Rnd Command

[V Power]

Hi,

I have just been putting together a random number
generator to practice with VB .NET. The Rnd command on its
own works fine, however as soon as I add = 10 to the
string I get a return value of false. If i use the string
CStr(Int(Rnd() = 10)) I get a return value of 0.

What am I doing wrong - because the debugger seems to
think everything is fine.

Kind regards

Vicky

[EricJ]

you are doing a boolean comparison

rnd() could be 5.3
is 5.3 = 10 ? --> false
cint(false) = 0
cstr(0) = "0"

i don't know w you want w the = 10 but thats not the way to do it

hope it helps

eric

"V Power" <an*******@disc ussions.microso ft.com> wrote in message
news:20******** *************** *****@phx.gbl.. .

Hi,

I have just been putting together a random number
generator to practice with VB .NET. The Rnd command on its
own works fine, however as soon as I add = 10 to the
string I get a return value of false. If i use the string
CStr(Int(Rnd() = 10)) I get a return value of 0.

What am I doing wrong - because the debugger seems to
think everything is fine.

Kind regards

Vicky

[V Power]

Hi,

Well apprently that string was supposed to round the random
number to = say 7 rather than 0.708

CStr(Int(Rnd() = 10))

Hope that makes sense,

thanks for your answer Ive noted it :)

Vicky

-----Original Message-----
you are doing a boolean comparison

rnd() could be 5.3
is 5.3 = 10 ? --> false
cint(false) = 0
cstr(0) = "0"

i don't know w you want w the = 10 but thats not the way to do it
hope it helps

eric

"V Power" <an*******@disc ussions.microso ft.com> wrote in messagenews:20******* *************** ******@phx.gbl. ..

Hi,

I have just been putting together a random number
generator to practice with VB .NET. The Rnd command on its
own works fine, however as soon as I add = 10 to the
string I get a return value of false. If i use the string
CStr(Int(Rnd() = 10)) I get a return value of 0.

What am I doing wrong - because the debugger seems to
think everything is fine.

Kind regards

Vicky

.

[EricJ]

that would be CStr(Int(Rnd() * 10)) :)
"V Power" <an*******@disc ussions.microso ft.com> wrote in message
news:21******** *************** *****@phx.gbl.. .

Hi,

Well apprently that string was supposed to round the random
number to = say 7 rather than 0.708

CStr(Int(Rnd() = 10))

Hope that makes sense,

thanks for your answer Ive noted it :)

Vicky

-----Original Message-----
you are doing a boolean comparison

rnd() could be 5.3
is 5.3 = 10 ? --> false
cint(false) = 0
cstr(0) = "0"

i don't know w you want w the = 10 but thats not the way

to do it

hope it helps

eric

"V Power" <an*******@disc ussions.microso ft.com> wrote in

message

news:20******* *************** ******@phx.gbl. ..

Hi,

I have just been putting together a random number
generator to practice with VB .NET. The Rnd command on its
own works fine, however as soon as I add = 10 to the
string I get a return value of false. If i use the string
CStr(Int(Rnd() = 10)) I get a return value of 0.

What am I doing wrong - because the debugger seems to
think everything is fine.

Kind regards

Vicky

.

[V Power]

Yeah,
Ive just sat and re-read it all loads and suddenly my
vision celared :)
I wont be forgetting that in a hurry! :)

thankyou

Vicky

-----Original Message-----
that would be CStr(Int(Rnd() * 10)) :)
"V Power" <an*******@disc ussions.microso ft.com> wrote in messagenews:21******* *************** ******@phx.gbl. ..

Hi,

Well apprently that string was supposed to round the random
number to = say 7 rather than 0.708

CStr(Int(Rnd() = 10))

Hope that makes sense,

thanks for your answer Ive noted it :)

Vicky

>-----Original Message-----
>you are doing a boolean comparison
>
>rnd() could be 5.3
>is 5.3 = 10 ? --> false
>cint(false) = 0
>cstr(0) = "0"
>
>i don't know w you want w the = 10 but thats not the way

to do it

>
>hope it helps
>
>eric
>
>"V Power" <an*******@disc ussions.microso ft.com> wrote in

message

>news:20******* *************** ******@phx.gbl. ..
>> Hi,
>>
>> I have just been putting together a random number
>> generator to practice with VB .NET. The Rnd command on its >> own works fine, however as soon as I add = 10 to the
>> string I get a return value of false. If i use the string
>> CStr(Int(Rnd() = 10)) I get a return value of 0.
>>
>> What am I doing wrong - because the debugger seems to
>> think everything is fine.
>>
>> Kind regards
>>
>> Vicky
>
>
>.
>

.

[Chris Dunaway]

On Wed, 21 Apr 2004 02:47:58 -0700, V Power wrote:

Hi,

I have just been putting together a random number
generator to practice with VB .NET. The Rnd command on its
own works fine, however as soon as I add = 10 to the

Any reason you're not using the Random class?

'Create an instance of the random class
Dim rand As New Random(Environm ent.TickCount)

'Generate 10 random integers between 1 and 100
For x As Integer = 0 To 99
Console.WriteLi ne(rand.Next(1, 101).ToString)
Next

'Generate 10 random doubles between 0 and 1
For x As Integer = 0 To 99
Console.WriteLi ne(rand.NextDou ble.ToString)
Next

--
Chris

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