hello all,
In XSL what would be the easiest way to remove only the <information> element of my xml file, but at the same time keeping the child elements and its contents?
Source xml file:
<envelope>
<body>
<information>
<lang>en</lang>
</information>
</body>
</envelope>
Wished transformed xml file:
<envelope>
<body>
<lang>...
</body>
</envelope>
I've managed to do it using xsl:variable with xsl:copy-of select but the problem is that I need to rewrite the tags above <information> manually in my <xsl:template > in order for them to appear. I wonder if there is an easiest way such as making a direct string replacement of the node itself such as in other programming langues (sth like a {xml document}.repla ceAll('<informa tion>', ' '), {xml document}.repla ceAll('</information>',' '). Is this possible with XSL?
Thanks,
James
2  3433  jkmyoung 2,057
Recognized Expert Top Contributor
Starting with the copy template: -
<?xml version="1.0" encoding="UTF-8"?>
-
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format">
-
<xsl:template match="*">
-
<xsl:copy>
-
<xsl:copy-of select="@*"/>
-
<xsl:apply-templates/>
-
</xsl:copy>
-
</xsl:template>
-
</xsl:stylesheet>
-
We make a special rule for information, where we don't copy the node. -
<xsl:template match="information">
-
<xsl:apply-templates/>
-
</xsl:template>
-
Oh well, you really made my day, thank you! Pretty tricky though, to have a <xsl:copy-of> inside a <xsl:copy>...
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