Hi there:
I know this probably is a very easy thing to do in python, but i wanted
to compare 2 lists and generate a new list that does not copy similar
entries. An example below
list= ["apple", "banana", "grape"]
list2=["orange","banana", "pear"]
now I want to compare these lits and generate a third list after
comparison
list3 would be ["apple", "banana","grape","orange", "pear"]
hence the double entry would not show up?
Is there a way to do this??
Stephen 7 1657
[Stephen]
[...] compare 2 lists and generate a new list that does not copy similar
entries. An example below
list= ["apple", "banana", "grape"]
list2=["orange","banana", "pear"]
now I want to compare these lits and generate a third list after
comparison
list3 would be ["apple", "banana","grape","orange", "pear"]
Use sets:
>>from sets import Set as set # For compatibility with Python 2.3 one = ["apple", "banana", "grape"] two = ["orange","banana", "pear"] print list(set(one) | set(two))
['grape', 'apple', 'orange', 'pear', 'banana']
--
Richie Hindle ri****@entrian.com
OriginalBrownster wrote:
Hi there:
I know this probably is a very easy thing to do in python, but i wanted
to compare 2 lists and generate a new list that does not copy similar
entries. An example below
list= ["apple", "banana", "grape"]
list2=["orange","banana", "pear"]
now I want to compare these lits and generate a third list after
comparison
list3 would be ["apple", "banana","grape","orange", "pear"]
hence the double entry would not show up?
Is there a way to do this??
Stephen
How about :
list3 = list1 + [item for item in list2 if item not in list1]
print list3:
['apple', 'banana', 'grape', 'orange', 'pear']
OriginalBrownster wrote:
Hi there:
I know this probably is a very easy thing to do in python, but i wanted
to compare 2 lists and generate a new list that does not copy similar
entries. An example below
list= ["apple", "banana", "grape"]
list2=["orange","banana", "pear"]
now I want to compare these lits and generate a third list after
comparison
list3 would be ["apple", "banana","grape","orange", "pear"]
hence the double entry would not show up?
Is there a way to do this??
Stephen
How about :
list3 = list1 + [item for item in list2 if item not in list1]
print list3:
['apple', 'banana', 'grape', 'orange', 'pear']
"OriginalBrownster" <or***************@gmail.comwrote in message
news:11********************@74g2000cwt.googlegroup s.com...
I know this probably is a very easy thing to do in python, but i wanted
to compare 2 lists and generate a new list that does not copy similar
entries. An example below
list= ["apple", "banana", "grape"]
list2=["orange","banana", "pear"]
Other people have already posted solutions but I'll add a couple of
comments:
1. Avoid calling lists 'list', you will break the list built-in function.
2. You don't specify whether the lists are ordered. If there is no
significance to the order of the items, it may be more appropriate
to use sets throughout. Then the answer is just: set3 = set1 | set2.
Richie Hindle schrieb:
[Stephen]
>>[...] compare 2 lists and generate a new list that does not copy similar entries. An example below
list= ["apple", "banana", "grape"] list2=["orange","banana", "pear"]
now I want to compare these lits and generate a third list after comparison
list3 would be ["apple", "banana","grape","orange", "pear"]
Use sets:
>>>>from sets import Set as set # For compatibility with Python 2.3 one = ["apple", "banana", "grape"] two = ["orange","banana", "pear"] print list(set(one) | set(two))
['grape', 'apple', 'orange', 'pear', 'banana']
Why using Set two times, when you can do it with one call?
>>list(set(one + two))
According to my benchmarks, this was five times faster than calling it
twice and use |.
There are also a few more good approaches uniquifying lists at http://www.peterbe.com/plog/uniqifiers-benchmark
Regards,
Stargaming th*********@gmail.com wrote:
OriginalBrownster wrote:
Hi there:
I know this probably is a very easy thing to do in python, but i wanted
to compare 2 lists and generate a new list that does not copy similar
entries. An example below
list= ["apple", "banana", "grape"]
list2=["orange","banana", "pear"]
now I want to compare these lits and generate a third list after
comparison
list3 would be ["apple", "banana","grape","orange", "pear"]
hence the double entry would not show up?
Is there a way to do this??
Stephen
How about:
list3 = list1 + [item for item in list2 if item not in list1]
print list3:
['apple', 'banana', 'grape', 'orange', 'pear']
It works with the data given, but if list1 contains duplicates...
- Pad
OriginalBrownster wrote:
Hi there:
I know this probably is a very easy thing to do in python, but i wanted
to compare 2 lists and generate a new list that does not copy similar
entries. An example below
list= ["apple", "banana", "grape"]
list2=["orange","banana", "pear"]
now I want to compare these lits and generate a third list after
comparison
list3 would be ["apple", "banana","grape","orange", "pear"]
hence the double entry would not show up?
Is there a way to do this??
Stephen
This solution uses sets; removes all duplicates and is order
preserving.
Remove the outer sorted wrapper if the order need not be preserved.
>>lst= ["apple", "banana", "grape"] lst2=["orange","banana", "pear"] lst3= lst+lst2 sorted([x for x in set(lst3)], key = lambda x: lst3.index(x))
['apple', 'banana', 'grape', 'orange', 'pear']
>>>
- Paddy This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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