how do i get 2 different number in same row? using random
example:
4 2
5 6
7 4
1 7
9 8
3 3 <===== i want different number but not same as opposite
8 5
6 8
2 1
in my code:
Dim Nine_numbers(9) as short
Dim nm, mm As Integer, nine(9), nineA(9) As Object, innn, mmm As Short
Dim j, k As Integer
For innn = 1 To 9
nine(innn) = innn
Next
For innn = 1 To 9
Do
Dim rng As New Random
k = rng.Next(1, 10)
Loop Until nine(k) > 0
nine(k) = 0
szArray(innn) = k
TextBox82.Text = szArray(1)
TextBox91.Text = szArray(2)
TextBox100.Text = szArray(3)
TextBox83.Text = szArray(4)
TextBox92.Text = szArray(5)
TextBox101.Text = szArray(6)
TextBox84.Text = szArray(7)
TextBox93.Text = szArray(8)
TextBox102.Text = szArray(9)
Debug.WriteLine (szArray(innn))
Next
For mmm = 1 To 9
nineA(mmm) = mmm
Next
For mmm = 1 To 9
Do
Dim rng As New Random
j = rng.Next(1, 10)
Loop Until nineA(j) > 0
nineA(j) = 0
szArray(mmm) = j
TextBox85.Text = szArray(1)
TextBox94.Text = szArray(2)
TextBox103.Text = szArray(3)
TextBox86.Text = szArray(4)
TextBox95.Text = szArray(5)
TextBox104.Text = szArray(6)
TextBox87.Text = szArray(7)
TextBox96.Text = szArray(8)
TextBox105.Text = szArray(9)
Debug.WriteLine (szArray(mmm))
Next
ne iideas?
regards
13  1500 
Hi,
there probably will be better ways but this does seem to do the trick for me
just open a new windows forms project add a button to it and copy paste this
code, the makeGrid part is just to show the use of a textbox array
hth
Greetz Peter
Private textboxGrid(8, 1) As TextBox
Private Sub Form1_Load(ByVa l sender As Object, ByVal e As
System.EventArg s) Handles MyBase.Load
makeGrid()
fillRandom()
End Sub
Private Sub makeGrid()
Dim x As TextBox
Dim xPos, yPos As Integer
yPos = 20
For row As Integer = 0 To 8
xPos = 20
For column As Integer = 0 To 1
x = New TextBox
x.Name = (CStr(row) & CStr(column))
x.Location = New Point(xPos, yPos)
x.BorderStyle = BorderStyle.Fix edSingle
x.Width = 20
x.Height = 20
x.Text = ""
Me.Controls.Add (x)
textboxGrid(row , column) = x
xPos += 21
Next
yPos += 21
Next
End Sub
Private Sub fillRandom()
Dim blnOk As Boolean
For row As Integer = 0 To 8
blnOk = False
Do While blnOk = False
textboxGrid(row , 0).Text = CStr(CInt(Rnd() * 9) + 1)
textboxGrid(row , 1).Text = CStr(CInt(Rnd() * 9) + 1)
If textboxGrid(row , 0).Text <> textboxGrid(row , 1).Text Then
blnOk = True
End If
Loop
Next
End Sub
Private Sub Button1_Click(B yVal sender As System.Object, ByVal e As
System.EventArg s) Handles _ Button1.Click
fillRandom()
End Sub
--
Programming today is a race between software engineers striving to build
bigger and better idiot-proof programs, and the Universe trying to produce
bigger and better idiots. So far, the Universe is winning.
"Supra" <su***@domain.i nvalid> schreef in bericht
news:AY******** ************@ro gers.com... how do i get 2 different number in same row? using random
example:
4 2
5 6
7 4
1 7
9 8
3 3 <===== i want different number but not same as opposite
8 5
6 8
2 1
in my code:
Dim Nine_numbers(9) as short
Dim nm, mm As Integer, nine(9), nineA(9) As Object, innn, mmm As Short
Dim j, k As Integer
For innn = 1 To 9
nine(innn) = innn
Next
For innn = 1 To 9
Do
Dim rng As New Random
k = rng.Next(1, 10)
Loop Until nine(k) > 0
nine(k) = 0
szArray(innn) = k
TextBox82.Text = szArray(1)
TextBox91.Text = szArray(2)
TextBox100.Text = szArray(3)
TextBox83.Text = szArray(4)
TextBox92.Text = szArray(5)
TextBox101.Text = szArray(6)
TextBox84.Text = szArray(7)
TextBox93.Text = szArray(8)
TextBox102.Text = szArray(9)
Debug.WriteLine (szArray(innn))
Next
For mmm = 1 To 9
nineA(mmm) = mmm
Next
For mmm = 1 To 9
Do
Dim rng As New Random
j = rng.Next(1, 10)
Loop Until nineA(j) > 0
nineA(j) = 0
szArray(mmm) = j
TextBox85.Text = szArray(1)
TextBox94.Text = szArray(2)
TextBox103.Text = szArray(3)
TextBox86.Text = szArray(4)
TextBox95.Text = szArray(5)
TextBox104.Text = szArray(6)
TextBox87.Text = szArray(7)
TextBox96.Text = szArray(8)
TextBox105.Text = szArray(9)
Debug.WriteLine (szArray(mmm))
Next
ne iideas?
