 32(e.Row.Cells[2].Text)>=15))&(C onvert.ToInt32( e.Row.Cells[2].Text)>=17);
If you use && and e.Row.Cells[2].Text)>=15 is false, e.Row.Cells[2].Text)>=17
is not evaluated (because the result of the AND operation is false no matter what the
value of e.Row.Cells[2].Text)>=17 may be).
This is known as "short-circuit" evaluation...bu t it requires *both* operands to be true.
In your code, that is not alsways the case.
Juan T. Llibre, asp.net MVP
asp.net faq : http://asp.net.do/faq/
foros de asp.net, en español : http://asp.net.do/foros/
=============== =============== ========
<bb****@yahoo.c omwrote in message news:11******** *************@e 9g2000prf.googl egroups.com...
It says invalid expression term &&
protected void GridView1_RowDa taBound(object sender,
GridViewRowEven tArgs e)
{
if
((Convert.ToInt 32(e.Row.Cells[2].Text)>=15))&&( Convert.ToInt32 (e.Row.Cells[2].Text)>=17);
{
e.Row.Cells[0].CssClass = "sdgStatusOrang e";
}
It says invalid expression term &&
The problem is a bit more than just misplaced parens.
See my just-sent explanation.
Juan T. Llibre, asp.net MVP
asp.net faq : http://asp.net.do/faq/
foros de asp.net, en español : http://asp.net.do/foros/
=============== =============== ========
"Turkbear" <no***@nowhere. comwrote in message news:91******** *************** *********@4ax.c om...
On Thu, 21 Jun 2007 13:19:41 -0700, bb****@yahoo.co m wrote:
>It says invalid expression term &&
protected void GridView1_RowDa taBound(object sender,
GridViewRowEv entArgs e)
{
if
((Convert.ToI nt32(e.Row.Cell s[2].Text)>=15))&&( Convert.ToInt32 (e.Row.Cells[2].Text)>=17);
{
e.Row.Cells[0].CssClass = "sdgStatusOrang e";
}
It says invalid expression term &&
Check the parens ( maybe):
if
((Convert.ToInt 32(e.Row.Cells[2].Text)>=15)&& (Convert.ToInt3 2(e.Row.Cells[2].Text)>=17)) ;
{
e.Row.Cells[0].CssClass = "sdgStatusOrang e";
}
Hi Juan,
In this case, "invalid expression term &&" is caused definitely by misplaced
parentheses, because it is a compiler message ;-) (evaluation would be done
at the runtime). Second, bitwise and & operator will give the same result
(apart from the fact short-circuit is not apllicable) because true & true =
true, false & true = false, false & false = false. Therefore, it should be
corrected to:
if (
(Convert.ToInt3 2(e.Row.Cells[2].Text) >= 15) &&
(Convert.ToInt3 2(e.Row.Cells[2].Text) >= 17))
{
e.Row.Cells[0].CssClass = "sdgStatusOrang e";
}
Best regards
--
Milosz
"Juan T. Llibre" wrote:
re:
((Convert.ToInt 32(e.Row.Cells[2].Text)>=15))&&( Convert.ToInt32 (e.Row.Cells[2].Text)>=17);
You need to use the "regular" AND operator.
Try :
((Convert.ToInt 32(e.Row.Cells[2].Text)>=15))&(C onvert.ToInt32( e.Row.Cells[2].Text)>=17);
If you use && and e.Row.Cells[2].Text)>=15 is false, e.Row.Cells[2].Text)>=17
is not evaluated (because the result of the AND operation is false no matter what the
value of e.Row.Cells[2].Text)>=17 may be).
This is known as "short-circuit" evaluation...bu t it requires *both* operands to be true.
In your code, that is not alsways the case.
Juan T. Llibre, asp.net MVP
asp.net faq : http://asp.net.do/faq/
foros de asp.net, en español : http://asp.net.do/foros/
=============== =============== ========
<bb****@yahoo.c omwrote in message news:11******** *************@e 9g2000prf.googl egroups.com...
It says invalid expression term &&
protected void GridView1_RowDa taBound(object sender,
GridViewRowEven tArgs e)
{
if
((Convert.ToInt 32(e.Row.Cells[2].Text)>=15))&&( Convert.ToInt32 (e.Row.Cells[2].Text)>=17);
{
e.Row.Cells[0].CssClass = "sdgStatusOrang e";
}
It says invalid expression term &&
Hi, Milosz,
In that case, what happens if Convert.ToInt32 (e.Row.Cells[2].Text = 14) ?
Juan T. Llibre, asp.net MVP
asp.net faq : http://asp.net.do/faq/
foros de asp.net, en español : http://asp.net.do/foros/
=============== =============== ========
"Milosz Skalecki [MCAD]" <mi*****@DONTLI KESPAMwp.plwrot e in message
news:85******** *************** ***********@mic rosoft.com...
