Hi, I am very new to the python web applications. can some one help.
I have a python application with some functions in it.
1) The application reads an input file ( say, IN.txt).
the IN.txt file contains names of three other files( x.dat, y.txt, z.dat) that are
in the same directory.
2) then the application reads the data in the files x.dat, y.txt, z.dat and performs some calculations.
3) outputs the results in a file called out.txt
The application is running perfectly from command mode. I need to make it a web application so that it can be run in a browser from anywhere.
I tried with cherrypy and django tutorials, but could not succeed, as i am completely new to this field. can some one help with steps to proceed.
Your help is highly appreciated.
Thanks in advance!
Susanne
13  3561  kudos 127
Recognized Expert New Member
It sound like what you need is a cgi-script. This is luckily quite simple.
here is a template: -
#!/usr/bin/python
-
-
import os
-
import cgi
-
-
print "Content-Type: text/plain\n\n"
-
-
# your script here...
-
print "hi how are you!"
-
Ofcourse there are some details:
1. the file should not have an .py extension, but rather a .cgi extension
2. the file should have the correct properties (i.e. chmod a+x <filename.cgi >)
3. it should be placed in a "cgi-bin" directory (under your www folder)
4. then you would access it like http://www.yourdomain.com/cgi-bin/yourpythonfile.cgi
(It sound like you were planning to do this in a unix enviroment)
There are multiple other options, but this one is quite simple.
-kudos
Frinavale 9,735
Recognized Expert Moderator Expert
I'm just going to add a bit to Kudos's answer.
The output that your python script should produce should be HTML since it's going to be displayed in a web browser.
I would recommend keeping a clear separation between your current logic and the HTML or else it can get very messy to read.
Make a function that builds the HTML so that it's easier to understand what's going on.
For example: -
#!/usr/bin/python
-
-
import os
-
import cgi
-
-
def getfileoutput():
-
# This is where you grab the data from the files
-
-
def output(fileoutput = ""):
-
#This produces the HTML that is to be sent to the browser
-
htmlOutput = '<html>'
-
htmlOutput += ' <head>'
-
htmlOutput += ' <title></title>'
-
htmlOutput += ' </head>'
-
htmlOutput += ' <body>'
-
htmlOutput += ' <div>'
-
htmlOutput += fileoutput
-
htmlOutput += ' </div>'
-
htmlOutput += ' </body>'
-
htmlOutput += '</html>'
-
return htmlOutput
-
-
print output(getfileoutput())
kudos 127
Recognized Expert New Member
That is very true! however do not forget this part: -
print "Content-Type: text/plain\n\n"
-
-kudos @Frinavale
Hi kudos and Frinavale,
Thanks a lot for your quick responses!
I did followed the steps as you suggested.
1) I inserted my complete python script in between line numbers 21 and 23 of Frinavale's code in the reply. after that i also inserted the "Content-Type" as Kudos suggested.
2) I renamed the file with .cgi extenstion.
3) I kept the .cgi file under the cgi-bin directory.
( Windows-XP/program files/apache 2.2/cgi-bin)
4) I copied the other files also to the same directory( In.txt, x.dat, y.txt, z.dat)
as the python script needed them.
when i executed the code in internet explorer or mozilla firefox http://localhost/cgi-bin/hi.cgi http://localhost:80/cgi-bin/hi.cgi
either I am getting
file not found error
OR
Internal Server Error: The server encountered an internal error or misconfiguratio n and was unable to complete your request.
When I check http://localhost:80 Then the server shows "It Is Working"
I am confused. Did I do some thing wrong with hte code. Or do I need to add anything else.
Please suggest me
Thanks
Susanne
kudos 127
Recognized Expert New Member
Ok, I see there is an apache server on a windows platform. Then you would need to find out how (and if) it is configured for python and cgi. You would also need be sure that the various files (.cgi) and (cgi-bin) directory is have the correct access rights.
