Combining Columns and Grouping By....

[JackT]

Hi,
I have the following SQL

SELECT Table1.Col1, Table3.Col1 AS Expr1,
COUNT(Table1.Co l2) AS Col2_No, COUNT(Table1.Co l3) AS Col3_No etc,
FROM Table3
INNER JOIN Table2 ON Table3.Col1=Tab le2.Col1
RIGHT OUTER JOIN Table1 ON Table2.Col2=Tab le2.Col2
GROUP BY Table1.Col1, Table3.Col1

The output rows have a value in either Table1.Col1 or Table3.Col1 but not
both.
I'd like to combine Table1.Col1 and Table3.Col1 and group by the combined
column in the result but don't know how.
Thanks gratefully

[John Bell]

Hi

It would help if you posted the DDL (Create Table Statements) , example data
(as insert statements) and expected output. From your description it is not
100% clear how the tables relate or what results you expect.

If the values of Col1 are unique between each table your solution might be:

SELECT Col1, COUNT(Col2) as Col2No, COUNT(Col3) as Col3No
FROM Table1
GROUP BY Col1
UNION
SELECT Col1, COUNT(Col2) as Col2No, COUNT(Col3) as Col3No
FROM Table3
GROUP BY Col1

If not

SELECT IsNULL(T1.Col1, T3.Col1), COUNT(CASE WHEN T1.Col1 IS NULL THEN T1.Col2
ELSE T3.Col2 END ) AS Col2No, COUNT(CASE WHEN T1.Col1 IS NULL THEN T1.Col3
ELSE T3.Col3 END ) AS Col3No
FROM Table1 T1
LEFT JOIN Table3 T3 ON T1.Col2 = T3.Col2
GROUP BY IsNULL(T1.Col1, T3.Col1)

or more probably

SELECT Col1, SUM(Col2No) as Col2No, SUM(Col3No) as Col3No
FROM (
SELECT Col1, COUNT(Col2) as Col2No, COUNT(Col3) as Col3No
FROM Table1
GROUP BY Col1
UNION
SELECT Col1, COUNT(Col2) as Col2No, COUNT(Col3) as Col3No
FROM Table3
GROUP BY Col1 ) A
GROUP BY Col1

John
"JackT" <tu***********@ ntlworld.com> wrote in message
news:ov******** **********@news fep2-win.server.ntli .net...

Hi,
I have the following SQL

SELECT Table1.Col1, Table3.Col1 AS Expr1,
COUNT(Table1.Co l2) AS Col2_No, COUNT(Table1.Co l3) AS Col3_No etc,
FROM Table3
INNER JOIN Table2 ON Table3.Col1=Tab le2.Col1
RIGHT OUTER JOIN Table1 ON Table2.Col2=Tab le2.Col2
GROUP BY Table1.Col1, Table3.Col1

The output rows have a value in either Table1.Col1 or Table3.Col1 but not
both.
I'd like to combine Table1.Col1 and Table3.Col1 and group by the combined
column in the result but don't know how.
Thanks gratefully

[JackT]

Thanks John,
I didn't explain too well so I'll detail tables, releationships and what I'm
trying to do. I have managed to reduce & simplify the issue to two tables:-

Targets table which has columns:
target id - key identity autoincrement integer
locationid - integer

Actions table which has columns:
actionid - key identity autoincrement integer
targetid - integer
locationid integer

relationship is Targets RIGHT OUTER JOIN Actions ON Targets.targeti d =
Actions.targeti d (I want results from all rows in Actions).

I want to count all rows from Actions and group by locationid combined from
both tables.

Targets content:
targetid locationid
1 1
2 1

Actions Content:
actionid targetid locationid
1 NULL 1
2 NULL 2
3 NULL 3
4 1 NULL
5 1 NULL
6 2 NULL

If I use:
SELECT Actions.locatio nid, Targets.locatio nid, COUNT(actionid) AS actions
FROM Targets RIGHT JOIN Actions ON Targets.targeti d = Actions.target id
GROUP BY Actions.locatio nid, Targets.locatio nid

I get:
Actions Actions.locatio nid Targets.locatio nid
1 1 NULL
1 2 NULL
1 3 NULL
3 NULL 1

I want to combine both locationid columns in result giving:
Actions locationid
4 1
1 2
1 3

There are more columns than illustrated but if you the above can be cracked,
I'll be away!
Cheers,
Jack

"John Bell" <jb************ @hotmail.com> wrote in message
news:3f******** *************** @news.easynet.c o.uk...

Hi

It would help if you posted the DDL (Create Table Statements) , example data (as insert statements) and expected output. From your description it is not 100% clear how the tables relate or what results you expect.