regards
nope. u have duplicate numbers in same column
Peter Proost wrote: Hi,
there probably will be better ways but this does seem to do the trick for me
just open a new windows forms project add a button to it and copy paste this
code, the makeGrid part is just to show the use of a textbox array
hth
Greetz Peter
Private textboxGrid(8, 1) As TextBox
Private Sub Form1_Load(ByVa l sender As Object, ByVal e As
System.EventAr gs) Handles MyBase.Load
makeGrid()
fillRandom()
End Sub
Private Sub makeGrid()
Dim x As TextBox
Dim xPos, yPos As Integer
yPos = 20
For row As Integer = 0 To 8
xPos = 20
For column As Integer = 0 To 1
x = New TextBox
x.Name = (CStr(row) & CStr(column))
x.Location = New Point(xPos, yPos)
x.BorderStyle = BorderStyle.Fix edSingle
x.Width = 20
x.Height = 20
x.Text = ""
Me.Controls.Add (x)
textboxGrid(row , column) = x
xPos += 21
Next
yPos += 21
Next
End Sub
Private Sub fillRandom()
Dim blnOk As Boolean
For row As Integer = 0 To 8
blnOk = False
Do While blnOk = False
textboxGrid(row , 0).Text = CStr(CInt(Rnd() * 9) + 1)
textboxGrid(row , 1).Text = CStr(CInt(Rnd() * 9) + 1)
If textboxGrid(row , 0).Text <> textboxGrid(row , 1).Text Then
blnOk = True
End If
Loop
Next
End Sub
Private Sub Button1_Click(B yVal sender As System.Object, ByVal e As
System.EventAr gs) Handles _ Button1.Click
fillRandom()
End Sub
--
Programming today is a race between software engineers striving to build
bigger and better idiot-proof programs, and the Universe trying to produce
bigger and better idiots. So far, the Universe is winning.
"Supra" <su***@domain.i nvalid> schreef in bericht
news:AY******* *************@r ogers.com...
how do i get 2 different number in same row? using random
example:
4 2
5 6
7 4
1 7
9 8
3 3 <===== i want different number but not same as opposite
8 5
6 8
2 1
in my code:
Dim Nine_numbers(9) as short
Dim nm, mm As Integer, nine(9), nineA(9) As Object, innn, mmm As Short
Dim j, k As Integer
For innn = 1 To 9
nine(innn) = innn
Next
For innn = 1 To 9
Do
Dim rng As New Random
k = rng.Next(1, 10)
Loop Until nine(k) > 0
nine(k) = 0
szArray(innn) = k
TextBox82.Text = szArray(1)
TextBox91.Text = szArray(2)
TextBox100.Text = szArray(3)
TextBox83.Text = szArray(4)
TextBox92.Text = szArray(5)
TextBox101.Text = szArray(6)
TextBox84.Text = szArray(7)
TextBox93.Text = szArray(8)
TextBox102.Text = szArray(9)
Debug.WriteLine (szArray(innn))
Next
For mmm = 1 To 9
nineA(mmm) = mmm
Next
For mmm = 1 To 9
Do
Dim rng As New Random
j = rng.Next(1, 10)
Loop Until nineA(j) > 0
nineA(j) = 0
szArray(mmm) = j
TextBox85.Text = szArray(1)
TextBox94.Text = szArray(2)
TextBox103.Text = szArray(3)
TextBox86.Text = szArray(4)
TextBox95.Text = szArray(5)
TextBox104.Text = szArray(6)
TextBox87.Text = szArray(7)
TextBox96.Text = szArray(8)
TextBox105.Text = szArray(9)
Debug.WriteLine (szArray(mmm))
Next
ne iideas?
regards
btw... i wanted random number from 1 to 9 in column and so on
Supra wrote: nope. u have duplicate numbers in same column
Peter Proost wrote:
Hi,
there probably will be better ways but this does seem to do the trick for me
just open a new windows forms project add a button to it and copy paste this
code, the makeGrid part is just to show the use of a textbox array
hth
Greetz Peter
Private textboxGrid(8, 1) As TextBox
Private Sub Form1_Load(ByVa l sender As Object, ByVal e As
System.EventA rgs) Handles MyBase.Load
makeGrid()
fillRandom()
End Sub
Private Sub makeGrid()
Dim x As TextBox
Dim xPos, yPos As Integer
yPos = 20
For row As Integer = 0 To 8
xPos = 20
For column As Integer = 0 To 1
x = New TextBox
x.Name = (CStr(row) & CStr(column))
x.Location = New Point(xPos, yPos)
x.BorderStyle = BorderStyle.Fix edSingle
x.Width = 20
x.Height = 20
x.Text = ""
Me.Controls.Add (x)
textboxGrid(row , column) = x
xPos += 21
Next
yPos += 21
Next
End Sub
Private Sub fillRandom()
Dim blnOk As Boolean
For row As Integer = 0 To 8
blnOk = False
Do While blnOk = False
textboxGrid(row , 0).Text = CStr(CInt(Rnd() * 9) + 1)
textboxGrid(row , 1).Text = CStr(CInt(Rnd() * 9) + 1)
If textboxGrid(row , 0).Text <> textboxGrid(row , 1).Text Then
blnOk = True
End If
Loop
Next
End Sub
Private Sub Button1_Click(B yVal sender As System.Object, ByVal e As
System.EventA rgs) Handles _ Button1.Click
fillRandom()
End Sub
--
Programming today is a race between software engineers striving to build
bigger and better idiot-proof programs, and the Universe trying to produce
bigger and better idiots. So far, the Universe is winning.