Hi Juan,
In this case, "invalid expression term &&" is caused definitely by misplaced
parentheses, because it is a compiler message ;-) (evaluation would be done
at the runtime). Second, bitwise and & operator will give the same result
(apart from the fact short-circuit is not apllicable) because true & true =
true, false & true = false, false & false = false. Therefore, it should be
corrected to:
if (
(Convert.ToInt3 2(e.Row.Cells[2].Text) >= 15) &&
(Convert.ToInt3 2(e.Row.Cells[2].Text) >= 17))
{
e.Row.Cells[0].CssClass = "sdgStatusOrang e";
}
Best regards
--
Milosz
"Juan T. Llibre" wrote:
>re:
((Convert.ToIn t32(e.Row.Cells[2].Text)>=15))&&( Convert.ToInt32 (e.Row.Cells[2].Text)>=17);
You need to use the "regular" AND operator.
Try :
((Convert.ToIn t32(e.Row.Cells[2].Text)>=15))&(C onvert.ToInt32( e.Row.Cells[2].Text)>=17);
If you use && and e.Row.Cells[2].Text)>=15 is false, e.Row.Cells[2].Text)>=17
is not evaluated (because the result of the AND operation is false no matter what the
value of e.Row.Cells[2].Text)>=17 may be).
This is known as "short-circuit" evaluation...bu t it requires *both* operands to be true.
In your code, that is not alsways the case.
Juan T. Llibre, asp.net MVP
asp.net faq : http://asp.net.do/faq/
foros de asp.net, en español : http://asp.net.do/foros/
============== =============== =========
<bb****@yahoo. comwrote in message news:11******** *************@e 9g2000prf.googl egroups.com...
It says invalid expression term &&
protected void GridView1_RowDa taBound(object sender,
GridViewRowEven tArgs e)
{
if
((Convert.ToInt 32(e.Row.Cells[2].Text)>=15))&&( Convert.ToInt32 (e.Row.Cells[2].Text)>=17);
{
e.Row.Cells[0].CssClass = "sdgStatusOrang e";
}
It says invalid expression term &&
Good morning Juan
Did you mean if the text in cell equals "14"
if (
(Convert.ToInt3 2(e.Row.Cells[2].Text) >= 15) &&
(Convert.ToInt3 2(e.Row.Cells[2].Text) >= 17))
{
e.Row.Cells[0].CssClass = "sdgStatusOrang e";
}
then statement inside is not going to be reached, simply because the first
condition is false, and short-circuit evaluation for && operator skips the
second operand. I understand your confusion as I have seen this guy's
previous post, but in this case it was just misplaced parentheses ;-)
--
Milosz
"Juan T. Llibre" wrote:
Hi, Milosz,
In that case, what happens if Convert.ToInt32 (e.Row.Cells[2].Text = 14) ?
Juan T. Llibre, asp.net MVP
asp.net faq : http://asp.net.do/faq/
foros de asp.net, en español : http://asp.net.do/foros/
=============== =============== ========
"Milosz Skalecki [MCAD]" <mi*****@DONTLI KESPAMwp.plwrot e in message
news:85******** *************** ***********@mic rosoft.com...
Hi Juan,
In this case, "invalid expression term &&" is caused definitely by misplaced
parentheses, because it is a compiler message ;-) (evaluation would be done
at the runtime). Second, bitwise and & operator will give the same result
(apart from the fact short-circuit is not apllicable) because true & true =
true, false & true = false, false & false = false. Therefore, it should be
corrected to:
if (
(Convert.ToInt3 2(e.Row.Cells[2].Text) >= 15) &&
(Convert.ToInt3 2(e.Row.Cells[2].Text) >= 17))
{
e.Row.Cells[0].CssClass = "sdgStatusOrang e";
}
Best regards
--
Milosz
"Juan T. Llibre" wrote:
re:
((Convert.ToInt 32(e.Row.Cells[2].Text)>=15))&&( Convert.ToInt32 (e.Row.Cells[2].Text)>=17);
You need to use the "regular" AND operator.
Try :
((Convert.ToInt 32(e.Row.Cells[2].Text)>=15))&(C onvert.ToInt32( e.Row.Cells[2].Text)>=17);
If you use && and e.Row.Cells[2].Text)>=15 is false, e.Row.Cells[2].Text)>=17
is not evaluated (because the result of the AND operation is false no matter what the
value of e.Row.Cells[2].Text)>=17 may be).
This is known as "short-circuit" evaluation...bu t it requires *both* operands to be true.
In your code, that is not alsways the case.
Juan T. Llibre, asp.net MVP
asp.net faq : http://asp.net.do/faq/
foros de asp.net, en español : http://asp.net.do/foros/
=============== =============== ========
<bb****@yahoo.c omwrote in message news:11******** *************@e 9g2000prf.googl egroups.com...
