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UPGENT HELP

table 1

APP_ID
1
3

table 2

APP_ID Profile_NUM
1 001AAA
2 001AAA
3 001AAA
1 000A223
2 000A223
1 01A345
2 01A345
1 0909
3 0909
5 BASS1
6 BASS1
7 BASS1


I would Like to perform the following:
. read table 1
. match table 1 against table 2, using App_ID column, and return
the following Profile_Num from table 2:
. 0909 - exact match
. 001AAA - close matches
. 000A223 - close match
. 01A345 - close match

THANKS!

(POSTED AGAIN FOR CORRECTION)
Jul 20 '05 #1
7 1850
> I would Like to perform the following:
. read table 1
. match table 1 against table 2, using App_ID column, and return
the following Profile_Num from table 2:
. 0909 - exact match
. 001AAA - close matches
. 000A223 - close match
. 01A345 - close match
I'm not sure I understand your match criteria. The example below may be
part of a solution though.

CREATE TABLE Table1
(
APP_ID int NOT NULL
CONSTRAINT PK_Table1 PRIMARY KEY,
)

CREATE TABLE Table2
(
APP_ID int NOT NULL,
Profile_NUM varchar(10) NOT NULL,
CONSTRAINT PK_Table2 PRIMARY KEY(APP_ID,Prof ile_NUM)
)

INSERT INTO Table1
SELECT 1 UNION ALL
SELECT 3

INSERT INTO Table2
SELECT 1, '001AAA' UNION ALL
SELECT 2, '001AAA' UNION ALL
SELECT 3, '001AAA' UNION ALL
SELECT 1, '000A223' UNION ALL
SELECT 2, '000A223' UNION ALL
SELECT 1, '01A345' UNION ALL
SELECT 2, '01A345' UNION ALL
SELECT 1, '0909' UNION ALL
SELECT 3, '0909' UNION ALL
SELECT 5, 'BASS1' UNION ALL
SELECT 6, 'BASS1' UNION ALL
SELECT 7, 'BASS1'

SELECT DISTINCT
MatchingProfile s.Profile_NUM,
CASE
WHEN MatchingProfile s.ProfileCount = AllProfiles.Pro fileCount
THEN 'exact match'
WHEN MatchingProfile s.ProfileCount = (SELECT COUNT(*) FROM Table1)
THEN 'close matches'
ELSE 'close match' END
FROM
(
SELECT Profile_NUM, COUNT(*) AS ProfileCount
FROM Table2
GROUP BY Profile_NUM
) AS AllProfiles
JOIN
(
SELECT Profile_NUM, COUNT(*) AS ProfileCount
FROM Table1 t1
JOIN Table2 t2 ON
t1.APP_ID = t2.APP_ID
GROUP BY Profile_NUM
) AS MatchingProfile s ON
AllProfiles.Pro file_NUM = MatchingProfile s.Profile_NUM

--
Hope this helps.

Dan Guzman
SQL Server MVP

"OBJECT MODULE, INC." <gr*********@ya hoo.com> wrote in message
news:99******** *************** ***@posting.goo gle.com... table 1

APP_ID
1
3

table 2

APP_ID Profile_NUM
1 001AAA
2 001AAA
3 001AAA
1 000A223
2 000A223
1 01A345
2 01A345
1 0909
3 0909
5 BASS1
6 BASS1
7 BASS1


I would Like to perform the following:
. read table 1
. match table 1 against table 2, using App_ID column, and return
the following Profile_Num from table 2:
. 0909 - exact match
. 001AAA - close matches
. 000A223 - close match
. 01A345 - close match

THANKS!

(POSTED AGAIN FOR CORRECTION)

Jul 20 '05 #2
Dan, tks. I will study this code and see if it's doable.

"Dan Guzman" <da*******@nosp am-earthlink.net> wrote in message news:<de******* ******@newsread 1.news.atl.eart hlink.net>...
I would Like to perform the following:
. read table 1
. match table 1 against table 2, using App_ID column, and return
the following Profile_Num from table 2:
. 0909 - exact match
. 001AAA - close matches
. 000A223 - close match
. 01A345 - close match


I'm not sure I understand your match criteria. The example below may be
part of a solution though.

