years,months,da ys

[Jose]

Exists a function that determined between two dates the years,months and
days?

Thanks a lot.

[Scott M.]

dim x as date = someDate.subtra ct(someOtherDat e)

Then format x as desired.

"Jose" <jo********@uni ca.com> wrote in message
news:ui******** ******@TK2MSFTN GP04.phx.gbl...

Exists a function that determined between two dates the years,months and
days?

Thanks a lot.

[Chris Dunaway]

Scott M. wrote:

dim x as date = someDate.subtra ct(someOtherDat e)

The Subtract method on the DateTime structure, when passed another
DateTime, returns a Timespan object and not a DateTime object.

Dim ts As TimeSpan = someDate.Subtra ct(someOtherDat e)

Then you can get the years, months, and days properties from the
TimeSpan.

[Göran Andersson]

Chris Dunaway wrote:

Scott M. wrote:

dim x as date = someDate.subtra ct(someOtherDat e)

The Subtract method on the DateTime structure, when passed another
DateTime, returns a Timespan object and not a DateTime object.

Dim ts As TimeSpan = someDate.Subtra ct(someOtherDat e)

Then you can get the years, months, and days properties from the
TimeSpan.

Actually, you can only get the value as days.

As the timespan doesn't contain a starting and ending time, there is no
way to determine the exact length in months and years.

[aaron.kempf]

or you could use a real function like DateDiff right?

who the hell changes a function like DateDiff??

-Aaron
Göran Andersson wrote:

Chris Dunaway wrote:

Scott M. wrote:

dim x as date = someDate.subtra ct(someOtherDat e)

The Subtract method on the DateTime structure, when passed another
DateTime, returns a Timespan object and not a DateTime object.

Dim ts As TimeSpan = someDate.Subtra ct(someOtherDat e)

Then you can get the years, months, and days properties from the
TimeSpan.

Actually, you can only get the value as days.

As the timespan doesn't contain a starting and ending time, there is no
way to determine the exact length in months and years.

[Chris Dunaway]

Göran Andersson wrote:

Actually, you can only get the value as days.

I stand corrected. But when you subtract a date from another date, it
returns a Timespan and not a date.

[Cor Ligthert [MVP]]

Jose,

In my idea does this never work as measuring system. Somehow I thought it is
not possible with the Gregorian Calender, every month can have a different
length you know, not to talk about leap years. Therefore it is not such a
good measuring system.

Therefore
Date - Date represented as year, months, will will give a total other
result in by instance days as you use another startdate and add your
measured result.

(Years, weeks, days) or (years, days) will do a better job.
Although the leap year problem sustains..

That is the reason that some people want to use this kind of calendars.

http://en.wikipedia.org/wiki/Positivist_Calendar

But just my thought.

Cor

[Göran Andersson]

Chris Dunaway wrote:

Göran Andersson wrote:

Actually, you can only get the value as days.

I stand corrected. But when you subtract a date from another date, it
returns a Timespan and not a date.

Yes. If you read my next sentence you see that I am referring to the
TimeSpan structure. That implies that I concur with your observation. :)

[Chris Dunaway]

Göran Andersson wrote:

Yes. If you read my next sentence you see that I am referring to the
TimeSpan structure. That implies that I concur with your observation. :)

My mistake, I was actually replying to Scott M.'s message.