working on a program that takes a file and determines what type it is. It must be a .wav or .jpg file to be correct, and if it is not one of those, it will display a message that says to choose a correct file type. However, I am stuck on how to get it to determine what type of file is being chosen, since for this program I am not allowed to use f.endswith()
I have tried something like this but it is giving me a syntax error for the line "if f[f.rfind:] == '.wav':" i am not sure what the error is here, could you help me with what the issue may be? - def fileType():
-
f = pickAFile
-
print f
-
print "File Type:", f[f.rfind('.'):]
-
if f[f.rfind('.'):] == '.wav':
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print "A sound file was selected."
-
if f[f.rfind('.'):] == '.jpg' :
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print "An image file was selected
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else:
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print " This was an incorrect file type."
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print " Please chose a .wav or .jpg file."
2  1331  dwblas 626
Recognized Expert Contributor
Assuming that you identify a file by the name ending, I always use endswith() or if fname[-4:]==. Note that the variable, pickAFile, may not be known to the function unless it is a global variable.
yes i know that endswith() would work best but it is not allowed in this program. How would I go about fixing what I have above?
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