what is wrong with my python code?

[Dongsheng Ruan]

I got feed back saying" list object is not callable". But I can't figure out
what is wrong with my code.

A=[3,5,4,9,6,7]
l=len(A)-1

for i in range(l):
print A(i)

[Paul Rubin]

"Dongsheng Ruan" <ru**@jcmills.comwrites:

for i in range(l):
print A(i)

Use square brackets, A[i].

Usually we'd write such a loop like this:

for x in A:
print x

[Pierre GM]

On Wednesday 07 February 2007 12:43:34 Dongsheng Ruan wrote:

I got feed back saying" list object is not callable". But I can't figure
out what is wrong with my code.

for i in range(l):
print A(i)

You're calling A, when you want to access one of its elements: use the
straight brackets [

for i in range(l):
print A[i]

[Bruno Desthuilliers]

Dongsheng Ruan a écrit :

I got feed back saying" list object is not callable". But I can't figure out
what is wrong with my code.

A=[3,5,4,9,6,7]
l=len(A)-1

for i in range(l):
print A(i)

The error message is quite clear when you remember that () is the call
operator. For the subscribe operator, you want [].

And FWIW, Python for loops are smarter than that:
A = [3,5,4,9,6,7]
for i in A:
print i

[John Machin]

On Feb 8, 4:43 am, "Dongsheng Ruan" <[e-mail]:

I got feed back saying" list object is not callable". But I can't figure out
what is wrong with my code.

A=[3,5,4,9,6,7]
l=len(A)-1

for i in range(l):
print A(i)

What the others said, *plus*:

(1) you are subtracting 1 off the length, so after the change from ()
to [], the last item would not be printed.

(2) have you considered working through a tutorial?

Cheers,
John