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GROUP BY column-name problem (need expression)

Please advise on how to get the GROUP BY coded in an acceptable way:

DECLARE @StartDate varchar(10)
DECLARE @EndDate varchar(10)

SELECT @StartDate = '01/01/2005'
SELECT @EndDate = '06/30/2005'
SELECT @LO = 250
SELECT @HI = 333

, CountyCD
, Zip
, Z.CityName
, Z.StateCode
, Z.CountyName
, 'Criteria' = 'JumboRange:' + Convert(varchar(4),@LO) + '-' +
, 'StartingDate' = @StartDate
, 'ThruDate' = @EndDate
, JumboAmount = SUM(JumboAmount)
, JumboMortgages = SUM(JumboMortgages)
, JumboFIXMortgages = SUM(JumboFIXMortgages)
, JumboFIXAmount = SUM(JumboFIXAmount)
, JumboARMMortgages = SUM(JumboARMMortgages)
, JumboARMAmount = SUM(JumboARMAmount)
FROM LoanDetails T INNER JOIN dbo.ZipCodesPreferred Z
ON T.StateCD = Z.FIPS_State AND T.CountyCD = Z.FIPS_County AND T.Zip =
, CountyCD
, Zip
, Z.CityName
, Z.StateCode
, Z.CountyName
, 'Criteria' = 'JumboRange:' + Convert(varchar(4),@LO) + '-' +
, 'StartingDate' = @StartDate
, 'ThruDate' = @EndDate

Aug 11 '05 #1
2 5956
You don't need the non-column expressions in the GROUP BY list. Column
aliases aren't permitted either. Try:

GROUP BY statecd, countycd, zip, Z.cityname, Z.statecode, Z.countyname

David Portas
SQL Server MVP

Aug 11 '05 #2
Here is how a SELECT works in SQL ... at least in theory. Real
products will optimize things, but the code has to produce the same

a) Start in the FROM clause and build a working table from all of the
joins, unions, intersections, and whatever other table constructors are
there. The <table expression> AS <correlation name> option allows you
give a name to this working table which you then have to use for the
rest of the containing query.

b) Go to the WHERE clause and remove rows that do not pass criteria;
that is, that do not test to TRUE (i.e. reject UNKNOWN and FALSE). The
WHERE clause is applied to the working set in the FROM clause.

c) Go to the optional GROUP BY clause, make groups and reduce each
group to a single row, replacing the original working table with the
new grouped table. The rows of a grouped table must be group
characteristics: (1) a grouping column (2) a statistic about the group
(i.e. aggregate functions) (3) a function or (4) an expression made up
those three items.

d) Go to the optional HAVING clause and apply it against the grouped
working table; if there was no GROUP BY clause, treat the entire table
as one group.

e) Go to the SELECT clause and construct the expressions in the list.
This means that the scalar subqueries, function calls and expressions
in the SELECT are done after all the other clauses are done. The
"AS" operator can also give names to expressions in the SELECT
list. These new names come into existence all at once, but after the
WHERE clause, GROUP BY clause and HAVING clause has been executed; you
cannot use them in the SELECT list or the WHERE clause for that reason.
If there is a SELECT DISTINCT, then redundant duplicate rows are
removed. For purposes of defining a duplicate row, NULLs are treated
as matching (just like in the GROUP BY).

f) Nested query expressions follow the usual scoping rules you would
expect from a block structured language like C, Pascal, Algol, etc.
Namely, the innermost queries can reference columns and tables in the
queries in which they are contained.

g) The ORDER BY clause is part of a cursor, not a query. The result
set is passed to the cursor, which can only see the names in the SELECT
clause list, and the sorting is done there. The ORDER BY clause cannot
have expression in it, or references to other columns because the
result set has been converted into a sequential file structure and that
is what is being sorted.

As you can see, things happen "all at once" in SQL, not "from left to
right" as they would in a sequential file/procedural language model. In
those languages, these two statements produce different results:
READ (a, b, c) FROM File_X;
READ (c, a, b) FROM File_X;

while these two statements return the same data:

SELECT a, b, c FROM Table_X;
SELECT c, a, b FROM Table_X;

Think about what a confused mess this statement is in the SQL model.

SELECT f(c2) AS c1, f(c1) AS c2 FROM Foobar;

That is why such nonsense is illegal syntax.

Aug 14 '05 #3

This thread has been closed and replies have been disabled. Please start a new discussion.

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