Hi,
Hi,
I am taking a string as an input from the user and it should only
contain the chars:L , M or R
I tried the folllowing in kodos but they are still not perfect:
[^A-K,^N-Q,^S-Z,^0-9]
[L][M][R]
[LRM]?L?[LRM]? etc but they do not exactly meet what I need.
For eg: LRLRLRLRLM is ok but LRLRLRNL is not as it has 'N' .like that.
regards,
SZ
The string may or may not have all the three chars.
20  1938 
On Jul 18, 8:33 pm, arnimavidyar... @gmail.com wrote:
Hi,
Hi,
I am taking a string as an input from the user and it should only
contain the chars:L , M or R
I tried the folllowing in kodos but they are still not perfect:
[^A-K,^N-Q,^S-Z,^0-9]
[L][M][R]
[LRM]?L?[LRM]? etc but they do not exactly meet what I need.
For eg: LRLRLRLRLM is ok but LRLRLRNL is not as it has 'N' .like that.
regards,
SZ
The string may or may not have all the three chars.
re.match(r'[LMR]+\Z', your_string)
in English: one or more of L, M , or R, followed by the end of the
string.
On Jul 18, 11:33*am, arnimavidyar... @gmail.com wrote:
Hi,
Hi,
I am taking a string as an input from the user and it should only
contain the chars:L , M or R
I tried the folllowing in kodos but they are still not perfect:
[^A-K,^N-Q,^S-Z,^0-9]
[L][M][R]
[LRM]?L?[LRM]? etc but they do not exactly meet what I need.
For eg: LRLRLRLRLM is ok but LRLRLRNL is not as it has 'N' .like that.
regards,
SZ
The string may or may not have all the three chars.
With regular expressions, [^LRM] matches a character that isn't L, R
or M. So:
import re
var = "LRLRLRLNR"
if re.search(r'[^LRM]', var):
print "Invalid"
On Jul 18, 9:05 pm, oj <ojee...@gmail. comwrote:
On Jul 18, 11:33 am, arnimavidyar... @gmail.com wrote:
Hi,
Hi,
I am taking a string as an input from the user and it should only
contain the chars:L , M or R
I tried the folllowing in kodos but they are still not perfect:
[^A-K,^N-Q,^S-Z,^0-9]
[L][M][R]
[LRM]?L?[LRM]? etc but they do not exactly meet what I need.
For eg: LRLRLRLRLM is ok but LRLRLRNL is not as it has 'N' .like that.
regards,
SZ
The string may or may not have all the three chars.
With regular expressions, [^LRM] matches a character that isn't L, R
or M. So:
import re
var = "LRLRLRLNR"
if re.search(r'[^LRM]', var):
print "Invalid"
Fails if var refers to the empty string.
On Jul 18, 12:10*pm, John Machin <sjmac...@lexic on.netwrote:
On Jul 18, 9:05 pm, oj <ojee...@gmail. comwrote:
On Jul 18, 11:33 am, arnimavidyar... @gmail.com wrote:
Hi,
Hi,
I am taking a string as an input from the user and it should only
contain the chars:L , M or R
I tried the folllowing in kodos but they are still not perfect:
[^A-K,^N-Q,^S-Z,^0-9]
[L][M][R]
[LRM]?L?[LRM]? etc but they do not exactly meet what I need.
For eg: LRLRLRLRLM is ok but LRLRLRNL is not as it has 'N' .like that..
regards,
SZ
The string may or may not have all the three chars.
With regular expressions, [^LRM] matches a character that isn't L, R
or M. So:
import re
var = "LRLRLRLNR"
if re.search(r'[^LRM]', var):
* * print "Invalid"
Fails if var refers to the empty string.
No it doesn't, it succeeds if var is an empty string. An empty string
doesn't contain characters that are not L, R or M.
The OP doesn't specify whether an empty string is valid or not. My
interpretation was that an empty string would be valid.
oj wrote:
On Jul 18, 12:10 pm, John Machin <sjmac...@lexic on.netwrote:
>On Jul 18, 9:05 pm, oj <ojee...@gmail. comwrote:
>>On Jul 18, 11:33 am, arnimavidyar... @gmail.com wrote:
Hi,
Hi,
I am taking a string as an input from the user and it should only
contain the chars:L , M or R
I tried the folllowing in kodos but they are still not perfect:
[^A-K,^N-Q,^S-Z,^0-9]
[L][M][R]
[LRM]?L?[LRM]? etc but they do not exactly meet what I need.
For eg: LRLRLRLRLM is ok but LRLRLRNL is not as it has 'N' .like that.
regards,
SZ
The string may or may not have all the three chars.
With regular expressions, [^LRM] matches a character that isn't L, R
or M. So:
import re
var = "LRLRLRLNR"
if re.search(r'[^LRM]', var):
print "Invalid"
Fails if var refers to the empty string.
No it doesn't, it succeeds if var is an empty string. An empty string
doesn't contain characters that are not L, R or M.
The OP doesn't specify whether an empty string is valid or not. My
interpretation was that an empty string would be valid.
Why not just use * instead of + like:
if re.search(r'^[^LRM]*$', var): # note: ^ outside [] is start of string; $ means end of string
print "Invalid"
This will *only* print invalid when there is a character other than L, R, or M or a empty string.
Andrew Freeman wrote:
oj wrote:
>On Jul 18, 12:10 pm, John Machin <sjmac...@lexic on.netwrote:
>>On Jul 18, 9:05 pm, oj <ojee...@gmail. comwrote:
On Jul 18, 11:33 am, arnimavidyar... @gmail.com wrote:
Hi,
Hi,
I am taking a string as an input from the user and it
should only
contain the chars:L , M or R
I tried the folllowing in kodos but they are still not
perfect:
[^A-K,^N-Q,^S-Z,^0-9]
[L][M][R]
[LRM]?L?[LRM]? etc but they do not exactly meet what I need.
