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Unable to start a process with subprocess Popen()

Hi,

I'm using the subprocess module's Popen() to start a batch file. This
batch file basically calls an exe which also gets started.
Unfortunately, this does not produce any results. I looked into the
Task bar that this exe has started but it does not consume and cpu so
I believet that this exe is not working.
I used the following command to start the batch fiile:

testing = subprocess.Pope n([batchFilePath], \
shell = True, \
stdout = subprocess.PIPE , \
stderr = subprocess.PIPE ).communicate()[0]
batchFilePath is the path of the batch file.

--
Regrads,
Rajat
Sep 8 '08 #1
0 814

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