If the values of Col1 are unique between each table your solution might be:
SELECT Col1, COUNT(Col2) as Col2No, COUNT(Col3) as Col3No
FROM Table1
GROUP BY Col1
UNION
SELECT Col1, COUNT(Col2) as Col2No, COUNT(Col3) as Col3No
FROM Table3
GROUP BY Col1

If not

SELECT IsNULL(T1.Col1, T3.Col1), COUNT(CASE WHEN T1.Col1 IS NULL THEN T1.Col2 ELSE T3.Col2 END ) AS Col2No, COUNT(CASE WHEN T1.Col1 IS NULL THEN T1.Col3
ELSE T3.Col3 END ) AS Col3No
FROM Table1 T1
LEFT JOIN Table3 T3 ON T1.Col2 = T3.Col2
GROUP BY IsNULL(T1.Col1, T3.Col1)

or more probably

SELECT Col1, SUM(Col2No) as Col2No, SUM(Col3No) as Col3No
FROM (
SELECT Col1, COUNT(Col2) as Col2No, COUNT(Col3) as Col3No
FROM Table1
GROUP BY Col1
UNION
SELECT Col1, COUNT(Col2) as Col2No, COUNT(Col3) as Col3No
FROM Table3
GROUP BY Col1 ) A
GROUP BY Col1

John

[JackT]

John,

Thanks for putting me on the right track. With ref to the example in my
reply post I used:

SELECT ISNULL(Actions. locationid, Targets.locatio nid) AS Location,
COUNT(Actions.a ctionid) AS Actions_No
FROM Actions LEFT OUTER JOIN
Targets ON Actions.targeti d = Targets.targeti d
GROUP BY ISNULL(Actions. locationid, Targets.locatio nid)

All the other columns I want to count are in the Actions table so I just
need to add them to the SELECT statement.
Thanks again,
Jack

"JackT" <tu***********@ ntlworld.com> wrote in message
news:Fu******** ***********@new sfep2-win.server.ntli .net...

Thanks John,
I didn't explain too well so I'll detail tables, releationships and what I'm trying to do. I have managed to reduce & simplify the issue to two tables:-
Targets table which has columns:
target id - key identity autoincrement integer
locationid - integer

Actions table which has columns:
actionid - key identity autoincrement integer
targetid - integer
locationid integer

relationship is Targets RIGHT OUTER JOIN Actions ON Targets.targeti d =
Actions.targeti d (I want results from all rows in Actions).

I want to count all rows from Actions and group by locationid combined from both tables.

Targets content:
targetid locationid
1 1
2 1

Actions Content:
actionid targetid locationid
1 NULL 1
2 NULL 2
3 NULL 3
4 1 NULL
5 1 NULL
6 2 NULL

If I use:
SELECT Actions.locatio nid, Targets.locatio nid, COUNT(actionid) AS actions
FROM Targets RIGHT JOIN Actions ON Targets.targeti d = Actions.target id
GROUP BY Actions.locatio nid, Targets.locatio nid

I get:
Actions Actions.locatio nid Targets.locatio nid
1 1 NULL
1 2 NULL
1 3 NULL
3 NULL 1

I want to combine both locationid columns in result giving:
Actions locationid
4 1
1 2
1 3

There are more columns than illustrated but if you the above can be cracked, I'll be away!
Cheers,
Jack

[John Bell]

Hi

It sounds like it worked then!

Here is usable DDL and example data in case you need it again.

create table Targets (
targetid integer NOT NULL identity (1,1) CONSTRAINT PK_Targets PRIMARY KEY,
locationid integer,
)

create table Actions (
actionid integer NOT NULL identity (1,1) CONSTRAINT PK_Actions PRIMARY KEY,
targetid integer NULL,
locationid integer,
CONSTRAINT FK_Actions FOREIGN KEY (TargetId) REFERENCES Targets(TargetI d)
)

INSERT INTO Targets (locationid) VALUES (1)
INSERT INTO Targets (locationid) VALUES (1)

INSERT INTO Actions (targetid, locationid) VALUES (NULL,1)
INSERT INTO Actions (targetid, locationid) VALUES (NULL,2)
INSERT INTO Actions (targetid, locationid) VALUES (NULL,3)
INSERT INTO Actions (targetid, locationid) VALUES (1,NULL)
INSERT INTO Actions (targetid, locationid) VALUES (1,NULL)
INSERT INTO Actions (targetid, locationid) VALUES (2,NULL)

SELECT * FROM Targets

/*
targetid locationid
----------- -----------
1 1
2 1

(2 row(s) affected)
*/
SELECT * FROM Actions

/*
actionid targetid locationid
----------- ----------- -----------
1 NULL 1
2 NULL 2
3 NULL 3
4 1 NULL
5 1 NULL
6 2 NULL

(6 row(s) affected)
*/

-- Your attempt
SELECT A.locationid, T.locationid, COUNT(A.actioni d) AS actions
FROM Targets T RIGHT JOIN Actions A ON T.targetid = A.targetid
GROUP BY A.locationid, T.locationid

/*
locationid locationid actions
----------- ----------- -----------
1 NULL 1
2 NULL 1
3 NULL 1
NULL 1 3

(4 row(s) affected)
*/

-- Your second attempt
SELECT ISNULL(A.locati onid, T.locationid) AS Location,
COUNT(A.actioni d) AS Actions_No
FROM Actions A LEFT OUTER JOIN Targets T ON A.targetid = T.targetid
GROUP BY ISNULL(A.locati onid, T.locationid)

/* Gives
Location Actions_No
----------- -----------
1 4
2 1
3 1

(3 row(s) affected)
*/
John

"JackT" <tu***********@ ntlworld.com> wrote in message
news:49******** ***********@new sfep2-win.server.ntli .net...

