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Create a Query that provides a running total but grouped?

8 New Member
I need to create a query that produces running totals for every group within my table for example i wish to see: -

Group A

[running total] 1
[running total] 5
[running total] 9
[running total] 15

Group B

[running total] 1
[running total] 2
[running total] 20

etc..

I have worked out how to produce a running total but this will produce it for all records in the table and not split it (or reset it when it find a new group). Also this method works on the Unique ID which will fail due to the grouping required.
Sep 26 '06 #1
16 11320
PEB
1,418 Recognized Expert Top Contributor
Hi,

Try to do a query that do the sum by your wanted groups and make Union query with your not aggregate query

:)
Sep 26 '06 #2
Gandalf186
8 New Member
Thanks for that, I think I understand what you mean!!

But if I sum by group and then run a query on the results, won't that just give me the running total of the groups?

I am looking to list all records by group with all the fields in each group showing a running total. After I have achieved that I only want to see records in ech group that reach a certain value.


Thanks again
Sep 26 '06 #3
PEB
1,418 Recognized Expert Top Contributor
You mention that u've done the running total! How did you do it?

Maybe we can integrate sth with this?

:)
Sep 26 '06 #4
Gandalf186
8 New Member
I used a sql query to create an alias and then compared ID with ID : -

SELECT tbl_Alias.group s, tbl_Alias.id AS Expr1, (SELECT Sum([table3].[totals]) AS Total
FROM [table3]
WHERE ((([table3].[ID])<=[tbl_alias].[ID]));) AS [Running Total], tbl_Alias.total s
FROM table3 AS tbl_Alias, Table3
GROUP BY tbl_Alias.group s, tbl_Alias.id, tbl_Alias.total s;

This wirks by creating a running total based on my unique ID field however I need to do this on the records within each group.

Any Ideas??
Sep 26 '06 #5
PEB
1,418 Recognized Expert Top Contributor
So it seems to be reachable using VB functions and a temporary table to store the results! This is the way that I see!

Do u want to proceed in this direction?
Sep 26 '06 #6
Gandalf186
8 New Member
I will be using the results as a transfer to MS Excel (the only reason I am using Access is because of the amount of rows required (over 65000 records). I will be happy to use any method avaliable.
Sep 26 '06 #7
PEB
1,418 Recognized Expert Top Contributor
So this have to be pasted into a module in Access:

Expand|Select|Wrap|Line Numbers
  1. Global last_criteria
  2. Global last_used
  3.  
  4. Function Set_last(Values, criterias)
  5. last_criteria = nts(criterias)
  6. last_used = nts(Values)
  7. Set_last = last_used
  8. End Function
  9.  
  10. Function show_last(Ref)
  11. 'Stop
  12. show_last = last_used
  13. End Function
  14. Function show_last_criteria(Ref)
  15. show_last_criteria = last_criteria
  16. End Function
  17.  
For running sum for a Group your column should be:
Run_sum: IIF(show_last_c riteria([Group_Name])=[Group_Name],Set_last(val(s how_last([Group_Name]))+ [myvalues],[Group_Name]),Set_last([myvalues], [Group_Name]))


So you need to change in this expression:
[Group_Name] with the name of the field that contains your groups
And
[myvalues] with the Field on which you are running sum

From query choose make table query and give the name of the table in which will be stored the result!

Than choose Run and open the respective table!

:)
Sep 26 '06 #8
Gandalf186
8 New Member
Thanks for the script, however I am getting a sub or function not defined.. with the nts highlighted??
Sep 26 '06 #9
Gandalf186
8 New Member
I have removed the nts references so now it looks like: -

Function Set_last(Values , criterias)
last_criteria = criterias
last_used = Values
Set_last = last_used
End Function

the code runs okay but my resulting table is duplicating the running sum?

i.e.

id totals Run_sum groups
1 0.2 0.4 group1 (added 0.4 instead of 0.2)
2 0.2 0.8 group1 (added 0.4 instead of 0.2)
3 0.5 1.8 group1 (added 1.0 instead of 0.5)
4 0.7 3.2 group1 etc...
5 0.8 4.8 group1
6 0.2 5.2 group1
7 0.5 6.2 group1
8 0.1 0.2 group2
9 0.1 0.4 group2
10 0.1 0.6 group2
11 0.1 0.8 group2
12 0.1 1 group2
13 0.1 1.2 group2
Sep 26 '06 #10

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