"Supra" <su***@domain.i nvalid> schreef in bericht
news:AY****** **************@ rogers.com...
how do i get 2 different number in same row? using random
example:
4 2
5 6
7 4
1 7
9 8
3 3 <===== i want different number but not same as opposite
8 5
6 8
2 1
in my code:
Dim Nine_numbers(9) as short
Dim nm, mm As Integer, nine(9), nineA(9) As Object, innn, mmm As Short
Dim j, k As Integer
For innn = 1 To 9
nine(innn) = innn
Next
For innn = 1 To 9
Do
Dim rng As New Random
k = rng.Next(1, 10)
Loop Until nine(k) > 0
nine(k) = 0
szArray(innn) = k
TextBox82.Text = szArray(1)
TextBox91.Text = szArray(2)
TextBox100.Text = szArray(3)
TextBox83.Text = szArray(4)
TextBox92.Text = szArray(5)
TextBox101.Text = szArray(6)
TextBox84.Text = szArray(7)
TextBox93.Text = szArray(8)
TextBox102.Text = szArray(9)
Debug.WriteLine (szArray(innn))
Next
For mmm = 1 To 9
nineA(mmm) = mmm
Next
For mmm = 1 To 9
Do
Dim rng As New Random
j = rng.Next(1, 10)
Loop Until nineA(j) > 0
nineA(j) = 0
szArray(mmm) = j
TextBox85.Text = szArray(1)
TextBox94.Text = szArray(2)
TextBox103.Text = szArray(3)
TextBox86.Text = szArray(4)
TextBox95.Text = szArray(5)
TextBox104.Text = szArray(6)
TextBox87.Text = szArray(7)
TextBox96.Text = szArray(8)
TextBox105.Text = szArray(9)
Debug.WriteLine (szArray(mmm))
Next
ne iideas?
regards
you wrote: how do i get 2 different number in same row? using random
example:
but it shouldn't be to difficult to alter my example
Greetz Peter
--
Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far, the Universe is winning.
"Supra" <su***@domain.i nvalid> schreef in bericht news:ZN******** ************@ro gers.com...
nope. u have duplicate numbers in same column
Peter Proost wrote:
Hi,
there probably will be better ways but this does seem to do the trick for me
just open a new windows forms project add a button to it and copy paste this
code, the makeGrid part is just to show the use of a textbox array
hth
Greetz Peter
Private textboxGrid(8, 1) As TextBox
Private Sub Form1_Load(ByVa l sender As Object, ByVal e As
System.EventArg s) Handles MyBase.Load
makeGrid()
fillRandom()
End Sub
Private Sub makeGrid()
Dim x As TextBox
Dim xPos, yPos As Integer
yPos = 20
For row As Integer = 0 To 8
xPos = 20
For column As Integer = 0 To 1
x = New TextBox
x.Name = (CStr(row) & CStr(column))
x.Location = New Point(xPos, yPos)
x.BorderStyle = BorderStyle.Fix edSingle
x.Width = 20
x.Height = 20
x.Text = ""
Me.Controls.Add (x)
textboxGrid(row , column) = x
xPos += 21
Next
yPos += 21
Next
End Sub
Private Sub fillRandom()
Dim blnOk As Boolean
For row As Integer = 0 To 8
blnOk = False
Do While blnOk = False
textboxGrid(row , 0).Text = CStr(CInt(Rnd() * 9) + 1)
textboxGrid(row , 1).Text = CStr(CInt(Rnd() * 9) + 1)
If textboxGrid(row , 0).Text <> textboxGrid(row , 1).Text Then
blnOk = True
End If
Loop
Next
End Sub
Private Sub Button1_Click(B yVal sender As System.Object, ByVal e As
System.EventArg s) Handles _ Button1.Click
fillRandom()
End Sub
--
Programming today is a race between software engineers striving to build
bigger and better idiot-proof programs, and the Universe trying to produce
bigger and better idiots. So far, the Universe is winning.
"Supra" <su***@domain.i nvalid> schreef in bericht
news:AY******** ************@ro gers.com...
how do i get 2 different number in same row? using random
example:
4 2
5 6
7 4
1 7
9 8
3 3 <===== i want different number but not same as opposite
8 5
6 8
2 1
in my code:
Dim Nine_numbers(9) as short
Dim nm, mm As Integer, nine(9), nineA(9) As Object, innn, mmm As Short
Dim j, k As Integer
For innn = 1 To 9
nine(innn) = innn
Next
For innn = 1 To 9
Do
Dim rng As New Random
k = rng.Next(1, 10)
Loop Until nine(k) > 0
nine(k) = 0
szArray(innn) = k
TextBox82.Text = szArray(1)
TextBox91.Text = szArray(2)
TextBox100.Text = szArray(3)
TextBox83.Text = szArray(4)
TextBox92.Text = szArray(5)
TextBox101.Text = szArray(6)
TextBox84.Text = szArray(7)
TextBox93.Text = szArray(8)
TextBox102.Text = szArray(9)
Debug.WriteLine (szArray(innn))
Next
For mmm = 1 To 9
nineA(mmm) = mmm
Next
For mmm = 1 To 9
Do
Dim rng As New Random
j = rng.Next(1, 10)
Loop Until nineA(j) > 0
nineA(j) = 0
szArray(mmm) = j
TextBox85.Text = szArray(1)
TextBox94.Text = szArray(2)
TextBox103.Text = szArray(3)
TextBox86.Text = szArray(4)
TextBox95.Text = szArray(5)
TextBox104.Text = szArray(6)
TextBox87.Text = szArray(7)
TextBox96.Text = szArray(8)
TextBox105.Text = szArray(9)
Debug.WriteLine (szArray(mmm))
Next
ne iideas?
regards
yes. but i random number in each column but compare row. what u do u
do random number have having same number in COLUMN but not in row not
ilike 775422133 in column but in order prevented same number in column
like i did previous code::
Loop Until (Nine_numbers3( inum3) > 0)
Nine_numbers3(i num3) = 0
szArray(n) = inum3
that is code will prevent same numbers. i was attempting subsistue in
ur sample code...
