Error Handling/Trapping Question

[JodiPhillips]

Hello again,

Its been a while since I've asked a question, I've been learning steadily reading the How To's and the questions in this forum, as well as reading my Access VBA and Access bibles till they are now in tatters!.

I'm stuck with understanding the error handling process by VB6.5 (in particular for MSAccess 2003).

The following code is a test code only, so that I could understand things before I go on to something more meaty. It is probably the 5th incarnation or attempt and as you can see I have resorted to If..Then..Else and a SubFunction to try and handle this type of error. The error I'm referring to is the nasy Err 13 Data Type Mismatch error which occurs when I deliberately enter a non numeric character in the text box on the form. (The from has one command button and one text box)

Sub Command0_Click()
 
            Dim aNumberbox As Double
        Dim NotANumber As Variant
                        aNumberbox = 0
           NotANumber = CVErr(13)
 
     aNumberbox = CheckData(Me.Text1)
 
      If IsError(aNumberbox) Then
         Select Case aNumberbox
                Case NotANumber
               MsgBox "Error: not a number."
            Case Else
               MsgBox "Unknown Error."
         End Select
      Else
      aNumberbox = Me.Text1
          MsgBox ("You entered the number " & aNumberbox)
          MsgBox ("Why not try it again?")
      End If
   End Sub
 
   Function CheckData(aNumberbox As Integer) As Integer
     Dim NotANumber As Integer
 
      If Not IsNumeric(aNumberbox) Then
         CheckData = NotANumber
            End If
   End Function

Despite trying to handle the error with a very simple error handle subroutine in my previous attempt:

Sub Command0_Click()
 
Dim aNumber As Double
On Error GoTo ErrorHandle
 
aNumber = CDbl(Me.Text1)
ExitHere:
  MsgBox ("You entered the number " & aNumber)
 MsgBox ("Why not try it again?")
 
 
ErrorHandle:
  MsgBox ("Please enter a number.")
  Resume ExitHere
End Sub
 

No matter what I do the Built-In Error Message (as unhelpful as they are :P) still occur.

Both sets of code of course break at the "aNumber = CDbl(Me.Text1)" line.

Would really appreciate it if anyone can help with this :)

JP

[anuragshrivastava64]

Sorry but can't get what u want exactly
anyways a dirty solution is here

Sub Command0_Click( )

Dim aNumber As Double
On Error GoTo ErrorHandle

aNumber = CDbl(Me.Text1)
ExitHere:
MsgBox ("You entered the number " & aNumber)
MsgBox ("Why not try it again?")
Me.Text1.SetFoc us
Exit Sub

ErrorHandle:
MsgBox ("Please enter a number.")
Resume ExitHere
End Sub

[JodiPhillips]

Sorry but can't get what u want exactly
anyways a dirty solution is here

Sub Command0_Click( )

Dim aNumber As Double
On Error GoTo ErrorHandle

aNumber = CDbl(Me.Text1)
ExitHere:
MsgBox ("You entered the number " & aNumber)
MsgBox ("Why not try it again?")
Me.Text1.SetFoc us
Exit Sub

ErrorHandle:
MsgBox ("Please enter a number.")
Resume ExitHere
End Sub

Hello anuragshrivasta va

Thank you for your reply.

What I am trying to achieve is to stop the built-in error handling from occuring when the code encounters an error. The variable aNumber is set as a double to capture all digits (both whole and decimal) and the code will work fine with a number entered. However, enter a text character and the built-in error handler returns a type mismatch error, which is expected due to the type of data entered not being numeric.

I'm trying to stop the in-built mismatch error from reporting, and the mismatch error to be handled specifically by the ErrorHandle code block.

Can the mismatch type error be trapped and handled programmaticall y or will I have to respecify the data type of the anumber variable as perhaps a variant? If I have to change the data type to variant I will need to go with something similar to the first code block posted above using If...then...els e (which still doesn't work to stop the in-built error handling).

Thanks again.

JP

[anuragshrivastava64]

Hello anuragshrivasta va

Thank you for your reply.

What I am trying to achieve is to stop the built-in error handling from occuring when the code encounters an error. The variable aNumber is set as a double to capture all digits (both whole and decimal) and the code will work fine with a number entered. However, enter a text character and the built-in error handler returns a type mismatch error, which is expected due to the type of data entered not being numeric.

I'm trying to stop the in-built mismatch error from reporting, and the mismatch error to be handled specifically by the ErrorHandle code block.

Can the mismatch type error be trapped and handled programmaticall y or will I have to respecify the data type of the anumber variable as perhaps a variant? If I have to change the data type to variant I will need to go with something similar to the first code block posted above using If...then...els e (which still doesn't work to stop the in-built error handling).

Thanks again.

JP

Then u can simply check whetetehr the text enterd is numeric or not thru ISNumeric function

Just copy the following spurce of code before u chek

If Not IsNumeric(Me.Te xt1) Then

MsgBox "Sorry wrong entry"
Text1= ""
Text1.setfocus
Else
aNumberbox = CheckData(Me.Te xt1)
End If

[JodiPhillips]

Hello again anuragshrivasta va, :)

Thank you again for replying.

Thanks also for the code tweak. I've probably not asked the question correctly in the first place. I'm actually looking not for an actual solution but an understanding of how to deal with errrors within VB in a very general sense. The code at the top is just a test code to see how the whole error trapping and handling event is carried out, and to show that I have at least tried to do this on my own. I picked the dreaded error 13 data type mismatch to test as it seems to be the one that will most often cause issues if a user doesn't understand or makes an error with data entry. I guess where I've got myself very confused is from the different methodologies of error handling between different versions of VB (2003 - 2005 for instance) and looking at things like C++ etc.

I do appreciate you taking the time to respond and I apologise if I have wasted your time.

[anuragshrivastava64]

I am afraid I can't help u thru the whole exception handler methodology in VB.

Anyways what u can do is to create a new exception handler and may be write the following

ExceptionHandle r:
If Err.Number =13
MsgBox "Please enter the number correctly"
End if

If anything else u want to know please feel free to ask.