Multiple conditions in a single IF

[Gonzalo Gonza]

I want to know whether a number is a multiple of 2 and/or 5
But Python doesn't let me put lots of things after the '=='

Here's my code:

def asdf(n):
    n=str(m)
    if n==2:
        a=True
    elif n==5:
        a=True
    elif m[-1:]==2 or 4 or 6 or 8 or 0 or 5:
        a=True

I also tried:

elif m[-1:]==2, 4, 6, 8, 0, 5:

But it doesn't make sense

I wish you could help me
Thank you

PS: I know that the program don't make any sense but that's not the real purpose, it's just to simplify.

[bvdet]

To determine if a variable is a multiple of 2 or 5, use the modulo operator.

>>> m = 12
>>> m % 2
 
>>> m % 5
2
>>> if not m % 2:
...     print "m is a multiple of 2"
...     
m is a multiple of 2
>>> 

To check multiple conditions in one statement:

>>> m = 15
>>> if not m % 2 or not m % 5:
...     print "m is a multiple of 2 or m is a multiple of 5"
...     
m is a multiple of 2 or m is a multiple of 5
>>> not m % 2 or not m % 5
True
>>> not m % 2
False
>>> not m % 5
True
>>> 

A variable can also be checked for membership:

>>> m in [3,6,9,12,15]
True
>>> 

[Gonzalo Gonza]

Thank you, but I forgot to say that this funcion will recieve huge numbers, and the method with the module would be very inefficient.

[Oralloy]

@Gonzalo Gonza - build composite conditions, something like this:

def asdf(n):
  if (((n % 2) == 0) or ((n % 5) == 0)):
    result = True
  else:
    result = False
 
def fdsa(n)
  result = (((n % 2) == 0) or ((n % 5) == 0))
 

If I've a syntax error, please forgive me; I'm looking at python and trying to learn.

[dwblas]

Note that the variable "m" in not known to the function

def asdf(n):
    n=str(m)

Also

    elif m[-1:]==2 or 4 or 6 or 8 or 0 or 5:
#
#   m would have to be a string or list to do a [-1], so compare 
#   to strings  (compare to integers is m is a list of integers)
    elif m[-1] in ['2', '4', '6', '8', '0', '5']: 

[2, 4, 6, 8, 0, 5] should give you all numbers divisible by 2 or 5, I think.