How to get indices of a two dimensional list

[sramaswamy]

I have a list

x = [0] * 2
x = x * [2]
x[1,1] = 7

This gives me the x value
[[0,0] [0,0] [0,0] [0,7]]

I want to get the indices of the value 7.
i.e. something like
i = a.index(max(a)) gives me '1'

This only gives me the index in one dimension. Is there any method by
which I can get (1,1) as the answer.

Thanks in advance.

[Simon Forman]

sr********@gmail.com wrote:

I have a list

x = [0] * 2
x = x * [2]
You're certainly not doing that.

x = [0] * 2
x = x * [2] Traceback (most recent call last):
File "<stdin>", line 1, in ?
TypeError: can't multiply sequence by non-int
And even if you *do* do what it looks like you think you want to do x = [[0] * 2] * 2
x [[0, 0], [0, 0]]

...you don't get what you think you'd get..

So, let's say you do this x[1][1] = 7
x [[0, 7], [0, 7], [0, 7], [0, 7]]

... still not what you thought
x = [[0] * 2] * 4
x

[[0, 0], [0, 0], [0, 0], [0, 0]]

x[1,1] = 7

This gives me the x value
[[0,0] [0,0] [0,0] [0,7]]

I want to get the indices of the value 7.
i.e. something like
i = a.index(max(a)) gives me '1'

This only gives me the index in one dimension. Is there any method by
which I can get (1,1) as the answer.
When you sort out what you're actually trying to do, the answer to your
question may be in this thread:
http://groups.google.ca/group/comp.l...925504b2a4eb4a

Thanks in advance.

Hope this helps,
~Simon

[Gerard Flanagan]

sr********@gmail.com wrote:

I have a list

x = [0] * 2
x = x * [2]
x[1,1] = 7

This gives me the x value
[[0,0] [0,0] [0,0] [0,7]]

I want to get the indices of the value 7.
i.e. something like
i = a.index(max(a)) gives me '1'

This only gives me the index in one dimension. Is there any method by
which I can get (1,1) as the answer.

Thanks in advance.

If you post code that doesn't work, people won't treat you seriously.
I have some code that might help if you'd like to try again.

All the best

Gerard

[Gerard Flanagan]

Gerard Flanagan wrote:

sr********@gmail.com wrote:

I have a list

x = [0] * 2
x = x * [2]
x[1,1] = 7

This gives me the x value
[[0,0] [0,0] [0,0] [0,7]]

I want to get the indices of the value 7.
i.e. something like
i = a.index(max(a)) gives me '1'

This only gives me the index in one dimension. Is there any method by
which I can get (1,1) as the answer.

Thanks in advance.

If you post code that doesn't work, people won't treat you seriously.
I have some code that might help if you'd like to try again.

All the best

Ok, that was mean-spirited. The code is below - it's related to
another problem but maybe it can be adapted to your own. Good luck!

def irows(n):
i=0
while True:
yield divmod(i,n)
i += 1

x = [0,0,0,7,0,0,0,0]

d = dict(zip(enumerate(x), irows(2)))

assert d[x.index(7),7] == (1,1)
assert d[x.index(0),0] == (0,0)

d = dict(zip(irows(2),x))

assert d[1,1] == 7

sudoku = dict(zip(irows(9),[[0]]*81))