It says invalid expression term &&
protected void GridView1_RowDa taBound(object sender,
GridViewRowEven tArgs e)
{
if
((Convert.ToInt 32(e.Row.Cells[2].Text)>=15))&&( Convert.ToInt32 (e.Row.Cells[2].Text)>=17);
{
e.Row.Cells[0].CssClass = "sdgStatusOrang e";
}
It says invalid expression term &&
re:
!Did you mean if the text in cell equals "14"
Yes.
re:
!then statement inside is not going to be reached, simply because the first
!condition is false, and short-circuit evaluation for && operator skips the second operand.
That's exactly what I explained...and that's an undesirable "feature".
That's why he needs to change the operator.
re:
!I understand your confusion
There's no confusion.
He should change both the parens *and* the operator,
the first as you suggest; the second as I suggest.
Doing that will cover all the bases for him.
Juan T. Llibre, asp.net MVP
asp.net faq : http://asp.net.do/faq/
foros de asp.net, en español : http://asp.net.do/foros/
=============== =============== ========
"Milosz Skalecki [MCAD]" <mi*****@DONTLI KESPAMwp.plwrot e in message
news:71******** *************** ***********@mic rosoft.com...
Good morning Juan
Did you mean if the text in cell equals "14"
if (
(Convert.ToInt3 2(e.Row.Cells[2].Text) >= 15) &&
(Convert.ToInt3 2(e.Row.Cells[2].Text) >= 17))
{
e.Row.Cells[0].CssClass = "sdgStatusOrang e";
}
then statement inside is not going to be reached, simply because the first
condition is false, and short-circuit evaluation for && operator skips the
second operand. I understand your confusion as I have seen this guy's
previous post, but in this case it was just misplaced parentheses ;-)
--
Milosz
"Juan T. Llibre" wrote:
>Hi, Milosz,
In that case, what happens if Convert.ToInt32 (e.Row.Cells[2].Text = 14) ?
Juan T. Llibre, asp.net MVP
asp.net faq : http://asp.net.do/faq/
foros de asp.net, en español : http://asp.net.do/foros/
============== =============== =========
"Milosz Skalecki [MCAD]" <mi*****@DONTLI KESPAMwp.plwrot e in message
news:85******* *************** ************@mi crosoft.com...
Hi Juan,
In this case, "invalid expression term &&" is caused definitely by misplaced
parentheses, because it is a compiler message ;-) (evaluation would be done
at the runtime). Second, bitwise and & operator will give the same result
(apart from the fact short-circuit is not apllicable) because true & true =
true, false & true = false, false & false = false. Therefore, it should be
corrected to:
if (
(Convert.ToInt3 2(e.Row.Cells[2].Text) >= 15) &&
(Convert.ToInt3 2(e.Row.Cells[2].Text) >= 17))
{
e.Row.Cells[0].CssClass = "sdgStatusOrang e";
}
Best regards
--
Milosz
"Juan T. Llibre" wrote:
re:
((Convert.ToIn t32(e.Row.Cells[2].Text)>=15))&&( Convert.ToInt32 (e.Row.Cells[2].Text)>=17);
You need to use the "regular" AND operator.
Try :
((Convert.ToIn t32(e.Row.Cells[2].Text)>=15))&(C onvert.ToInt32( e.Row.Cells[2].Text)>=17);
If you use && and e.Row.Cells[2].Text)>=15 is false, e.Row.Cells[2].Text)>=17
is not evaluated (because the result of the AND operation is false no matter what the
value of e.Row.Cells[2].Text)>=17 may be).
This is known as "short-circuit" evaluation...bu t it requires *both* operands to be true.
In your code, that is not alsways the case.
Juan T. Llibre, asp.net MVP
asp.net faq : http://asp.net.do/faq/
foros de asp.net, en español : http://asp.net.do/foros/
============== =============== =========
<bb****@yahoo. comwrote in message
news:11******* **************@ e9g2000prf.goog legroups.com...
It says invalid expression term &&
protected void GridView1_RowDa taBound(object sender,
GridViewRowEven tArgs e)
{
if
((Convert.ToInt 32(e.Row.Cells[2].Text)>=15))&&( Convert.ToInt32 (e.Row.Cells[2].Text)>=17);
{
e.Row.Cells[0].CssClass = "sdgStatusOrang e";
}
It says invalid expression term &&
Juan,
Come on, i can't see any logical exlanation in changing && operator to & for
this case :-). First of all, logically, his "if" statement could be
simplified changed to:
if (Convert.ToInt3 2(e.Row.Cells[2].Text) >= 17)
{
e.Row.Cells[0].CssClass = "sdgStatusOrang e";
}
simply because the only numbers that meet both criteria are >= 17. Second,
if the first operand (Convert.ToInt3 2(e.Row.Cells[2].Text) >= 15) would
return false, second could not be true (logically). Please also note he used
&& therefore there is not point to test the second operand as you're trying
to point out. Third, it was definitely compiler error (syntax error) which
has nothing to do with runtime evaluation.
