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How to display "all" the items of listbox?

Hi,
I want to display ALL the items (includes unselected items) of listbox
control. How can i code this? Should i use "for each" or other?

For example:
Assume you have a listbox with 3 items sth like:

Hello
There
Guys

And i want to display them in the same format within a messagebox with
seperated each line(maybe i have to use " + vbnewline"?).

How to do this?

Thanks!
Dec 23 '07 #1
3 11733

"kimiraikko nen" <ki************ *@gmail.comkirj oitti viestissä
news:c2******** *************** ***********@t1g 2000pra.googleg roups.com...
Hi,
I want to display ALL the items (includes unselected items) of listbox
control. How can i code this? Should i use "for each" or other?

For example:
Assume you have a listbox with 3 items sth like:

Hello
There
Guys

And i want to display them in the same format within a messagebox with
seperated each line(maybe i have to use " + vbnewline"?).

How to do this?

Thanks!
ListBox1.Items. Add("1")
ListBox1.Items. Add("2")
ListBox1.Items. Add("3")

Dim buffer As New System.Text.Str ingBuilder
For i As Integer = 0 To ListBox1.Items. Count - 1
buffer.AppendLi ne(ListBox1.Ite ms(i).ToString)
Next
MsgBox(buffer.T oString)

-Teemu

Dec 23 '07 #2
"kimiraikko nen" <ki************ *@gmail.comschr ieb
Hi,
I want to display ALL the items (includes unselected items) of
listbox control. How can i code this? Should i use "for each" or
other?

For example:
Assume you have a listbox with 3 items sth like:

Hello
There
Guys

And i want to display them in the same format within a messagebox
with seperated each line(maybe i have to use " + vbnewline"?).

How to do this?
If language = VB 2008 AndAlso all items in the list are Strings:

MsgBox(String.J oin(vbCrLf, Me.ListBox1.Ite ms.Cast(Of String).ToArray ))
Armin
Dec 23 '07 #3

"Armin Zingler" <az*******@free net.dekirjoitti viestissä
news:%2******** ********@TK2MSF TNGP06.phx.gbl. ..
If language = VB 2008 AndAlso all items in the list are Strings:

MsgBox(String.J oin(vbCrLf, Me.ListBox1.Ite ms.Cast(Of String).ToArray ))
Quite handy. LINQ makes everything too easy. :-)

-Teemu

Dec 23 '07 #4

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