CREATE TABLE Table1
(
APP_ID int NOT NULL
CONSTRAINT PK_Table1 PRIMARY KEY,
)

CREATE TABLE Table2
(
APP_ID int NOT NULL,
Profile_NUM varchar(10) NOT NULL,
CONSTRAINT PK_Table2 PRIMARY KEY(APP_ID,Prof ile_NUM)
)

INSERT INTO Table1
SELECT 1 UNION ALL
SELECT 3

INSERT INTO Table2
SELECT 1, '001AAA' UNION ALL
SELECT 2, '001AAA' UNION ALL
SELECT 3, '001AAA' UNION ALL
SELECT 1, '000A223' UNION ALL
SELECT 2, '000A223' UNION ALL
SELECT 1, '01A345' UNION ALL
SELECT 2, '01A345' UNION ALL
SELECT 1, '0909' UNION ALL
SELECT 3, '0909' UNION ALL
SELECT 5, 'BASS1' UNION ALL
SELECT 6, 'BASS1' UNION ALL
SELECT 7, 'BASS1'

SELECT DISTINCT
MatchingProfile s.Profile_NUM,
CASE
WHEN MatchingProfile s.ProfileCount = AllProfiles.Pro fileCount
THEN 'exact match'
WHEN MatchingProfile s.ProfileCount = (SELECT COUNT(*) FROM Table1)
THEN 'close matches'
ELSE 'close match' END
FROM
(
SELECT Profile_NUM, COUNT(*) AS ProfileCount
FROM Table2
GROUP BY Profile_NUM
) AS AllProfiles
JOIN
(
SELECT Profile_NUM, COUNT(*) AS ProfileCount
FROM Table1 t1
JOIN Table2 t2 ON
t1.APP_ID = t2.APP_ID
GROUP BY Profile_NUM
) AS MatchingProfile s ON
AllProfiles.Pro file_NUM = MatchingProfile s.Profile_NUM

--
Hope this helps.

Dan Guzman
SQL Server MVP

"OBJECT MODULE, INC." <gr*********@ya hoo.com> wrote in message
news:99******** *************** ***@posting.goo gle.com...
table 1

APP_ID
1
3

table 2

APP_ID Profile_NUM
1 001AAA
2 001AAA
3 001AAA
1 000A223
2 000A223
1 01A345
2 01A345
1 0909
3 0909
5 BASS1
6 BASS1
7 BASS1


I would Like to perform the following:
. read table 1
. match table 1 against table 2, using App_ID column, and return
the following Profile_Num from table 2:
. 0909 - exact match
. 001AAA - close matches
. 000A223 - close match
. 01A345 - close match

THANKS!

(POSTED AGAIN FOR CORRECTION)

Jul 20 '05 #3
could not quite the result. let's try this again:

Table 1
ID
1
3

TABLE 2
ID PROFILE_NUM
1 AA1
1 AA2
1 AA3
1 AA7
2 AA2
2 AA3
3 AA1
3 AA2
3 AA7
4 AA9
4 AA8

WOULD TO TO SEE THIS RESULT:
AA1 - Exact Match
AA2 - Close Match
AA3 - Close Match
AA7 - Exact Match

g2**********@ya hoo.com (OBJECT MODULE, INC.) wrote in message ne3ws:<99****** *************** *****@posting.g oogle.com>...
Dan, tks. I will study this code and see if it's doable.

"Dan Guzman" <da*******@nosp am-earthlink.net> wrote in message news:<de******* ******@newsread 1.news.atl.eart hlink.net>...
I would Like to perform the following:
. read table 1
. match table 1 against table 2, using App_ID column, and return
the following Profile_Num from table 2:
. 0909 - exact match
. 001AAA - close matches
. 000A223 - close match
. 01A345 - close match


I'm not sure I understand your match criteria. The example below may be
part of a solution though.