For row As Integer = 0 To 8
blnOk = False
Do
' blnOk = False
textboxGrid(row , 0).Text = Int(9 * Rnd() + 1)
' textboxGrid(row , 1).Text = Int(9 * Rnd() + 1)
' textboxGrid(row , 2).Text = Int(9 * Rnd() + 1)
' If textboxGrid(row , 0).Text <> textboxGrid(row ,
1).Text <> textboxGrid(row , 2).Text Then
' blnOk = True
' End If
Loop Until textboxGrid(row , 0).Text > 0
Next
but can't figuring it out..... i will have to work around.
regards,
Peter Proost wrote: you wrote:how do i get 2 different number in same row? using random
example:
but it shouldn't be to difficult to alter my example
Greetz Peter
--
Programming today is a race between software engineers striving to
build bigger and better idiot-proof programs, and the Universe trying
to produce bigger and better idiots. So far, the Universe is winning.
"Supra" <su***@domain.i nvalid <mailto:su***@d omain.invalid>>
schreef in bericht news:ZN******** ************@ro gers.com...
nope. u have duplicate numbers in same column
Peter Proost wrote:
Hi,
there probably will be better ways but this does seem to do the trick for me
just open a new windows forms project add a button to it and copy paste this
code, the makeGrid part is just to show the use of a textbox array
hth
Greetz Peter
Private textboxGrid(8, 1) As TextBox
Private Sub Form1_Load(ByVa l sender As Object, ByVal e As
System.EventA rgs) Handles MyBase.Load
makeGrid()
fillRandom()
End Sub
Private Sub makeGrid()
Dim x As TextBox
Dim xPos, yPos As Integer
yPos = 20
For row As Integer = 0 To 8
xPos = 20
For column As Integer = 0 To 1
x = New TextBox
x.Name = (CStr(row) & CStr(column))
x.Location = New Point(xPos, yPos)
x.BorderStyle = BorderStyle.Fix edSingle
x.Width = 20
x.Height = 20
x.Text = ""
Me.Controls.Add (x)
textboxGrid(row , column) = x
xPos += 21
Next
yPos += 21
Next
End Sub
Private Sub fillRandom()
Dim blnOk As Boolean
For row As Integer = 0 To 8
blnOk = False
Do While blnOk = False
textboxGrid(row , 0).Text = CStr(CInt(Rnd() * 9) + 1)
textboxGrid(row , 1).Text = CStr(CInt(Rnd() * 9) + 1)
If textboxGrid(row , 0).Text <> textboxGrid(row , 1).Text Then
blnOk = True
End If
Loop
Next
End Sub
Private Sub Button1_Click(B yVal sender As System.Object, ByVal e As
System.EventA rgs) Handles _ Button1.Click
fillRandom()
End Sub
--
Programming today is a race between software engineers striving to build
bigger and better idiot-proof programs, and the Universe trying to produce
bigger and better idiots. So far, the Universe is winning.
"Supra" <su***@domain.i nvalid> schreef in bericht
news:AY****** **************@ rogers.com...
how do i get 2 different number in same row? using random
example:
4 2
5 6
7 4
1 7
9 8
3 3 <===== i want different number but not same as opposite
8 5
6 8
2 1
in my code:
Dim Nine_numbers(9) as short
Dim nm, mm As Integer, nine(9), nineA(9) As Object, innn, mmm As Short
Dim j, k As Integer
For innn = 1 To 9
nine(innn) = innn
Next
For innn = 1 To 9
Do
Dim rng As New Random
k = rng.Next(1, 10)
Loop Until nine(k) > 0
nine(k) = 0
szArray(innn) = k
TextBox82.Text = szArray(1)
TextBox91.Text = szArray(2)
TextBox100.Text = szArray(3)
TextBox83.Text = szArray(4)
TextBox92.Text = szArray(5)
TextBox101.Text = szArray(6)
TextBox84.Text = szArray(7)
TextBox93.Text = szArray(8)
TextBox102.Text = szArray(9)
Debug.WriteLine (szArray(innn))
Next
For mmm = 1 To 9
nineA(mmm) = mmm
Next
For mmm = 1 To 9
Do
Dim rng As New Random
j = rng.Next(1, 10)
Loop Until nineA(j) > 0
nineA(j) = 0
szArray(mmm) = j
TextBox85.Text = szArray(1)
TextBox94.Text = szArray(2)
TextBox103.Text = szArray(3)
TextBox86.Text = szArray(4)
TextBox95.Text = szArray(5)
TextBox104.Text = szArray(6)
TextBox87.Text = szArray(7)
TextBox96.Text = szArray(8)
TextBox105.Text = szArray(9)
Debug.WriteLine (szArray(mmm))
Next
ne iideas?
regards
Hi I'm going home now, but I'll try to help you 2morrow (I'm not sure if I'll have access to a .net computer tonight)
Greetz Peter
--
Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far, the Universe is winning.
"Supra" <su***@domain.i nvalid> schreef in bericht news:2I******** ************@ro gers.com...
yes. but i random number in each column but compare row. what u do u do random number have having same number in COLUMN but not in row not ilike 775422133 in column but in order prevented same number in column like i did previous code::
Loop Until (Nine_numbers3( inum3) > 0)
Nine_numbers3(i num3) = 0
szArray(n) = inum3
that is code will prevent same numbers. i was attempting subsistue in ur sample code...
For row As Integer = 0 To 8
blnOk = False
Do
' blnOk = False
textboxGrid(row , 0).Text = Int(9 * Rnd() + 1)
' textboxGrid(row , 1).Text = Int(9 * Rnd() + 1)
' textboxGrid(row , 2).Text = Int(9 * Rnd() + 1)
' If textboxGrid(row , 0).Text <> textboxGrid(row , 1).Text <> textboxGrid(row , 2).Text Then
' blnOk = True
' End If
Loop Until textboxGrid(row , 0).Text > 0
Next
but can't figuring it out..... i will have to work around.
regards,
Peter Proost wrote:
you wrote: how do i get 2 different number in same row? using random
example:
but it shouldn't be to difficult to alter my example
Greetz Peter
--
Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far, the Universe is winning.
