the property object

<bm@bm.bm> schrieb

In VB6 there was a property - object. What is the similar property in
.NET I am using a 3rd party COM grid object that requests the object
property of another such object. e;g:

Set grd.ddb = grd1.Object

what is the equivalent of the line above in .NET?

AFAIR, VB6 used an Extender Object, wrapping the actual COM control, so the
Object properpty referred to the real control. There is no extender (and no
need for it) with .NET controls, consequently there is no such property.
--
Armin

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Nov 20 '05 #2

<bm@bm.bm> schrieb

In VB6 there was a property - object. What is the similar property in
.NET I am using a 3rd party COM grid object that requests the object
property of another such object. e;g:

Set grd.ddb = grd1.Object

what is the equivalent of the line above in .NET?

Nov 20 '05 #3

Well how do I do then. The COM control I am using is doing kind of binding
to another COM control and it will not work if I don't perform the
following:
Set grd.ddb = grd1.Object
Any ideas for work around?
Please note this is not a .NET control it is a COM control probably written
in VB6. It is a 3rd party so I cannot simply port it. I don't have the
sources

Please advise

"Armin Zingler" <az*******@freenet.de> wrote in message
news:40***********************@news.freenet.de...

<bm@bm.bm> schrieb
In VB6 there was a property - object. What is the similar property in
.NET I am using a 3rd party COM grid object that requests the object
property of another such object. e;g:

Set grd.ddb = grd1.Object

what is the equivalent of the line above in .NET?
AFAIR, VB6 used an Extender Object, wrapping the actual COM control, so

the Object properpty referred to the real control. There is no extender (and no need for it) with .NET controls, consequently there is no such property.
--
Armin

How to quote and why:
http://www.plig.net/nnq/nquote.html
http://www.netmeister.org/news/learn2quote.html

Nov 20 '05 #4

<bm@bm.bm> schrieb
In VB6 there was a property - object. What is the similar property in
.NET I am using a 3rd party COM grid object that requests the object
property of another such object. e;g:

Set grd.ddb = grd1.Object

what is the equivalent of the line above in .NET?
AFAIR, VB6 used an Extender Object, wrapping the actual COM control, so

the Object properpty referred to the real control. There is no extender (and no need for it) with .NET controls, consequently there is no such property.
--
Armin

How to quote and why:
http://www.plig.net/nnq/nquote.html
http://www.netmeister.org/news/learn2quote.html

Nov 20 '05 #5

<bm@bm.bm> schrieb

Well how do I do then. The COM control I am using is doing kind of
binding to another COM control and it will not work if I don't
perform the following:
Set grd.ddb = grd1.Object
Any ideas for work around?
Please note this is not a .NET control it is a COM control probably
written in VB6. It is a 3rd party so I cannot simply port it. I don't
have the sources

Sorry for answering late. (Had some problems with my PC so I couldn't use
the upgrade wizard that I wanted to use to do some research.)

Ok, I thought you wanted to do the same for a .NET control. Well, I think I
can't help you here.

The documentation contains the changes of the VBControlExtender object -
unfortunatelly without any comment about the object property.

http://msdn.microsoft.com/library/en...asp?frame=true
--
Armin

How to quote and why:
http://www.plig.net/nnq/nquote.html
http://www.netmeister.org/news/learn2quote.html

Nov 20 '05 #6

document property of object?

<bm@bm.bm> schrieb

Well how do I do then. The COM control I am using is doing kind of
binding to another COM control and it will not work if I don't
perform the following:
Set grd.ddb = grd1.Object
Any ideas for work around?
Please note this is not a .NET control it is a COM control probably
written in VB6. It is a 3rd party so I cannot simply port it. I don't
have the sources

Nov 20 '05 #7

Thanks for the effort. I tried with port of VB6 application as well and got
the same results as you. I guess I have to upgrade to a .NET version of the
3rd party control. It costs 500 USD so I will see what I'll do about it.

Thanx again

"Armin Zingler" <az*******@freenet.de> wrote in message
news:40***********************@news.freenet.de...

<bm@bm.bm> schrieb
Well how do I do then. The COM control I am using is doing kind of
binding to another COM control and it will not work if I don't
perform the following:
Set grd.ddb = grd1.Object
Any ideas for work around?
Please note this is not a .NET control it is a COM control probably
written in VB6. It is a 3rd party so I cannot simply port it. I don't
have the sources
Sorry for answering late. (Had some problems with my PC so I couldn't use
the upgrade wizard that I wanted to use to do some research.)

Ok, I thought you wanted to do the same for a .NET control. Well, I think

I can't help you here.

The documentation contains the changes of the VBControlExtender object -
unfortunatelly without any comment about the object property.

http://msdn.microsoft.com/library/en...asp?frame=true

--
Armin

How to quote and why:
http://www.plig.net/nnq/nquote.html
http://www.netmeister.org/news/learn2quote.html

Nov 20 '05 #8

<bm@bm.bm> schrieb
Well how do I do then. The COM control I am using is doing kind of
binding to another COM control and it will not work if I don't
perform the following:
Set grd.ddb = grd1.Object
Any ideas for work around?
Please note this is not a .NET control it is a COM control probably
written in VB6. It is a 3rd party so I cannot simply port it. I don't
have the sources
Sorry for answering late. (Had some problems with my PC so I couldn't use
the upgrade wizard that I wanted to use to do some research.)

Ok, I thought you wanted to do the same for a .NET control. Well, I think

I can't help you here.

The documentation contains the changes of the VBControlExtender object -
unfortunatelly without any comment about the object property.

http://msdn.microsoft.com/library/en...asp?frame=true

--
Armin

How to quote and why:
http://www.plig.net/nnq/nquote.html
http://www.netmeister.org/news/learn2quote.html

Nov 20 '05 #9

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