CREATE TABLE Table1
(
APP_ID int NOT NULL
CONSTRAINT PK_Table1 PRIMARY KEY,
)

CREATE TABLE Table2
(
APP_ID int NOT NULL,
Profile_NUM varchar(10) NOT NULL,
CONSTRAINT PK_Table2 PRIMARY KEY(APP_ID,Prof ile_NUM)
)

INSERT INTO Table1
SELECT 1 UNION ALL
SELECT 3

INSERT INTO Table2
SELECT 1, '001AAA' UNION ALL
SELECT 2, '001AAA' UNION ALL
SELECT 3, '001AAA' UNION ALL
SELECT 1, '000A223' UNION ALL
SELECT 2, '000A223' UNION ALL
SELECT 1, '01A345' UNION ALL
SELECT 2, '01A345' UNION ALL
SELECT 1, '0909' UNION ALL
SELECT 3, '0909' UNION ALL
SELECT 5, 'BASS1' UNION ALL
SELECT 6, 'BASS1' UNION ALL
SELECT 7, 'BASS1'

SELECT DISTINCT
MatchingProfile s.Profile_NUM,
CASE
WHEN MatchingProfile s.ProfileCount = AllProfiles.Pro fileCount
THEN 'exact match'
WHEN MatchingProfile s.ProfileCount = (SELECT COUNT(*) FROM Table1)
THEN 'close matches'
ELSE 'close match' END
FROM
(
SELECT Profile_NUM, COUNT(*) AS ProfileCount
FROM Table2
GROUP BY Profile_NUM
) AS AllProfiles
JOIN
(
SELECT Profile_NUM, COUNT(*) AS ProfileCount
FROM Table1 t1
JOIN Table2 t2 ON
t1.APP_ID = t2.APP_ID
GROUP BY Profile_NUM
) AS MatchingProfile s ON
AllProfiles.Pro file_NUM = MatchingProfile s.Profile_NUM

--
Hope this helps.

Dan Guzman
SQL Server MVP

"OBJECT MODULE, INC." <gr*********@ya hoo.com> wrote in message
news:99******** *************** ***@posting.goo gle.com...
table 1

APP_ID
1
3

table 2

APP_ID Profile_NUM
1 001AAA
2 001AAA
3 001AAA
1 000A223
2 000A223
1 01A345
2 01A345
1 0909
3 0909
5 BASS1
6 BASS1
7 BASS1


I would Like to perform the following:
. read table 1
. match table 1 against table 2, using App_ID column, and return
the following Profile_Num from table 2:
. 0909 - exact match
. 001AAA - close matches
. 000A223 - close match
. 01A345 - close match

THANKS!

(POSTED AGAIN FOR CORRECTION)

Jul 20 '05 #4
Try:

SELECT
MatchingProfile s.Profile_NUM,
CASE
WHEN MatchingProfile s.ProfileCount = AllProfiles.Pro fileCount
THEN 'exact match'
ELSE 'close match' END
FROM
(
SELECT Profile_NUM, COUNT(*) AS ProfileCount
FROM Table2
GROUP BY Profile_NUM
) AS AllProfiles
JOIN
(
SELECT Profile_NUM, COUNT(*) AS ProfileCount
FROM Table1 t1
JOIN Table2 t2 ON
t1.APP_ID = t2.APP_ID
GROUP BY Profile_NUM
) AS MatchingProfile s ON
AllProfiles.Pro file_NUM = MatchingProfile s.Profile_NUM

--
Hope this helps.

Dan Guzman
SQL Server MVP

"OBJECT MODULE, INC." <gr*********@ya hoo.com> wrote in message
news:99******** *************** ***@posting.goo gle.com...
could not quite the result. let's try this again:

Table 1
ID
1
3

TABLE 2
ID PROFILE_NUM
1 AA1
1 AA2
1 AA3
1 AA7
2 AA2
2 AA3
3 AA1
3 AA2
3 AA7
4 AA9
4 AA8

WOULD TO TO SEE THIS RESULT:
AA1 - Exact Match
AA2 - Close Match
AA3 - Close Match
AA7 - Exact Match

g2**********@ya hoo.com (OBJECT MODULE, INC.) wrote in message

ne3ws:<99****** *************** *****@posting.g oogle.com>...
Dan, tks. I will study this code and see if it's doable.

"Dan Guzman" <da*******@nosp am-earthlink.net> wrote in message news:<de******* ******@newsread 1.news.atl.eart hlink.net>...
> I would Like to perform the following:
> . read table 1
> . match table 1 against table 2, using App_ID column, and return
> the following Profile_Num from table 2:
> . 0909 - exact match
> . 001AAA - close matches
> . 000A223 - close match
> . 01A345 - close match

I'm not sure I understand your match criteria. The example below may be part of a solution though.