Take it easy mate ;-)
Best regards
--
Milosz
"Juan T. Llibre" wrote:
re:
!Did you mean if the text in cell equals "14"
Yes.
re:
!then statement inside is not going to be reached, simply because the first
!condition is false, and short-circuit evaluation for && operator skips the second operand.
That's exactly what I explained...and that's an undesirable "feature".
That's why he needs to change the operator.
re:
!I understand your confusion
There's no confusion.
He should change both the parens *and* the operator,
the first as you suggest; the second as I suggest.
Doing that will cover all the bases for him.
Juan T. Llibre, asp.net MVP
asp.net faq : http://asp.net.do/faq/
foros de asp.net, en español : http://asp.net.do/foros/
=============== =============== ========
"Milosz Skalecki [MCAD]" <mi*****@DONTLI KESPAMwp.plwrot e in message
news:71******** *************** ***********@mic rosoft.com...
Good morning Juan
Did you mean if the text in cell equals "14"
if (
(Convert.ToInt3 2(e.Row.Cells[2].Text) >= 15) &&
(Convert.ToInt3 2(e.Row.Cells[2].Text) >= 17))
{
e.Row.Cells[0].CssClass = "sdgStatusOrang e";
}
then statement inside is not going to be reached, simply because the first
condition is false, and short-circuit evaluation for && operator skips the
second operand. I understand your confusion as I have seen this guy's
previous post, but in this case it was just misplaced parentheses ;-)
--
Milosz
"Juan T. Llibre" wrote:
Hi, Milosz,
In that case, what happens if Convert.ToInt32 (e.Row.Cells[2].Text = 14) ?
Juan T. Llibre, asp.net MVP
asp.net faq : http://asp.net.do/faq/
foros de asp.net, en español : http://asp.net.do/foros/
=============== =============== ========
"Milosz Skalecki [MCAD]" <mi*****@DONTLI KESPAMwp.plwrot e in message
news:85******** *************** ***********@mic rosoft.com...
Hi Juan,
In this case, "invalid expression term &&" is caused definitely by misplaced
parentheses, because it is a compiler message ;-) (evaluation would be done
at the runtime). Second, bitwise and & operator will give the same result
(apart from the fact short-circuit is not apllicable) because true & true =
true, false & true = false, false & false = false. Therefore, it should be
corrected to:
if (
(Convert.ToInt3 2(e.Row.Cells[2].Text) >= 15) &&
(Convert.ToInt3 2(e.Row.Cells[2].Text) >= 17))
{
e.Row.Cells[0].CssClass = "sdgStatusOrang e";
}
Best regards
--
Milosz
"Juan T. Llibre" wrote:
re:
((Convert.ToInt 32(e.Row.Cells[2].Text)>=15))&&( Convert.ToInt32 (e.Row.Cells[2].Text)>=17);
You need to use the "regular" AND operator.
Try :
((Convert.ToInt 32(e.Row.Cells[2].Text)>=15))&(C onvert.ToInt32( e.Row.Cells[2].Text)>=17);
If you use && and e.Row.Cells[2].Text)>=15 is false, e.Row.Cells[2].Text)>=17
is not evaluated (because the result of the AND operation is false no matter what the
value of e.Row.Cells[2].Text)>=17 may be).
This is known as "short-circuit" evaluation...bu t it requires *both* operands to be true.
In your code, that is not alsways the case.
Juan T. Llibre, asp.net MVP
asp.net faq : http://asp.net.do/faq/
foros de asp.net, en español : http://asp.net.do/foros/
=============== =============== ========
<bb****@yahoo.c omwrote in message
news:11******** *************@e 9g2000prf.googl egroups.com...
It says invalid expression term &&
protected void GridView1_RowDa taBound(object sender,
GridViewRowEven tArgs e)
{
if
((Convert.ToInt 32(e.Row.Cells[2].Text)>=15))&&( Convert.ToInt32 (e.Row.Cells[2].Text)>=17);
{
e.Row.Cells[0].CssClass = "sdgStatusOrang e";
}
It says invalid expression term &&
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A Windows Forms form does not have the event Unload, like VB6. What one acts like?
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by: muto222 |
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How can i add a mobile payment intergratation into php mysql website.
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by: bsmnconsultancy |
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In today's digital era, a well-designed website is crucial for businesses looking to succeed. Whether you're a small business owner or a large corporation in Toronto, having a strong online presence can significantly impact your brand's success. BSMN Consultancy, a leader in Website Development in Toronto offers valuable insights into creating effective websites that not only look great but also perform exceptionally well. In this comprehensive...
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