"Supra" <su***@domain.i nvalid> schreef in bericht news:ZN******** ************@ro gers.com...
nope. u have duplicate numbers in same column
Peter Proost wrote:
Hi,
there probably will be better ways but this does seem to do the trick for me
just open a new windows forms project add a button to it and copy paste this
code, the makeGrid part is just to show the use of a textbox array
hth
Greetz Peter
Private textboxGrid(8, 1) As TextBox
Private Sub Form1_Load(ByVa l sender As Object, ByVal e As
System.EventArg s) Handles MyBase.Load
makeGrid()
fillRandom()
End Sub
Private Sub makeGrid()
Dim x As TextBox
Dim xPos, yPos As Integer
yPos = 20
For row As Integer = 0 To 8
xPos = 20
For column As Integer = 0 To 1
x = New TextBox
x.Name = (CStr(row) & CStr(column))
x.Location = New Point(xPos, yPos)
x.BorderStyle = BorderStyle.Fix edSingle
x.Width = 20
x.Height = 20
x.Text = ""
Me.Controls.Add (x)
textboxGrid(row , column) = x
xPos += 21
Next
yPos += 21
Next
End Sub
Private Sub fillRandom()
Dim blnOk As Boolean
For row As Integer = 0 To 8
blnOk = False
Do While blnOk = False
textboxGrid(row , 0).Text = CStr(CInt(Rnd() * 9) + 1)
textboxGrid(row , 1).Text = CStr(CInt(Rnd() * 9) + 1)
If textboxGrid(row , 0).Text <> textboxGrid(row , 1).Text Then
blnOk = True
End If
Loop
Next
End Sub
Private Sub Button1_Click(B yVal sender As System.Object, ByVal e As
System.EventArg s) Handles _ Button1.Click
fillRandom()
End Sub
--
Programming today is a race between software engineers striving to build
bigger and better idiot-proof programs, and the Universe trying to produce
bigger and better idiots. So far, the Universe is winning.
"Supra" <su***@domain.i nvalid> schreef in bericht
news:AY******** ************@ro gers.com...
how do i get 2 different number in same row? using random
example:
4 2
5 6
7 4
1 7
9 8
3 3 <===== i want different number but not same as opposite
8 5
6 8
2 1
in my code:
Dim Nine_numbers(9) as short
Dim nm, mm As Integer, nine(9), nineA(9) As Object, innn, mmm As Short
Dim j, k As Integer
For innn = 1 To 9
nine(innn) = innn
Next
For innn = 1 To 9
Do
Dim rng As New Random
k = rng.Next(1, 10)
Loop Until nine(k) > 0
nine(k) = 0
szArray(innn) = k
TextBox82.Text = szArray(1)
TextBox91.Text = szArray(2)
TextBox100.Text = szArray(3)
TextBox83.Text = szArray(4)
TextBox92.Text = szArray(5)
TextBox101.Text = szArray(6)
TextBox84.Text = szArray(7)
TextBox93.Text = szArray(8)
TextBox102.Text = szArray(9)
Debug.WriteLine (szArray(innn))
Next
For mmm = 1 To 9
nineA(mmm) = mmm
Next
For mmm = 1 To 9
Do
Dim rng As New Random
j = rng.Next(1, 10)
Loop Until nineA(j) > 0
nineA(j) = 0
szArray(mmm) = j
TextBox85.Text = szArray(1)
TextBox94.Text = szArray(2)
TextBox103.Text = szArray(3)
TextBox86.Text = szArray(4)
TextBox95.Text = szArray(5)
TextBox104.Text = szArray(6)
TextBox87.Text = szArray(7)
TextBox96.Text = szArray(8)
TextBox105.Text = szArray(9)
Debug.WriteLine (szArray(mmm))
Next
ne iideas?
regards
have nice day trip :-)
Peter Proost wrote: Hi I'm going home now, but I'll try to help you 2morrow (I'm not sure
if I'll have access to a .net computer tonight)
Greetz Peter
--
Programming today is a race between software engineers striving to
build bigger and better idiot-proof programs, and the Universe trying
to produce bigger and better idiots. So far, the Universe is winning.
"Supra" <su***@domain.i nvalid <mailto:su***@d omain.invalid>>
schreef in bericht news:2I******** ************@ro gers.com...
yes. but i random number in each column but compare row. what u
do u do random number have having same number in COLUMN but not
in row not ilike 775422133 in column but in order prevented same
number in column like i did previous code::
Loop Until (Nine_numbers3( inum3) > 0)
Nine_numbers3(i num3) = 0
szArray(n) = inum3
that is code will prevent same numbers. i was attempting
subsistue in ur sample code...
For row As Integer = 0 To 8
blnOk = False
Do
' blnOk = False
textboxGrid(row , 0).Text = Int(9 * Rnd() + 1)
' textboxGrid(row , 1).Text = Int(9 * Rnd() + 1)
' textboxGrid(row , 2).Text = Int(9 * Rnd() + 1)
' If textboxGrid(row , 0).Text <> textboxGrid(row ,
1).Text <> textboxGrid(row , 2).Text Then
' blnOk = True
' End If
Loop Until textboxGrid(row , 0).Text > 0
Next
but can't figuring it out..... i will have to work around.
regards,
Peter Proost wrote:
you wrote: >how do i get 2 different number in same row? using random
>example:
but it shouldn't be to difficult to alter my example
Greetz Peter
--
Programming today is a race between software engineers striving
to build bigger and better idiot-proof programs, and the Universe
trying to produce bigger and better idiots. So far, the Universe
is winning.