CREATE TABLE Table1
(
APP_ID int NOT NULL
CONSTRAINT PK_Table1 PRIMARY KEY,
)

CREATE TABLE Table2
(
APP_ID int NOT NULL,
Profile_NUM varchar(10) NOT NULL,
CONSTRAINT PK_Table2 PRIMARY KEY(APP_ID,Prof ile_NUM)
)

INSERT INTO Table1
SELECT 1 UNION ALL
SELECT 3

INSERT INTO Table2
SELECT 1, '001AAA' UNION ALL
SELECT 2, '001AAA' UNION ALL
SELECT 3, '001AAA' UNION ALL
SELECT 1, '000A223' UNION ALL
SELECT 2, '000A223' UNION ALL
SELECT 1, '01A345' UNION ALL
SELECT 2, '01A345' UNION ALL
SELECT 1, '0909' UNION ALL
SELECT 3, '0909' UNION ALL
SELECT 5, 'BASS1' UNION ALL
SELECT 6, 'BASS1' UNION ALL
SELECT 7, 'BASS1'

SELECT DISTINCT
MatchingProfile s.Profile_NUM,
CASE
WHEN MatchingProfile s.ProfileCount = AllProfiles.Pro fileCount
THEN 'exact match'
WHEN MatchingProfile s.ProfileCount = (SELECT COUNT(*) FROM Table1) THEN 'close matches'
ELSE 'close match' END
FROM
(
SELECT Profile_NUM, COUNT(*) AS ProfileCount
FROM Table2
GROUP BY Profile_NUM
) AS AllProfiles
JOIN
(
SELECT Profile_NUM, COUNT(*) AS ProfileCount
FROM Table1 t1
JOIN Table2 t2 ON
t1.APP_ID = t2.APP_ID
GROUP BY Profile_NUM
) AS MatchingProfile s ON
AllProfiles.Pro file_NUM = MatchingProfile s.Profile_NUM

--
Hope this helps.

Dan Guzman
SQL Server MVP

"OBJECT MODULE, INC." <gr*********@ya hoo.com> wrote in message
news:99******** *************** ***@posting.goo gle.com...
> table 1
>
> APP_ID
> 1
> 3
>
>
>
> table 2
>
> APP_ID Profile_NUM
> 1 001AAA
> 2 001AAA
> 3 001AAA
> 1 000A223
> 2 000A223
> 1 01A345
> 2 01A345
> 1 0909
> 3 0909
> 5 BASS1
> 6 BASS1
> 7 BASS1
>
>
>
>
> I would Like to perform the following:
> . read table 1
> . match table 1 against table 2, using App_ID column, and return
> the following Profile_Num from table 2:
> . 0909 - exact match
> . 001AAA - close matches
> . 000A223 - close match
> . 01A345 - close match
>
> THANKS!
>
> (POSTED AGAIN FOR CORRECTION)

Jul 20 '05 #5
Worked like an expert. Thanks Dan!
"Dan Guzman" <da*******@nosp am-earthlink.net> wrote in message news:<0e******* ********@newsre ad1.news.atl.ea rthlink.net>...
Try:

SELECT
MatchingProfile s.Profile_NUM,
CASE
WHEN MatchingProfile s.ProfileCount = AllProfiles.Pro fileCount
THEN 'exact match'
ELSE 'close match' END
FROM
(
SELECT Profile_NUM, COUNT(*) AS ProfileCount
FROM Table2
GROUP BY Profile_NUM
) AS AllProfiles
JOIN
(
SELECT Profile_NUM, COUNT(*) AS ProfileCount
FROM Table1 t1
JOIN Table2 t2 ON
t1.APP_ID = t2.APP_ID
GROUP BY Profile_NUM
) AS MatchingProfile s ON
AllProfiles.Pro file_NUM = MatchingProfile s.Profile_NUM

--
Hope this helps.

Dan Guzman
SQL Server MVP

"OBJECT MODULE, INC." <gr*********@ya hoo.com> wrote in message
news:99******** *************** ***@posting.goo gle.com...
could not quite the result. let's try this again:

Table 1
ID
1
3

TABLE 2
ID PROFILE_NUM
1 AA1
1 AA2
1 AA3
1 AA7
2 AA2
2 AA3
3 AA1
3 AA2
3 AA7
4 AA9
4 AA8

WOULD TO TO SEE THIS RESULT:
AA1 - Exact Match
AA2 - Close Match
AA3 - Close Match
AA7 - Exact Match

g2**********@ya hoo.com (OBJECT MODULE, INC.) wrote in message

ne3ws:<99****** *************** *****@posting.g oogle.com>...
Dan, tks. I will study this code and see if it's doable.