However, I have an alternative solution for you, python has a built in webserver! -
from BaseHTTPServer import BaseHTTPRequestHandler, HTTPServer
-
-
class myserver(BaseHTTPRequestHandler):
-
def do_GET(self):
-
self.send_response(200)
-
self.send_header("content-type","text/html")
-
self.end_headers()
-
self.wfile.write("your output as a html-string here...")
-
return
-
try:
-
s = HTTPServer(('',2606),myserver)
-
s.serve_forever()
-
except KeyboardInterrupt:
-
s.socket_close()
-
Now, type http://localhost:2606 in your browser to see the webserver in action
-kudos @susanne
HI kudos, thanks a lot again for your help
I tried configuring apache server to be able to work with cgi as well.
And I tried with the built-in server script you have provided.
The server is running but i can see only
" your output as a html-string here..." in the browser.
I tried even this simple cgi script (hi.cgi) to execute
( http://localhost:2606/hi.cgi )
but i see only the same message as above.
#!/usr/bin/python
import os
import cgi
print "Content-Type: text/plain\n\n"
print "hello!"
 kudos 127
Recognized Expert New Member
Hi,
what you should do is the following:
place your program between : -
self.end_headers()
-
-- your program here ---
-
return
-
then use the following to output from your program: -
self.wfile.write("your output as a html-string here...")
-
I have created a simple example, that does something, and later puts it to the webbrowser -
from BaseHTTPServer import BaseHTTPRequestHandler, HTTPServer
-
-
class myserver(BaseHTTPRequestHandler):
-
def do_GET(self):
-
self.send_response(200)
-
self.send_header("content-type","text/html")
-
self.end_headers()
-
-
# this code do 'something'
-
-
html=""
-
for i in range(32):
-
html+="<tr>"
-
for j in range(32):
-
html+="<td bgcolor=\""+hex(int(((j^i) / 64.0)*256))+"\"></td> </td>"
-
html+="</tr>"
-
-
# writes all to string called html
-
-
html = "<html></body><table border=\"0\" cellspacing=\"0\" cellpadding=\"0\" width=\"100%\" height=\"100%\">" +html+"</table></body></html>"
-
-
# writes to the screen/webclient
-
-
self.wfile.write(html)
-
return
-
-
try:
-
s = HTTPServer(('',2606),myserver)
-
s.serve_forever()
-
except KeyboardInterrupt:
-
s.socket_close()
-
Please note, this webserver doesn't have the features of a normal webserver, but is more intended to do the following:
1. do some kind of calculations (read files, add numbers etc, etc)
2. display it to a webbrowser (as a webserver)
(PS. to set ut apache for cgi-script, if I remeber correctly you would need to change something called scriptalias)
-kudos @susanne
I am reading in bytes from a hdd image (dd). I want to look for the header of a JPEG (FFD8 4a 46 49 46) and replace all the bytes before the footer (FFD9) with 0. My questions is: How can I make a change to the original file stream?
kudos 127
Recognized Expert New Member
First, I happen to have done some jpeg work earlier, are you sure that your header is correct? (I thought it was a bit longer) anyway, here is some code to get you started: -
import os
-
import stat
-
f = file('yourimage.jpg', 'rb')
-
-
pat = [0xFF,0xD8,0xff,0xe0,0x0,0x10,0x4a,0x46,0x49,0x46] # i thought that this was the pattern...
-
pati = 0
-
-
s = os.stat('yourimage')
-
size = s[stat.ST_SIZE]
-
for i in range(size):
-
v = f.read(1)
-
if(pati > len(pat)):
-
if(v == pat[pati]):
-
pati+=1
-
else:
-
pati=0
-
else:
-
if(i < size - 2):
-
# write the 0's here or simillar (then you would need to write 'ab' instead above
-
pass
-
f.close()
-
-kudos @martinscott Sign in to post your reply or Sign up for a free account.
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