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[Access 2002] InStr problem

6 New Member
Hi,

I'm banging my head against the desk because I can't find a solution for the following simple problem.

Case: There is a column in a table that has FamilyName and FirstName(s) in one field. ie "McCarthy,J ohn Doe Willy". I have to split up Familyname and the 1st FirstName. The FamilyName works perfect, just looking up the comma with InStr and use Left().
Now can someone throw me a bone to help me get the 1st Firstname. "John" according to the example.

This is what I got but I think InStr function doesn't work properly. I thought the 3 parameters were InStr(placetost artlooking, [field],'SearchString' )

Expand|Select|Wrap|Line Numbers
  1. SELECT 
  2. Naam_en_voornamen, 
  3. Left([naam_en_voornamen],InStr(1,[naam_en_voornamen],',')-1) AS Naam, 
  4. InStr([naam_en_voornamen],',')+1 AS Start, 
  5. InStr(9,[naam_en_voornamen],'a') AS stop, 
  6. Mid([naam_en_voornamen],[start],[stop]) AS Voornaam
  7. FROM tbl_kankerpreventie;
  8.  
Sep 21 '06 #1
4 3912
MMcCarthy
14,534 Recognized Expert Moderator MVP
Try this:

Expand|Select|Wrap|Line Numbers
  1.  
  2. SELECT Naam_en_voornamen, 
  3. Left([naam_en_voornamen],InStr(1,[naam_en_voornamen],',')-1) AS Naam, 
  4. Right([naam_en_voornamen],(Len([naam_en_voornamen])-InStr(1,[naam_en_voornamen],',')+1)) AS Voornaam
  5. FROM tbl_kankerpreventie;
  6.  
  7.  
Sep 21 '06 #2
fischerspooner
6 New Member
Thanks for the response but that's the same result I get.

This is what I want to achieve:
Expand|Select|Wrap|Line Numbers
  1. "Naam_en_voornamen"      | "Naam"     | "Voornaam"
  2. ----------------------------------------------------
  3. McCarthy,John Doe Willy  | McCarthy   | John
  4.  
So it has to drop the "Doe Willy". Locating the first "space" between John Doe is not the problem it's getting out the John ;-)
Sep 22 '06 #3
PEB
1,418 Recognized Expert Top Contributor
Hi,

try;

Expand|Select|Wrap|Line Numbers
  1. SELECT 
  2. Naam_en_voornamen, 
  3. Left([naam_en_voornamen],InStr(1,[naam_en_voornamen],',')-1) AS Naam, 
  4. Mid([naam_en_voornamen],InStr([naam_en_voornamen],',')+1,InStr(1,[naam_en_voornamen]," ")-InStr([naam_en_voornamen],',')-1) AS Voornaam
  5. FROM tbl_kankerpreventie;
  6.  
  7.  
:)
Sep 22 '06 #4
fischerspooner
6 New Member
Works like a charm, I owe you :)
Sep 22 '06 #5

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