hi all,
I am really do not know how to get this. Tried all types of queries.
The requirement is as below
itemid maxqty Mdate (date is when the max qty went out)
001 5 5/1/2004
002 2 5/10/2004
The actual table has all transaction data as below.
itemid qty date
001 5 5/1/2004
001 3 5/2/2004
001 3 5/3/2004
001 2 5/4/2004
002 0 5/1/2004
......
002 2 5/10/2004
one query is
select itemid,max(qty) from mTran
with the above require which date it occurred.
Please help
Cap2010 2 1299
Try this.....theres a good chance its horribly wrong though :)
select itemId, dateStamp, nz(select max(qty) from mtrans as m1 where
m1.itemId=m2.it emId group by itemId),0)
from mtrans as m2
John
"captain" <ca**********@y ahoo.com> wrote in message
news:27******** *************** ***@posting.goo gle.com... hi all,
I am really do not know how to get this. Tried all types of queries. The requirement is as below
itemid maxqty Mdate (date is when the max qty went out) 001 5 5/1/2004 002 2 5/10/2004
The actual table has all transaction data as below. itemid qty date 001 5 5/1/2004 001 3 5/2/2004 001 3 5/3/2004 001 2 5/4/2004 002 0 5/1/2004 ..... 002 2 5/10/2004
one query is select itemid,max(qty) from mTran
with the above require which date it occurred.
Please help
Cap2010 ca**********@ya hoo.com (captain) wrote in message news:<27******* *************** ****@posting.go ogle.com>... hi all,
I am really do not know how to get this. Tried all types of queries. The requirement is as below
itemid maxqty Mdate (date is when the max qty went out) 001 5 5/1/2004 002 2 5/10/2004
The actual table has all transaction data as below. itemid qty date 001 5 5/1/2004 001 3 5/2/2004 001 3 5/3/2004 001 2 5/4/2004 002 0 5/1/2004 ..... 002 2 5/10/2004
one query is select itemid,max(qty) from mTran
with the above require which date it occurred.
Please help
Cap2010
Try:
SELECT itemid, qty AS maxqty, DateStamp AS Mdate FROM mtrans WHERE qty
IN (SELECT Max(qty) AS MaxQty from mtrans AS mt where mt.itemid =
mtrans.itemid);
Of course, only use this query if the other poster's answer is
horribly wrong :-).
James A. Fortune This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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