Help..please!
I'm a rookie in terms of VB, but I'm desperately trying to make Access
count the number of days between two dates and then subtract the
weekends. Can anyone tell me what is wrong with the follwing code:
Option Compare Database
Public Function WorkingDays(Sta rtDate As Date, EndDate As Date) As
Integer
On Error GoTo Err_WorkingDays
Dim intCountA As Integer
If StartDate Is Empty Then
intCountA = 0
Else
intCountA = 0
Do While StartDate <= EndDate
Select Case Weekday(StartDa te)
Case Is = 1, 7
intCountA = intCountA
Case Is = 2, 3, 4, 5, 6
intCountA = intCountA + 1
End Select
StartDate = StartDate + 1
Loop
WorkingDays = intCountA
Exit_WorkingDay s:
Exit Function
Err_WorkingDays :
Select Case Err
Case Else
MsgBox Err.Description
Resume Exit_WorkingDay s
End Select
End Function 2 2208
I haven't tried to analyze your code, but it apparently doesn't take
holidays into account. A solution I've used includes generating an
array for dates -20 to +20 years from today leaving weekends and
holidays out. I'll share the code if you write to bi***@gci.net,
although it may take a few hours for me to extract it for you.
On 27 Feb 2006 06:05:46 -0800, "Jannick"
<ja************ ***********@hot mail.com> wrote: Help..please !
I'm a rookie in terms of VB, but I'm desperately trying to make Access count the number of days between two dates and then subtract the weekends. Can anyone tell me what is wrong with the follwing code:
Option Compare Database
Public Function WorkingDays(Sta rtDate As Date, EndDate As Date) As Integer
On Error GoTo Err_WorkingDays
Dim intCountA As Integer
If StartDate Is Empty Then intCountA = 0 Else
intCountA = 0 Do While StartDate <= EndDate Select Case Weekday(StartDa te) Case Is = 1, 7 intCountA = intCountA Case Is = 2, 3, 4, 5, 6 intCountA = intCountA + 1 End Select StartDate = StartDate + 1 Loop
WorkingDays = intCountA
Exit_WorkingDa ys: Exit Function
Err_WorkingDay s: Select Case Err
Case Else MsgBox Err.Description Resume Exit_WorkingDay s End Select
End Function
OTTOMH
Only variants can be empty;
An EndIf is missing;
The function counts the day started, so it may not actually return the
weekdays between (I think if one inputs a Sunday and the next Saturday
as parameters one gets 6 weekdays);
The Select Case in the Err_Working Days does nothing.
I encourage you to write your own code, and will resist the temptation
to post a function of my own. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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last post by:
Good morning, C++ers,
A couple days ago i came across a useful trick for counting instances of a
given class, and i thought i'd pass it on:
Conventionally, as described in several books, to do instance counting we
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/**
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I'm looking for a script that, instead of counting down, can "count up"
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Thanks in advance.
Yours,
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I have tried using the following code to count the specific number of
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Public Function HowManySpecificDays(StartDate As Date, EndDate As
Date) As DayCounts
and specifically the word "DayCounts"
Can anyone help?
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by: William Stacey [MVP] |
last post by:
Here is the link. If you find an issue or think of a feature, please post a
reply or send an email. Cheers!
http://www.mvptools.com/doco/csharp/semaphoredjikstra.htm
--
William Stacey, MVP
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Please consider the following class (it's not really my class, but it's
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class Vector {
int myN;
double *myX;
Vector(int n) : myN(n), myX(new double) { }
double &operator()(int i) { return myX; }
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