RE: How to round a floating point to nearest 10?

[Edwin.Madari]

>>round(76.1, -2)
100.0

>>round(76.1, -1)

80.0

>>round(76.1)

76.0

>>

builtin function round, will work for you......
Help on built-in function round in module __builtin__:
round(...)
round(number[, ndigits]) -floating point number

Round a number to a given precision in decimal digits (default 0 digits).
This always returns a floating point number. Precision may be negative.

good luck..
Edwin

-----Original Message-----
From: py************* *************** *************** *******@python. org
[mailto:py****** *************** *************** **************@ python.org]
On Behalf Of John Machin
Sent: Saturday, August 09, 2008 5:54 PM
To: py*********@pyt hon.org
Subject: Re: How to round a floating point to nearest 10?
On Aug 10, 1:19 am, Mensanator <mensana...@aol .comwrote:

On Aug 9, 6:31 am, Will Rocisky <geekm...@gmail .comwrote:

I want my 76.1 to be rounded to decimal 80 and 74.9 to decimal 70.
How can I achieve that?

>print '%.0e' % 74.9

7e+01

>print '%.0e' % 76.1

8e+01

But:

>>print '%.0e' % 176.1

2e+002

Giving the Subject ("How to round a floating point to nearest 10?"),
there's a strong presumption that the OP would want the answer to be
180, not 200.
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