"gianluca" <ge*******@gmai l.comwrote in message
news:58******** *************** ***********@z72 g2000hsb.google groups.com...
On 30 Giu, 18:26, Jean-Paul Calderone <exar...@divmod .comwrote:
>On Mon, 30 Jun 2008 09:13:42 -0700 (PDT), gianluca <geonom...@gmai l.com>
wrote:
>I've a problem with dll function colled with python/ctypes. My
functions (C) requred a typedef int "value_type " in tree different
way:
same as value_type; - mydll.foo1(valu e_type)
same as *value_type; - mydll.foo2(*val ue_type)
same as **value_type; - mydll.foo3(**va lue_type)
>How can pass it in python. If i do that:
rules=POINTER( value_type)
opr=rsl.Streng thOfRules(rules ,10)
R=POINTER(rule s)
POINTER takes a class and returns a new class which represents a pointer
to input class.
pointer takes an instance and returns a new object which represents a
pointer to that instance.
Jean-Paul
so,
if I write this:
p=pointer(value _type)
mydll.foo1(p)
could be correct but python say me:
TypeError: _type_ must have storage info
what does mean?
thank you
gima
It means you cannot create a pointer to a type, you need to provide an
instance of a type:
>>from ctypes import *
px=pointer(c_ int)
Traceback (most recent call last):
File "<interacti ve input>", line 1, in <module>
File "C:\dev\python\ lib\ctypes\__in it__.py", line 282, in pointer
return POINTER(type(in st))(inst)
File "C:\dev\python\ lib\ctypes\__in it__.py", line 226, in POINTER
{'_type_': cls})
TypeError: _type_ must have storage info
>>x=c_int(5) # make an instance (C equiv. is "int x=5;")
px=pointer( x) # int* px = &x;
ppx=pointer(p x) # int** ppx = &px;
x
c_long(5)
>>px
<ctypes.LP_c_lo ng object at 0x00E87350>
>>ppx
<ctypes.LP_LP_c _long object at 0x00E873A0>
--Mark