"Dan Guzman" <da*******@nosp am-earthlink.net> wrote in message news:<de******* ******@newsread 1.news.atl.eart hlink.net>... > > I would Like to perform the following:
> > . read table 1
> > . match table 1 against table 2, using App_ID column, and return
> > the following Profile_Num from table 2:
> > . 0909 - exact match
> > . 001AAA - close matches
> > . 000A223 - close match
> > . 01A345 - close match
>
> I'm not sure I understand your match criteria. The example below may be > part of a solution though.
>
> CREATE TABLE Table1
> (
> APP_ID int NOT NULL
> CONSTRAINT PK_Table1 PRIMARY KEY,
> )
>
> CREATE TABLE Table2
> (
> APP_ID int NOT NULL,
> Profile_NUM varchar(10) NOT NULL,
> CONSTRAINT PK_Table2 PRIMARY KEY(APP_ID,Prof ile_NUM)
> )
>
> INSERT INTO Table1
> SELECT 1 UNION ALL
> SELECT 3
>
> INSERT INTO Table2
> SELECT 1, '001AAA' UNION ALL
> SELECT 2, '001AAA' UNION ALL
> SELECT 3, '001AAA' UNION ALL
> SELECT 1, '000A223' UNION ALL
> SELECT 2, '000A223' UNION ALL
> SELECT 1, '01A345' UNION ALL
> SELECT 2, '01A345' UNION ALL
> SELECT 1, '0909' UNION ALL
> SELECT 3, '0909' UNION ALL
> SELECT 5, 'BASS1' UNION ALL
> SELECT 6, 'BASS1' UNION ALL
> SELECT 7, 'BASS1'
>
> SELECT DISTINCT
> MatchingProfile s.Profile_NUM,
> CASE
> WHEN MatchingProfile s.ProfileCount = AllProfiles.Pro fileCount
> THEN 'exact match'
> WHEN MatchingProfile s.ProfileCount = (SELECT COUNT(*) FROM Table1) > THEN 'close matches'
> ELSE 'close match' END
> FROM
> (
> SELECT Profile_NUM, COUNT(*) AS ProfileCount
> FROM Table2
> GROUP BY Profile_NUM
> ) AS AllProfiles
> JOIN
> (
> SELECT Profile_NUM, COUNT(*) AS ProfileCount
> FROM Table1 t1
> JOIN Table2 t2 ON
> t1.APP_ID = t2.APP_ID
> GROUP BY Profile_NUM
> ) AS MatchingProfile s ON
> AllProfiles.Pro file_NUM = MatchingProfile s.Profile_NUM
>
> --
> Hope this helps.
>
> Dan Guzman
> SQL Server MVP
>
>
>
> "OBJECT MODULE, INC." <gr*********@ya hoo.com> wrote in message
> news:99******** *************** ***@posting.goo gle.com...
> > table 1
> >
> > APP_ID
> > 1
> > 3
> >
> >
> >
> > table 2
> >
> > APP_ID Profile_NUM
> > 1 001AAA
> > 2 001AAA
> > 3 001AAA
> > 1 000A223
> > 2 000A223
> > 1 01A345
> > 2 01A345
> > 1 0909
> > 3 0909
> > 5 BASS1
> > 6 BASS1
> > 7 BASS1
> >
> >
> >
> >
> > I would Like to perform the following:
> > . read table 1
> > . match table 1 against table 2, using App_ID column, and return
> > the following Profile_Num from table 2:
> > . 0909 - exact match
> > . 001AAA - close matches
> > . 000A223 - close match
> > . 01A345 - close match
> >
> > THANKS!
> >
> > (POSTED AGAIN FOR CORRECTION)

Jul 20 '05 #6
"Dan Guzman" <da*******@nosp am-earthlink.net> wrote in message
news:0e******** *******@newsrea d1.news.atl.ear thlink.net...
Try:

SELECT
MatchingProfile s.Profile_NUM,
CASE
WHEN MatchingProfile s.ProfileCount = AllProfiles.Pro fileCount
THEN 'exact match'
ELSE 'close match' END
FROM
(
SELECT Profile_NUM, COUNT(*) AS ProfileCount
FROM Table2
GROUP BY Profile_NUM
) AS AllProfiles
JOIN
(
SELECT Profile_NUM, COUNT(*) AS ProfileCount
FROM Table1 t1
JOIN Table2 t2 ON
t1.APP_ID = t2.APP_ID
GROUP BY Profile_NUM
) AS MatchingProfile s ON
AllProfiles.Pro file_NUM = MatchingProfile s.Profile_NUM
Dan, please note that you have to additionally check that
AllProfiles.Pro fileCount = (SELECT COUNT(*) FROM Table1)
when testing for an exact match. For example, given the sample data,
if AA7 is only associated with 1 or 3, but not both and with no other id,
then it should not be an exact match but a close match.

Regards,
jag
--
Hope this helps.

Dan Guzman
SQL Server MVP

"OBJECT MODULE, INC." <gr*********@ya hoo.com> wrote in message
news:99******** *************** ***@posting.goo gle.com...
could not quite the result. let's try this again:

Table 1
ID
1
3

TABLE 2
ID PROFILE_NUM
1 AA1
1 AA2
1 AA3
1 AA7
2 AA2
2 AA3
3 AA1
3 AA2
3 AA7
4 AA9
4 AA8

WOULD TO TO SEE THIS RESULT:
AA1 - Exact Match
AA2 - Close Match
AA3 - Close Match
AA7 - Exact Match

g2**********@ya hoo.com (OBJECT MODULE, INC.) wrote in message

ne3ws:<99****** *************** *****@posting.g oogle.com>...
Dan, tks. I will study this code and see if it's doable.

"Dan Guzman" <da*******@nosp am-earthlink.net> wrote in message news:<de******* ******@newsread 1.news.atl.eart hlink.net>... > > I would Like to perform the following:
> > . read table 1
> > . match table 1 against table 2, using App_ID column, and return
> > the following Profile_Num from table 2:
> > . 0909 - exact match
> > . 001AAA - close matches
> > . 000A223 - close match
> > . 01A345 - close match
>
> I'm not sure I understand your match criteria. The example below may be > part of a solution though.
>
> CREATE TABLE Table1
> (
> APP_ID int NOT NULL
> CONSTRAINT PK_Table1 PRIMARY KEY,
> )
>
> CREATE TABLE Table2
> (
> APP_ID int NOT NULL,
> Profile_NUM varchar(10) NOT NULL,
> CONSTRAINT PK_Table2 PRIMARY KEY(APP_ID,Prof ile_NUM)
> )
>
> INSERT INTO Table1
> SELECT 1 UNION ALL
> SELECT 3
>
> INSERT INTO Table2
> SELECT 1, '001AAA' UNION ALL
> SELECT 2, '001AAA' UNION ALL
> SELECT 3, '001AAA' UNION ALL
> SELECT 1, '000A223' UNION ALL
> SELECT 2, '000A223' UNION ALL
> SELECT 1, '01A345' UNION ALL
> SELECT 2, '01A345' UNION ALL
> SELECT 1, '0909' UNION ALL
> SELECT 3, '0909' UNION ALL
> SELECT 5, 'BASS1' UNION ALL
> SELECT 6, 'BASS1' UNION ALL
> SELECT 7, 'BASS1'
>
> SELECT DISTINCT
> MatchingProfile s.Profile_NUM,
> CASE
> WHEN MatchingProfile s.ProfileCount = AllProfiles.Pro fileCount
> THEN 'exact match'
> WHEN MatchingProfile s.ProfileCount = (SELECT COUNT(*) FROM Table1) > THEN 'close matches'
> ELSE 'close match' END
> FROM
> (
> SELECT Profile_NUM, COUNT(*) AS ProfileCount
> FROM Table2
> GROUP BY Profile_NUM
> ) AS AllProfiles
> JOIN
> (
> SELECT Profile_NUM, COUNT(*) AS ProfileCount
> FROM Table1 t1
> JOIN Table2 t2 ON
> t1.APP_ID = t2.APP_ID
> GROUP BY Profile_NUM
> ) AS MatchingProfile s ON
> AllProfiles.Pro file_NUM = MatchingProfile s.Profile_NUM
>
> --
> Hope this helps.
>
> Dan Guzman
> SQL Server MVP
>
>
>
> "OBJECT MODULE, INC." <gr*********@ya hoo.com> wrote in message
> news:99******** *************** ***@posting.goo gle.com...
> > table 1
> >
> > APP_ID
> > 1
> > 3
> >
> >
> >
> > table 2
> >
> > APP_ID Profile_NUM
> > 1 001AAA
> > 2 001AAA
> > 3 001AAA
> > 1 000A223
> > 2 000A223
> > 1 01A345
> > 2 01A345
> > 1 0909
> > 3 0909
> > 5 BASS1
> > 6 BASS1
> > 7 BASS1
> >
> >
> >
> >
> > I would Like to perform the following:
> > . read table 1
> > . match table 1 against table 2, using App_ID column, and return
> > the following Profile_Num from table 2:
> > . 0909 - exact match
> > . 001AAA - close matches
> > . 000A223 - close match
> > . 01A345 - close match
> >
> > THANKS!
> >
> > (POSTED AGAIN FOR CORRECTION)


