hey gang.
I have a code to create a random string of letters. The number of them can
be whatever I desire.
what i would like to do, is have it both letters and integers. how would i
modify this code to allow that.
'***** make random password ******
Sub StrRandomize(st rSeed)
Dim i, nSeed
nSeed = CLng(0)
For i = 1 To Len(strSeed)
nSeed = nSeed Xor ((256 * ((i - 1) Mod 4) * AscB(Mid(strSee d, i, 1))))
Next
Randomize nSeed
End Sub
'----------
Function GeneratePasswor d(nLength)
Dim i, bMadeConsonant, c, nRnd
Const strDoubleConson ants = "bdfglmnpst "
Const strConsonants = "bcdfghklmnpqrs tv"
Const strVocal = "aeiou"
GeneratePasswor d = ""
bMadeConsonant = False
For i = 0 To nLength
nRnd = Rnd
If GeneratePasswor d <"" AND _
(bMadeConsonant <True) AND (nRnd < 0.15) Then
c = Mid(strDoubleCo nsonants, Len(strDoubleCo nsonants) * Rnd + 1, 1)
c = c & c
i = i + 1
bMadeConsonant = True
Else
If (bMadeConsonant <True) And (nRnd < 0.95) Then
c = Mid(strConsonan ts, Len(strConsonan ts) * Rnd + 1, 1)
bMadeConsonant = True
Else
c = Mid(strVocal, Len(strVocal) * Rnd + 1, 1)
bMadeConsonant = False
End If
End If
GeneratePasswor d = GeneratePasswor d & c
Next
If Len(GeneratePas sword nLength) Then
GeneratePasswor d = Left(GeneratePa ssword, nLength)
End If
End Function
'----------
StrRandomize CStr(Now) & CStr(Rnd)
var_var = GeneratePasswor d(6)
'************** *************** *********
this gives me 6 letters at random.
for example utjand
i would like it to give say 3 letters and 3 numbers. is this possible with
the code i have?
TIA
Bam
1  3152 
scratch that. one of these days I will learn to just think!!
just added 1234567890 in the Const strConsonants = "bcdfghklmnpqrs tv"
line, all is well
thanks
"Jeff" <ba*@gig-gamers.comwrote in message
news:46******** *************** @roadrunner.com ...
hey gang.
I have a code to create a random string of letters. The number of them can
be whatever I desire.
what i would like to do, is have it both letters and integers. how would i
modify this code to allow that.
'***** make random password ******
Sub StrRandomize(st rSeed)
Dim i, nSeed
nSeed = CLng(0)
For i = 1 To Len(strSeed)
nSeed = nSeed Xor ((256 * ((i - 1) Mod 4) * AscB(Mid(strSee d, i, 1))))
Next
Randomize nSeed
End Sub
'----------
Function GeneratePasswor d(nLength)
Dim i, bMadeConsonant, c, nRnd
Const strDoubleConson ants = "bdfglmnpst "
Const strConsonants = "bcdfghklmnpqrs tv"
Const strVocal = "aeiou"
GeneratePasswor d = ""
bMadeConsonant = False
For i = 0 To nLength
nRnd = Rnd
If GeneratePasswor d <"" AND _
(bMadeConsonant <True) AND (nRnd < 0.15) Then
c = Mid(strDoubleCo nsonants, Len(strDoubleCo nsonants) * Rnd + 1, 1)
c = c & c
i = i + 1
bMadeConsonant = True
Else
If (bMadeConsonant <True) And (nRnd < 0.95) Then
c = Mid(strConsonan ts, Len(strConsonan ts) * Rnd + 1, 1)
bMadeConsonant = True
Else
c = Mid(strVocal, Len(strVocal) * Rnd + 1, 1)
bMadeConsonant = False
End If
End If
GeneratePasswor d = GeneratePasswor d & c
Next
If Len(GeneratePas sword nLength) Then
GeneratePasswor d = Left(GeneratePa ssword, nLength)
End If
End Function
'----------
StrRandomize CStr(Now) & CStr(Rnd)
var_var = GeneratePasswor d(6)
'************** *************** *********
this gives me 6 letters at random.
for example utjand
i would like it to give say 3 letters and 3 numbers. is this possible with
the code i have?
TIA
Bam
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