If I run this...
For i = -1 To -12 Step -1
Debug.Print CStr(Month(Date Add("m", i, Now))) & "/";
CStr(Year(DateA dd("m", i, Now)))
Next i
I get this...
5/2005
4/2005
3/2005
2/2005
1/2005
12/2004
11/2004
10/2004
9/2004
8/2004
7/2004
6/2004
which is exactly what I want, except for one thing -
I would like to see month abbrev replace the numbers.
So, I run this...
For i = -1 To -12 Step -1
Debug.Print Format(Month(Da teAdd("m", i, Now)), "mmm") & "/";
CStr(Year(DateA dd("m", i, Now)))
Next i
But, unfortunately, it returns this...
Jan/2005
Jan/2005
Jan/2005
Jan/2005
Dec/2005
Jan/2004
Jan/2004
Jan/2004
Jan/2004
Jan/2004
Jan/2004
Jan/2004
Am I missing something here?
2  1227 
"MLH" <CR**@NorthStat e.net> wrote in message
news:di******** *************** *********@4ax.c om...
[snip] I would like to see month abbrev replace the numbers.
So, I run this...
For i = -1 To -12 Step -1
Debug.Print Format(Month(Da teAdd("m", i, Now)), "mmm") & "/";
CStr(Year(DateA dd("m", i, Now)))
Next i
But, unfortunately, it returns this...
Jan/2005
Jan/2005
Jan/2005
Jan/2005
Dec/2005
Jan/2004
Jan/2004
Jan/2004
Jan/2004
Jan/2004
Jan/2004
Jan/2004
Am I missing something here?
Yes, the expression...
Format(Month(Da teAdd("m", i, Now)), "mmm")
....is incorrect because to format something as "mmm" you must provide a first
argument that is a date and the Month() function returns an integer. Since
dates are actually Doubles under the covers you are actually asking to format a
date that occurs in the first 12 days of the year 1900. Just remove the Month()
function from your expression and it should work.
Actually all you need is...
Format(DateAdd( "m", i, Now), "mmm/yyyy")
--
I don't check the Email account attached
to this message. Send instead to...
RBrandt at Hunter dot com
Many thx, Rick. That was certainly my problem.
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