John,

Thanks for putting me on the right track. With ref to the example in my
reply post I used:

SELECT ISNULL(Actions. locationid, Targets.locatio nid) AS Location,
COUNT(Actions.a ctionid) AS Actions_No
FROM Actions LEFT OUTER JOIN
Targets ON Actions.targeti d = Targets.targeti d
GROUP BY ISNULL(Actions. locationid, Targets.locatio nid)

All the other columns I want to count are in the Actions table so I just
need to add them to the SELECT statement.
Thanks again,
Jack

"JackT" <tu***********@ ntlworld.com> wrote in message
news:Fu******** ***********@new sfep2-win.server.ntli .net...

Thanks John,
I didn't explain too well so I'll detail tables, releationships and what

I'm

trying to do. I have managed to reduce & simplify the issue to two

tables:-

Targets table which has columns:
target id - key identity autoincrement integer
locationid - integer

Actions table which has columns:
actionid - key identity autoincrement integer
targetid - integer
locationid integer

relationship is Targets RIGHT OUTER JOIN Actions ON Targets.targeti d =
Actions.targeti d (I want results from all rows in Actions).

I want to count all rows from Actions and group by locationid combined

from

both tables.

Targets content:
targetid locationid
1 1
2 1

Actions Content:
actionid targetid locationid
1 NULL 1
2 NULL 2
3 NULL 3
4 1 NULL
5 1 NULL
6 2 NULL

If I use:
SELECT Actions.locatio nid, Targets.locatio nid, COUNT(actionid) AS actions FROM Targets RIGHT JOIN Actions ON Targets.targeti d = Actions.target id
GROUP BY Actions.locatio nid, Targets.locatio nid

I get:
Actions Actions.locatio nid Targets.locatio nid
1 1 NULL
1 2 NULL
1 3 NULL
3 NULL 1

I want to combine both locationid columns in result giving:
Actions locationid
4 1
1 2
1 3

There are more columns than illustrated but if you the above can be

cracked,

I'll be away!
Cheers,
Jack

[JackT]

Thanks John,
Appreciate your informative close-out post and will certainly file for
reference.
Cheers,
Jack

"John Bell" <jb************ @hotmail.com> wrote in message
news:3f******** *************** @news.easynet.c o.uk...

Hi

It sounds like it worked then!

Here is usable DDL and example data in case you need it again.

create table Targets (
targetid integer NOT NULL identity (1,1) CONSTRAINT PK_Targets PRIMARY KEY, locationid integer,
)

create table Actions (
actionid integer NOT NULL identity (1,1) CONSTRAINT PK_Actions PRIMARY KEY, targetid integer NULL,
locationid integer,
CONSTRAINT FK_Actions FOREIGN KEY (TargetId) REFERENCES Targets(TargetI d)
)

INSERT INTO Targets (locationid) VALUES (1)
INSERT INTO Targets (locationid) VALUES (1)

INSERT INTO Actions (targetid, locationid) VALUES (NULL,1)
INSERT INTO Actions (targetid, locationid) VALUES (NULL,2)
INSERT INTO Actions (targetid, locationid) VALUES (NULL,3)
INSERT INTO Actions (targetid, locationid) VALUES (1,NULL)
INSERT INTO Actions (targetid, locationid) VALUES (1,NULL)
INSERT INTO Actions (targetid, locationid) VALUES (2,NULL)

SELECT * FROM Targets

/*
targetid locationid
----------- -----------
1 1
2 1

(2 row(s) affected)
*/
SELECT * FROM Actions

/*
actionid targetid locationid
----------- ----------- -----------
1 NULL 1
2 NULL 2
3 NULL 3
4 1 NULL
5 1 NULL
6 2 NULL

(6 row(s) affected)
*/

-- Your attempt
SELECT A.locationid, T.locationid, COUNT(A.actioni d) AS actions
FROM Targets T RIGHT JOIN Actions A ON T.targetid = A.targetid
GROUP BY A.locationid, T.locationid

/*
locationid locationid actions
----------- ----------- -----------
1 NULL 1
2 NULL 1
3 NULL 1
NULL 1 3

(4 row(s) affected)
*/

-- Your second attempt
SELECT ISNULL(A.locati onid, T.locationid) AS Location,
COUNT(A.actioni d) AS Actions_No
FROM Actions A LEFT OUTER JOIN Targets T ON A.targetid = T.targetid
GROUP BY ISNULL(A.locati onid, T.locationid)

/* Gives
Location Actions_No
----------- -----------
1 4
2 1
3 1

(3 row(s) affected)
*/
John