Jul 20 '05 #7
> Dan, please note that you have to additionally check that
AllProfiles.Pro fileCount = (SELECT COUNT(*) FROM Table1)
when testing for an exact match. For example, given the sample data,
if AA7 is only associated with 1 or 3, but not both and with no other id,
then it should not be an exact match but a close match.
Thanks for catching this, John. I only tested with the provided sample data
and didn't notice that all conditions weren't tested.

SELECT
MatchingProfile s.Profile_NUM,
CASE
WHEN MatchingProfile s.ProfileCount = AllProfiles.Pro fileCount AND
AllProfiles.Pro fileCount = (SELECT COUNT(*) FROM Table1)
THEN 'exact match'
ELSE 'close match' END
FROM
(
SELECT Profile_NUM, COUNT(*) AS ProfileCount
FROM Table2
GROUP BY Profile_NUM
) AS AllProfiles
JOIN
(
SELECT Profile_NUM, COUNT(*) AS ProfileCount
FROM Table1 t1
JOIN Table2 t2 ON
t1.APP_ID = t2.APP_ID
GROUP BY Profile_NUM
) AS MatchingProfile s ON
AllProfiles.Pro file_NUM = MatchingProfile s.Profile_NUM
--
Hope this helps.

Dan Guzman
SQL Server MVP

"John Gilson" <ja*@acm.org> wrote in message
news:sW******** *************@t wister.nyc.rr.c om... "Dan Guzman" <da*******@nosp am-earthlink.net> wrote in message
news:0e******** *******@newsrea d1.news.atl.ear thlink.net...
Try:

SELECT
MatchingProfile s.Profile_NUM,
CASE
WHEN MatchingProfile s.ProfileCount = AllProfiles.Pro fileCount
THEN 'exact match'
ELSE 'close match' END
FROM
(
SELECT Profile_NUM, COUNT(*) AS ProfileCount
FROM Table2
GROUP BY Profile_NUM
) AS AllProfiles
JOIN
(
SELECT Profile_NUM, COUNT(*) AS ProfileCount
FROM Table1 t1
JOIN Table2 t2 ON
t1.APP_ID = t2.APP_ID
GROUP BY Profile_NUM
) AS MatchingProfile s ON
AllProfiles.Pro file_NUM = MatchingProfile s.Profile_NUM


Dan, please note that you have to additionally check that
AllProfiles.Pro fileCount = (SELECT COUNT(*) FROM Table1)
when testing for an exact match. For example, given the sample data,
if AA7 is only associated with 1 or 3, but not both and with no other id,
then it should not be an exact match but a close match.

Regards,
jag
--
Hope this helps.