"Supra" <su***@domain.i nvalid <mailto:su***@d omain.invalid>>
schreef in bericht news:ZN******** ************@ro gers.com...
nope. u have duplicate numbers in same column
Peter Proost wrote:
Hi,
there probably will be better ways but this does seem to do the trick for me
just open a new windows forms project add a button to it and copy paste this
code, the makeGrid part is just to show the use of a textbox array
hth
Greetz Peter
Private textboxGrid(8, 1) As TextBox
Private Sub Form1_Load(ByVa l sender As Object, ByVal e As
System.Event Args) Handles MyBase.Load
makeGrid()
fillRandom()
End Sub
Private Sub makeGrid()
Dim x As TextBox
Dim xPos, yPos As Integer
yPos = 20
For row As Integer = 0 To 8
xPos = 20
For column As Integer = 0 To 1
x = New TextBox
x.Name = (CStr(row) & CStr(column))
x.Location = New Point(xPos, yPos)
x.BorderStyle = BorderStyle.Fix edSingle
x.Width = 20
x.Height = 20
x.Text = ""
Me.Controls.Add (x)
textboxGrid(row , column) = x
xPos += 21
Next
yPos += 21
Next
End Sub
Private Sub fillRandom()
Dim blnOk As Boolean
For row As Integer = 0 To 8
blnOk = False
Do While blnOk = False
textboxGrid(row , 0).Text = CStr(CInt(Rnd() * 9) + 1)
textboxGrid(row , 1).Text = CStr(CInt(Rnd() * 9) + 1)
If textboxGrid(row , 0).Text <> textboxGrid(row , 1).Text Then
blnOk = True
End If
Loop
Next
End Sub
Private Sub Button1_Click(B yVal sender As System.Object, ByVal e As
System.Event Args) Handles _ Button1.Click
fillRandom()
End Sub
--
Programmin g today is a race between software engineers striving to build
bigger and better idiot-proof programs, and the Universe trying to produce
bigger and better idiots. So far, the Universe is winning.
"Supra" <su***@domain.i nvalid> schreef in bericht
news:AY***** *************** @rogers.com...
how do i get 2 different number in same row? using random
example:
4 2
5 6
7 4
1 7
9 8
3 3 <===== i want different number but not same as opposite
8 5
6 8
2 1
in my code:
Dim Nine_numbers(9) as short
Dim nm, mm As Integer, nine(9), nineA(9) As Object, innn, mmm As Short
Dim j, k As Integer
For innn = 1 To 9
nine(innn) = innn
Next
For innn = 1 To 9
Do
Dim rng As New Random
k = rng.Next(1, 10)
Loop Until nine(k) > 0
nine(k) = 0
szArray(innn) = k
TextBox82.Text = szArray(1)
TextBox91.Text = szArray(2)
TextBox100.Text = szArray(3)
TextBox83.Text = szArray(4)
TextBox92.Text = szArray(5)
TextBox101.Text = szArray(6)
TextBox84.Text = szArray(7)
TextBox93.Text = szArray(8)
TextBox102.Text = szArray(9)
Debug.WriteLine (szArray(innn))
Next
For mmm = 1 To 9
nineA(mmm) = mmm
Next
For mmm = 1 To 9
Do
Dim rng As New Random
j = rng.Next(1, 10)
Loop Until nineA(j) > 0
nineA(j) = 0
szArray(mmm) = j
TextBox85.Text = szArray(1)
TextBox94.Text = szArray(2)
TextBox103.Text = szArray(3)
TextBox86.Text = szArray(4)
TextBox95.Text = szArray(5)
TextBox104.Text = szArray(6)
TextBox87.Text = szArray(7)
TextBox96.Text = szArray(8)
TextBox105.Text = szArray(9)
Debug.WriteLine (szArray(mmm))
Next
ne iideas?
regards
Hi try it with this code in the fillrandom sub, it should work:
Private Sub fillRandom()
Dim left As New ArrayList
Dim right As New ArrayList
Dim blnOk As Boolean = False
Dim intGetal As Integer
For i As Integer = 0 To 8
blnOk = False
Do While blnOk = False
intGetal = CInt(Rnd() * 8) + 1
If left.IndexOf(in tGetal) < 0 Then
left.Add(intGet al)
blnOk = True
Else
blnOk = False
End If
Loop
Next
For i As Integer = 0 To 8
blnOk = False
Do While blnOk = False
intGetal = CInt(Rnd() * 8) + 1
If right.IndexOf(i ntGetal) < 0 And intGetal <> CInt(left(i)) Then
right.Add(intGe tal)
blnOk = True
Else
blnOk = False
End If
Loop
Next
For i As Integer = 0 To 8
textboxGrid(i, 0).Text = CStr(left(i))
textboxGrid(i, 1).Text = CStr(right(i))
Next
End Sub
hth Greetz Peter
--
Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far, the Universe is winning.
"Supra" <su***@domain.i nvalid> schreef in bericht news:38******** ************@ro gers.com...
have nice day trip :-)
Peter Proost wrote:
Hi I'm going home now, but I'll try to help you 2morrow (I'm not sure if I'll have access to a .net computer tonight)
Greetz Peter
--
Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far, the Universe is winning.
"Supra" <su***@domain.i nvalid> schreef in bericht news:2I******** ************@ro gers.com...
yes. but i random number in each column but compare row. what u do u do random number have having same number in COLUMN but not in row not ilike 775422133 in column but in order prevented same number in column like i did previous code::
Loop Until (Nine_numbers3( inum3) > 0)
Nine_numbers3(i num3) = 0
szArray(n) = inum3
that is code will prevent same numbers. i was attempting subsistue in ur sample code...
