Hi All,
Consider the following code.
Dim str As String
Dim i As Integer
str = " Hello Hi"
If str.IndexOf("Ab c Def") Or str.IndexOf("Gh i jkl mno") Or _
str.IndexOf("pq r stu vwxe") Or str.IndexOf("er rr erttt. tttt")
Or _
str.IndexOf("gf gh fgfg fgfhe") Or str.IndexOf("fg Cghr hggh.
sds") Or _
str.IndexOf("sd s sd dfd dfd dfd") Or str.IndexOf("df d dfd dfd
dfdf") Or _
str.IndexOf("df ds qwq cvb") Or str.IndexOf("jh jhy hjht") Or _
str.IndexOf("hj jyy Lyy") Or str.IndexOf("ty tl jjj") Or _
str.IndexOf("we w vbn ghg ghg") Or str.IndexOf("gh gj ghhe hhj hjh
gh ghjg") Or _
str.IndexOf("gh jg gh. ghj. gh") Or _
str.IndexOf("gh ghjg") > -1 Then
MsgBox("Found", MsgBoxStyle.OKO nly)
Else
MsgBox("Not Found", MsgBoxStyle.OKO nly)
End If
i = str.IndexOf("Ab c Def")
MsgBox(i, MsgBoxStyle.OKO nly)
If i > -1 Then
MsgBox("False", MsgBoxStyle.OKO nly)
Else
MsgBox("True", MsgBoxStyle.OKO nly)
End If
Though the first condition returns -1, "Found" is diplayed. However 'i'
contains -1 and the second condition is executed correctly and "True" is
displayed!
Could anybody please explain as to why the first condition returned true?
Thanks.
kd.
2  4215 
Hi,
Dont let vb.net convert an integer to a boolean add > -1 to each
str.Indexof statement.
Ken
---------------
"kd" <kd@discussions .microsoft.com> wrote in message
news:E7******** *************** ***********@mic rosoft.com...
Hi All,
Consider the following code.
Dim str As String
Dim i As Integer
str = " Hello Hi"
If str.IndexOf("Ab c Def") Or str.IndexOf("Gh i jkl mno") Or _
str.IndexOf("pq r stu vwxe") Or str.IndexOf("er rr erttt. tttt")
Or _
str.IndexOf("gf gh fgfg fgfhe") Or str.IndexOf("fg Cghr hggh.
sds") Or _
str.IndexOf("sd s sd dfd dfd dfd") Or str.IndexOf("df d dfd dfd
dfdf") Or _
str.IndexOf("df ds qwq cvb") Or str.IndexOf("jh jhy hjht") Or _
str.IndexOf("hj jyy Lyy") Or str.IndexOf("ty tl jjj") Or _
str.IndexOf("we w vbn ghg ghg") Or str.IndexOf("gh gj ghhe hhj hjh
gh ghjg") Or _
str.IndexOf("gh jg gh. ghj. gh") Or _
str.IndexOf("gh ghjg") > -1 Then
MsgBox("Found", MsgBoxStyle.OKO nly)
Else
MsgBox("Not Found", MsgBoxStyle.OKO nly)
End If
i = str.IndexOf("Ab c Def")
MsgBox(i, MsgBoxStyle.OKO nly)
If i > -1 Then
MsgBox("False", MsgBoxStyle.OKO nly)
Else
MsgBox("True", MsgBoxStyle.OKO nly)
End If
Though the first condition returns -1, "Found" is diplayed. However 'i'
contains -1 and the second condition is executed correctly and "True" is
displayed!
Could anybody please explain as to why the first condition returned true?
Thanks.
kd.
To add to what Ken has said, Option Strict On would tell you you are
doing something wrong here. Integers should not be trated as
truth-values - yes VB6 let you do this, but it's not 'Strict'ly (haha)
correct...
--
Larry Lard
Replies to group please
Ken Tucker [MVP] wrote: Hi,
Dont let vb.net convert an integer to a boolean add > -1 to
each str.Indexof statement.
Ken
---------------
"kd" <kd@discussions .microsoft.com> wrote in message
news:E7******** *************** ***********@mic rosoft.com...
Hi All,
Consider the following code.
Dim str As String
Dim i As Integer
str = " Hello Hi"
If str.IndexOf("Ab c Def") Or str.IndexOf("Gh i jkl mno") Or _
str.IndexOf("pq r stu vwxe") Or str.IndexOf("er rr erttt.
tttt") Or _
str.IndexOf("gf gh fgfg fgfhe") Or str.IndexOf("fg Cghr
hggh. sds") Or _
str.IndexOf("sd s sd dfd dfd dfd") Or str.IndexOf("df d dfd
dfd dfdf") Or _
str.IndexOf("df ds qwq cvb") Or str.IndexOf("jh jhy hjht")
Or _ str.IndexOf("hj jyy Lyy") Or str.IndexOf("ty tl jjj") Or _
str.IndexOf("we w vbn ghg ghg") Or str.IndexOf("gh gj ghhe
hhj hjh gh ghjg") Or _
str.IndexOf("gh jg gh. ghj. gh") Or _
str.IndexOf("gh ghjg") > -1 Then
MsgBox("Found", MsgBoxStyle.OKO nly)
Else
MsgBox("Not Found", MsgBoxStyle.OKO nly)
End If
i = str.IndexOf("Ab c Def")
MsgBox(i, MsgBoxStyle.OKO nly)
If i > -1 Then
MsgBox("False", MsgBoxStyle.OKO nly)
Else
MsgBox("True", MsgBoxStyle.OKO nly)
End If
Though the first condition returns -1, "Found" is diplayed. However
'i' contains -1 and the second condition is executed correctly and "True"
is displayed!
Could anybody please explain as to why the first condition returned
true?
Thanks.
kd. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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