Dan Guzman
SQL Server MVP

"OBJECT MODULE, INC." <gr*********@ya hoo.com> wrote in message
news:99******** *************** ***@posting.goo gle.com...
could not quite the result. let's try this again:

Table 1
ID
1
3

TABLE 2
ID PROFILE_NUM
1 AA1
1 AA2
1 AA3
1 AA7
2 AA2
2 AA3
3 AA1
3 AA2
3 AA7
4 AA9
4 AA8

WOULD TO TO SEE THIS RESULT:
AA1 - Exact Match
AA2 - Close Match
AA3 - Close Match
AA7 - Exact Match

g2**********@ya hoo.com (OBJECT MODULE, INC.) wrote in message

ne3ws:<99****** *************** *****@posting.g oogle.com>...
> Dan, tks. I will study this code and see if it's doable.
>
>
>
> "Dan Guzman" <da*******@nosp am-earthlink.net> wrote in message

news:<de******* ******@newsread 1.news.atl.eart hlink.net>...
> > > I would Like to perform the following:
> > > . read table 1
> > > . match table 1 against table 2, using App_ID column, and return
> > > the following Profile_Num from table 2:
> > > . 0909 - exact match
> > > . 001AAA - close matches
> > > . 000A223 - close match
> > > . 01A345 - close match
> >
> > I'm not sure I understand your match criteria. The example below may
be
> > part of a solution though.
> >
> > CREATE TABLE Table1
> > (
> > APP_ID int NOT NULL
> > CONSTRAINT PK_Table1 PRIMARY KEY,
> > )
> >
> > CREATE TABLE Table2
> > (
> > APP_ID int NOT NULL,
> > Profile_NUM varchar(10) NOT NULL,
> > CONSTRAINT PK_Table2 PRIMARY KEY(APP_ID,Prof ile_NUM)
> > )
> >
> > INSERT INTO Table1
> > SELECT 1 UNION ALL
> > SELECT 3
> >
> > INSERT INTO Table2
> > SELECT 1, '001AAA' UNION ALL
> > SELECT 2, '001AAA' UNION ALL
> > SELECT 3, '001AAA' UNION ALL
> > SELECT 1, '000A223' UNION ALL
> > SELECT 2, '000A223' UNION ALL
> > SELECT 1, '01A345' UNION ALL
> > SELECT 2, '01A345' UNION ALL
> > SELECT 1, '0909' UNION ALL
> > SELECT 3, '0909' UNION ALL
> > SELECT 5, 'BASS1' UNION ALL
> > SELECT 6, 'BASS1' UNION ALL
> > SELECT 7, 'BASS1'
> >
> > SELECT DISTINCT
> > MatchingProfile s.Profile_NUM,
> > CASE
> > WHEN MatchingProfile s.ProfileCount =

AllProfiles.Pro fileCount > > THEN 'exact match'
> > WHEN MatchingProfile s.ProfileCount = (SELECT COUNT(*) FROM

Table1)
> > THEN 'close matches'
> > ELSE 'close match' END
> > FROM
> > (
> > SELECT Profile_NUM, COUNT(*) AS ProfileCount
> > FROM Table2
> > GROUP BY Profile_NUM
> > ) AS AllProfiles
> > JOIN
> > (
> > SELECT Profile_NUM, COUNT(*) AS ProfileCount
> > FROM Table1 t1
> > JOIN Table2 t2 ON
> > t1.APP_ID = t2.APP_ID
> > GROUP BY Profile_NUM
> > ) AS MatchingProfile s ON
> > AllProfiles.Pro file_NUM = MatchingProfile s.Profile_NUM
> >
> > --
> > Hope this helps.
> >
> > Dan Guzman
> > SQL Server MVP
> >
> >
> >
> > "OBJECT MODULE, INC." <gr*********@ya hoo.com> wrote in message
> > news:99******** *************** ***@posting.goo gle.com...
> > > table 1
> > >
> > > APP_ID
> > > 1
> > > 3
> > >
> > >
> > >
> > > table 2
> > >
> > > APP_ID Profile_NUM
> > > 1 001AAA
> > > 2 001AAA
> > > 3 001AAA
> > > 1 000A223
> > > 2 000A223
> > > 1 01A345
> > > 2 01A345
> > > 1 0909
> > > 3 0909
> > > 5 BASS1
> > > 6 BASS1
> > > 7 BASS1
> > >
> > >
> > >
> > >
> > > I would Like to perform the following:
> > > . read table 1
> > > . match table 1 against table 2, using App_ID column, and return
> > > the following Profile_Num from table 2:
> > > . 0909 - exact match
> > > . 001AAA - close matches
> > > . 000A223 - close match
> > > . 01A345 - close match
> > >
> > > THANKS!
> > >
> > > (POSTED AGAIN FOR CORRECTION)



Jul 20 '05 #8

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