For row As Integer = 0 To 8
blnOk = False
Do
' blnOk = False
textboxGrid(row , 0).Text = Int(9 * Rnd() + 1)
' textboxGrid(row , 1).Text = Int(9 * Rnd() + 1)
' textboxGrid(row , 2).Text = Int(9 * Rnd() + 1)
' If textboxGrid(row , 0).Text <> textboxGrid(row , 1).Text <> textboxGrid(row , 2).Text Then
' blnOk = True
' End If
Loop Until textboxGrid(row , 0).Text > 0
Next
but can't figuring it out..... i will have to work around.
regards,
Peter Proost wrote:
you wrote: how do i get 2 different number in same row? using random
example:
but it shouldn't be to difficult to alter my example
Greetz Peter
--
Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far, the Universe is winning.
"Supra" <su***@domain.i nvalid> schreef in bericht news:ZN******** ************@ro gers.com...
nope. u have duplicate numbers in same column
Peter Proost wrote:
Hi,
there probably will be better ways but this does seem to do the trick for me
just open a new windows forms project add a button to it and copy paste this
code, the makeGrid part is just to show the use of a textbox array
hth
Greetz Peter
Private textboxGrid(8, 1) As TextBox
Private Sub Form1_Load(ByVa l sender As Object, ByVal e As
System.EventArg s) Handles MyBase.Load
makeGrid()
fillRandom()
End Sub
Private Sub makeGrid()
Dim x As TextBox
Dim xPos, yPos As Integer
yPos = 20
For row As Integer = 0 To 8
xPos = 20
For column As Integer = 0 To 1
x = New TextBox
x.Name = (CStr(row) & CStr(column))
x.Location = New Point(xPos, yPos)
x.BorderStyle = BorderStyle.Fix edSingle
x.Width = 20
x.Height = 20
x.Text = ""
Me.Controls.Add (x)
textboxGrid(row , column) = x
xPos += 21
Next
yPos += 21
Next
End Sub
Private Sub fillRandom()
Dim blnOk As Boolean
For row As Integer = 0 To 8
blnOk = False
Do While blnOk = False
textboxGrid(row , 0).Text = CStr(CInt(Rnd() * 9) + 1)
textboxGrid(row , 1).Text = CStr(CInt(Rnd() * 9) + 1)
If textboxGrid(row , 0).Text <> textboxGrid(row , 1).Text Then
blnOk = True
End If
Loop
Next
End Sub
Private Sub Button1_Click(B yVal sender As System.Object, ByVal e As
System.EventArg s) Handles _ Button1.Click
fillRandom()
End Sub
--
Programming today is a race between software engineers striving to build
bigger and better idiot-proof programs, and the Universe trying to produce
bigger and better idiots. So far, the Universe is winning.
"Supra" <su***@domain.i nvalid> schreef in bericht
news:AY******** ************@ro gers.com...
how do i get 2 different number in same row? using random
example:
4 2
5 6
7 4
1 7
9 8
3 3 <===== i want different number but not same as opposite
8 5
6 8
2 1
in my code:
Dim Nine_numbers(9) as short
Dim nm, mm As Integer, nine(9), nineA(9) As Object, innn, mmm As Short
Dim j, k As Integer
For innn = 1 To 9
nine(innn) = innn
Next
For innn = 1 To 9
Do
Dim rng As New Random
k = rng.Next(1, 10)
Loop Until nine(k) > 0
nine(k) = 0
szArray(innn) = k
TextBox82.Text = szArray(1)
TextBox91.Text = szArray(2)
TextBox100.Text = szArray(3)
TextBox83.Text = szArray(4)
TextBox92.Text = szArray(5)
TextBox101.Text = szArray(6)
TextBox84.Text = szArray(7)
TextBox93.Text = szArray(8)
TextBox102.Text = szArray(9)
Debug.WriteLine (szArray(innn))
Next
For mmm = 1 To 9
nineA(mmm) = mmm
Next
For mmm = 1 To 9
Do
Dim rng As New Random
j = rng.Next(1, 10)
Loop Until nineA(j) > 0
nineA(j) = 0
szArray(mmm) = j
TextBox85.Text = szArray(1)
TextBox94.Text = szArray(2)
TextBox103.Text = szArray(3)
TextBox86.Text = szArray(4)
TextBox95.Text = szArray(5)
TextBox104.Text = szArray(6)
TextBox87.Text = szArray(7)
TextBox96.Text = szArray(8)
TextBox105.Text = szArray(9)
Debug.WriteLine (szArray(mmm))
Next
ne iideas?
regards
:-)
Peter Proost wrote: Hi try it with this code in the fillrandom sub, it should work:
Private Sub fillRandom()
Dim left As New ArrayList
Dim right As New ArrayList
Dim blnOk As Boolean = False
Dim intGetal As Integer
For i As Integer = 0 To 8
blnOk = False
Do While blnOk = False
intGetal = CInt(Rnd() * 8) + 1
If left.IndexOf(in tGetal) < 0 Then
left.Add(intGet al)
blnOk = True
Else
blnOk = False
End If
Loop
Next
For i As Integer = 0 To 8
blnOk = False
Do While blnOk = False
intGetal = CInt(Rnd() * 8) + 1
If right.IndexOf(i ntGetal) < 0 And intGetal <>
CInt(left(i)) Then
right.Add(intGe tal)
blnOk = True
Else
blnOk = False
End If
Loop
Next
For i As Integer = 0 To 8
textboxGrid(i, 0).Text = CStr(left(i))
textboxGrid(i, 1).Text = CStr(right(i))
Next
End Sub
hth Greetz Peter
--
Programming today is a race between software engineers striving to
build bigger and better idiot-proof programs, and the Universe trying
to produce bigger and better idiots. So far, the Universe is winning.
