Must all parent node have the same types of childs?

8,658

Recognized Expert Moderator Expert

it is valid in the sense as it follows the XML base rules (given that you use UTF-8).

for stricter validaty, you’d need a DTD or Schema (XSD or RelaxNG)

Apr 1 '11 #2

New Member

aside from the DTD/UTF-8 because everything I have seen up to now sticks with the same childs in every parent node with the same name, is there some downside/disadvantange with this logic?
(When extracting data in my for loop I plan to use a simple if to see wheather the <url> child exists or not in each parent)

Apr 1 '11 #3

8,658

Recognized Expert Moderator Expert

I think it’s a matter of personal preference. if you want only the URLs, use XPath or getElementsByTagName().

Apr 1 '11 #4

New Member

All the job will be done with JS. Know any good tutorial?
(Also for reading an xml file, the only option is AJAX? Because the point of the whole thing is to make an application which works offline on the browser-thus the javascript)

Apr 2 '11 #5

8,658

Recognized Expert Moderator Expert

without help of a server side script, AJAX is the only option in mind for reading XML in a HTML page.

Apr 3 '11 #6

New Member

following the original problem I need to check wheather a parent node has a child node <data> (some will and some will not) trying

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if (typeof(x[i].getElementsByTagName("data")[0].childNodes[0].nodeValue)== "undefined")  

  data='none';

  else

  data=x[i].getElementsByTagName("data")[0].childNodes[0].nodeValue;

where x[i] the current parent element within the loop but still get an error that x[i].getElementsByTagName("data")[0].childNodes[0].nodeValue is undefined, note that if the parent has this node everything is works ok, so x[i].getElementsByTagName("data")[0].childNodes[0].nodeValue gets the value if it finds it, any ideas?

Apr 4 '11 #7

8,658

Recognized Expert Moderator Expert

check the length of the getElementsByTagName() list. childNodes[0].nodeValue is undefined if there is either no child node (empty tag) or no parent node (no parent, no child)

Apr 4 '11 #8

New Member

worked well, with this I can check the existance of data. The other think I want to do is check the overall xml file for syntax errors. Because a admin will upload it, say he deleted a '<' when changing and now a node is not closed properly do you now any way to check it?

Apr 5 '11 #9

8,658

Recognized Expert Moderator Expert

invalid XML doesn’t load.

Apr 5 '11 #10

getting parent node using XLST

New Member

found this from w3schools and seems to work, will dig to see how it is done.
P.S. You load the xml with the way shown below or with AJAX like any other data like this ?

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function loadXMLDoc(dname)

{

if (window.XMLHttpRequest)

  {

  xhttp=new XMLHttpRequest();

  }

else

  {

  xhttp=new ActiveXObject("Microsoft.XMLHTTP");

  }

xhttp.open("GET",dname,false);

xhttp.send();

return xhttp.responseXML;

}

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<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<html lang="en-US" xml:lang="en-US" xmlns="http://www.w3.org/1999/xhtml">

<head>

<title>DOM Tutorial - Validate XML</title>

</head>

<body>
 
<script language="JavaScript" type="text/javascript">

document.write("<h2>Result of Validating: http://www.w3schools.com/dom/cd_catalog.xml</h2>");

// code for IE

if (window.ActiveXObject)

{

var xmlDoc = new ActiveXObject("Microsoft.XMLDOM");

xmlDoc.async="false";

xmlDoc.validateOnParse="true";

xmlDoc.load("http://www.w3schools.com/dom/cd_catalog.xml");
 
if (xmlDoc.parseError.errorCode == 0) 

  {

  document.write("The file <b>http://www.w3schools.com/dom/cd_catalog.xml</b><br />Validated Successfully without Errors");

  }

else

  {

  document.write("<code>");

  document.write("Error in line " + xmlDoc.parseError.line + " position " + xmlDoc.parseError.linePos);

  document.write("<br /><br />");
 
  document.write("Error Code: " + xmlDoc.parseError.errorCode);

  document.write("<br /><br />");
 
  document.write("Error Reason: " + xmlDoc.parseError.reason);

  document.write("</code>");
 
  document.write("<xmp>");

  document.write("Error Line: " + xmlDoc.parseError.srcText);

  document.write("</xmp>");

  }

}

// code for Mozilla, Firefox, Opera, etc.

else if (document.implementation && document.implementation.createDocument)

{

xmlDoc=document.implementation.createDocument("","",null);

xmlDoc.async=false;

xmlDoc.load("http://www.w3schools.com/dom/cd_catalog.xml");
 
if (xmlDoc.documentElement.nodeName=="parsererror")

  {

  document.write(xmlDoc.documentElement.childNodes[0].nodeValue);

  }

else

  {

  document.write("XML is valid");

  }

}

else

{

document.write('Your browser cannot handle this script');

}

</script>
 
</body>

</html>

Apr 5 '11 #11

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