For eg: LRLRLRLRLM is ok but LRLRLRNL is not as it has 'N'
.like that.
regards,
SZ
The string may or may not have all the three chars.
>
With regular expressions, [^LRM] matches a character that isn't L, R
or M. So:
import re
var = "LRLRLRLNR"
if re.search(r'[^LRM]', var):
print "Invalid"
Fails if var refers to the empty string.
No it doesn't, it succeeds if var is an empty string. An empty string
doesn't contain characters that are not L, R or M.
The OP doesn't specify whether an empty string is valid or not. My
interpretati on was that an empty string would be valid.
Why not just use * instead of + like:
if re.search(r'^[^LRM]*$', var): # note: ^ outside [] is start of
string; $ means end of string
print "Invalid"
This will *only* print invalid when there is a character other than L,
R, or M or a empty string.
Sorry, forget the beginning and ending markers, I just tried it out, it
doesn't work.
use this instead:
if re.search(r'[^LRM]*', var):
print "Invalid"
On Jul 18, 7:51*pm, Andrew Freeman <alif...@gmail. comwrote:
Andrew Freeman wrote:
oj wrote:
On Jul 18, 12:10 pm, John Machin <sjmac...@lexic on.netwrote:
>On Jul 18, 9:05 pm, oj <ojee...@gmail. comwrote:
>>On Jul 18, 11:33 am, arnimavidyar... @gmail.com wrote:
>>>Hi,
* * * * Hi,
* * * * I am taking a string as an input from the user and it
should only
contain the chars:L , M or R
* * * * I tried the folllowing in kodos but they are still not
perfect:
* * * * [^A-K,^N-Q,^S-Z,^0-9]
[L][M][R]
[LRM]?L?[LRM]? etc but they do not exactly meet what I need.
* * * * For eg: LRLRLRLRLM is ok but LRLRLRNL is not as it has 'N'
.like that.
* * * * regards,
SZ
* * * * The string may or may not have all the three chars.
>>With regular expressions, [^LRM] matches a character that isn't L, R
or M. So:
* * * import re
* * * var = "LRLRLRLNR"
* * * if re.search(r'[^LRM]', var):
* * print "Invalid"
>Fails if var refers to the empty string.
No it doesn't, it succeeds if var is an empty string. An empty string
doesn't contain characters that are not L, R or M.
The OP doesn't specify whether an empty string is valid or not. My
interpretation was that an empty string would be valid.
Why not just use * instead of + like:
if re.search(r'^[^LRM]*$', var): # note: ^ outside [] is start of
string; $ means end of string
* *print "Invalid"
This will *only* print invalid when there is a character other than L,
R, or M or a empty string.
Sorry, forget the beginning and ending markers, I just tried it out, it
doesn't work.
use this instead:
if re.search(r'[^LRM]*', var):
* *print "Invalid"
I was using kodos to check the regex.I should have used the IDE
instead.Thanks a lot again.
On Jul 18, 7:51 am, Andrew Freeman <alif...@gmail. comwrote:
Andrew Freeman wrote:
oj wrote:
On Jul 18, 12:10 pm, John Machin <sjmac...@lexic on.netwrote:
>On Jul 18, 9:05 pm, oj <ojee...@gmail. comwrote:
>>On Jul 18, 11:33 am, arnimavidyar... @gmail.com wrote:
>>>Hi,
Hi,
I am taking a string as an input from the user and it
should only
contain the chars:L , M or R
I tried the folllowing in kodos but they are still not
perfect:
[^A-K,^N-Q,^S-Z,^0-9]
[L][M][R]
[LRM]?L?[LRM]? etc but they do not exactly meet what I need.
For eg: LRLRLRLRLM is ok but LRLRLRNL is not as it has 'N'
.like that.
regards,
SZ
The string may or may not have all the three chars.
>>With regular expressions, [^LRM] matches a character that isn't L, R
or M. So:
import re
var = "LRLRLRLNR"
if re.search(r'[^LRM]', var):
print "Invalid"
>Fails if var refers to the empty string.
No it doesn't, it succeeds if var is an empty string. An empty string
doesn't contain characters that are not L, R or M.
The OP doesn't specify whether an empty string is valid or not. My
interpretation was that an empty string would be valid.
Why not just use * instead of + like:
if re.search(r'^[^LRM]*$', var): # note: ^ outside [] is start of
string; $ means end of string
print "Invalid"
This will *only* print invalid when there is a character other than L,
R, or M or a empty string.
Sorry, forget the beginning and ending markers, I just tried it out, it
doesn't work.
use this instead:
if re.search(r'[^LRM]*', var):
print "Invalid"
This won't work -- every string in the universe contains 0 or more
characters which are not 'L', 'R', or 'M'. That is, the regular
expression X* could match the empty string, which can be found in all
strings.
>
Why not just use * instead of + like:
if re.search(r'^[^LRM]*$', var): # note: ^ outside [] is start of
string; $ means end of string
* *print "Invalid"
This will *only* print invalid when there is a character other than L,
R, or M or a empty string.
Sorry, forget the beginning and ending markers, I just tried it out, it
doesn't work.
use this instead:
if re.search(r'[^LRM]*', var):
* *print "Invalid"
No, that's broken.
That searches for any number of invalid characters. Even 0, so it
ALWAYS matches, no matter what string you give it.
My regex worked in the first place, you're complicating it needlessly.
The presence of one invalid character makes the string invalid, so why
not just search for one? Similarly, there's no need to stick in the
beginning and end markers - you're not trying to match the entire
string, just find part of it that is invalid.
However, I think the sets solution by Scott David Daniels is the most
elegant method put forward. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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