"Supra" <su***@domain.i nvalid <mailto:su***@d omain.invalid>>
schreef in bericht news:38******** ************@ro gers.com...
have nice day trip :-)
Peter Proost wrote:
Hi I'm going home now, but I'll try to help you 2morrow (I'm not
sure if I'll have access to a .net computer tonight)
Greetz Peter
--
Programming today is a race between software engineers striving
to build bigger and better idiot-proof programs, and the Universe
trying to produce bigger and better idiots. So far, the Universe
is winning.
"Supra" <su***@domain.i nvalid <mailto:su***@d omain.invalid>>
schreef in bericht news:2I******** ************@ro gers.com...
yes. but i random number in each column but compare row.
what u do u do random number have having same number in
COLUMN but not in row not ilike 775422133 in column but in
order prevented same number in column like i did previous code::
Loop Until (Nine_numbers3( inum3) > 0)
Nine_numbers3(i num3) = 0
szArray(n) = inum3
that is code will prevent same numbers. i was attempting
subsistue in ur sample code...
For row As Integer = 0 To 8
blnOk = False
Do
' blnOk = False
textboxGrid(row , 0).Text = Int(9 * Rnd() + 1)
' textboxGrid(row , 1).Text = Int(9 * Rnd() + 1)
' textboxGrid(row , 2).Text = Int(9 * Rnd() + 1)
' If textboxGrid(row , 0).Text <>
textboxGrid(row , 1).Text <> textboxGrid(row , 2).Text Then
' blnOk = True
' End If
Loop Until textboxGrid(row , 0).Text > 0
Next
but can't figuring it out..... i will have to work around.
regards,
Peter Proost wrote:
you wrote:
>how do i get 2 different number in same row? using random
>example:
but it shouldn't be to difficult to alter my example
Greetz Peter
--
Programming today is a race between software engineers
striving to build bigger and better idiot-proof programs,
and the Universe trying to produce bigger and better idiots.
So far, the Universe is winning.
"Supra" <su***@domain.i nvalid
<mailto:su***@d omain.invalid>> schreef in bericht
news:ZN******** ************@ro gers.com...
nope. u have duplicate numbers in same column
Peter Proost wrote:
Hi,
there probably will be better ways but this does seem to do the trick for me
just open a new windows forms project add a button to it and copy paste this
code, the makeGrid part is just to show the use of a textbox array
hth
Greetz Peter
Private textboxGrid(8, 1) As TextBox
Private Sub Form1_Load(ByVa l sender As Object, ByVal e As
System.Even tArgs) Handles MyBase.Load
makeGrid()
fillRandom()
End Sub
Private Sub makeGrid()
Dim x As TextBox
Dim xPos, yPos As Integer
yPos = 20
For row As Integer = 0 To 8
xPos = 20
For column As Integer = 0 To 1
x = New TextBox
x.Name = (CStr(row) & CStr(column))
x.Location = New Point(xPos, yPos)
x.BorderStyle = BorderStyle.Fix edSingle
x.Width = 20
x.Height = 20
x.Text = ""
Me.Controls.Add (x)
textboxGrid(row , column) = x
xPos += 21
Next
yPos += 21
Next
End Sub
Private Sub fillRandom()
Dim blnOk As Boolean
For row As Integer = 0 To 8
blnOk = False
Do While blnOk = False
textboxGrid(row , 0).Text = CStr(CInt(Rnd() * 9) + 1)
textboxGrid(row , 1).Text = CStr(CInt(Rnd() * 9) + 1)
If textboxGrid(row , 0).Text <> textboxGrid(row , 1).Text Then
blnOk = True
End If
Loop
Next
End Sub
Private Sub Button1_Click(B yVal sender As System.Object, ByVal e As
System.Even tArgs) Handles _ Button1.Click
fillRandom()
End Sub
--
Programmi ng today is a race between software engineers striving to build
bigger and better idiot-proof programs, and the Universe trying to produce
bigger and better idiots. So far, the Universe is winning.
"Supra" <su***@domain.i nvalid> schreef in bericht
news:AY**** *************** *@rogers.com...
>how do i get 2 different number in same row? using random
>example:
>
>4 2
>5 6
>7 4
>1 7
>9 8
>3 3 <===== i want different number but not same as opposite
>8 5
>6 8
>2 1
>
>in my code:
>
>Dim Nine_numbers(9) as short
> Dim nm, mm As Integer, nine(9), nineA(9) As Object, innn, mmm As Short
> Dim j, k As Integer
> For innn = 1 To 9
> nine(innn) = innn
> Next
> For innn = 1 To 9
> Do
> Dim rng As New Random
> k = rng.Next(1, 10)
> Loop Until nine(k) > 0
> nine(k) = 0
> szArray(innn) = k
> TextBox82.Text = szArray(1)
> TextBox91.Text = szArray(2)
> TextBox100.Text = szArray(3)
> TextBox83.Text = szArray(4)
> TextBox92.Text = szArray(5)
> TextBox101.Text = szArray(6)
> TextBox84.Text = szArray(7)
> TextBox93.Text = szArray(8)
> TextBox102.Text = szArray(9)
> Debug.WriteLine (szArray(innn))
> Next
>
> For mmm = 1 To 9
> nineA(mmm) = mmm
> Next
> For mmm = 1 To 9
> Do
> Dim rng As New Random
> j = rng.Next(1, 10)
> Loop Until nineA(j) > 0
> nineA(j) = 0
> szArray(mmm) = j
> TextBox85.Text = szArray(1)
> TextBox94.Text = szArray(2)
> TextBox103.Text = szArray(3)
> TextBox86.Text = szArray(4)
> TextBox95.Text = szArray(5)
> TextBox104.Text = szArray(6)
> TextBox87.Text = szArray(7)
> TextBox96.Text = szArray(8)
> TextBox105.Text = szArray(9)
> Debug.WriteLine (szArray(mmm))
> Next
>
>ne iideas?
>regards
>
>
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