Hi,
I am using poplib's retr() to fetch mails from my gmail account. It
works fine, in some cases it gets stuck inside the retr() method and
does not come out.
From the logs I could find that when retr() is called, it stops
executing further statements, nor does it throw an exceptions but
simply stops. My code is roughly like the foll:
try:
print "1"
mymsg = M.retr(msg_no)
print "2"
except poplib.error_pr oto, e:
print "exception1 "
except Exception, e:
print "exception2 "
What can be the reason for this? Can anyone help me.
Thanks
Roopesh 2 2651
En Fri, 20 Jun 2008 04:37:32 -0300, Roopesh <ro*********@gm ail.com>
escribió:
I am using poplib's retr() to fetch mails from my gmail account. It
works fine, in some cases it gets stuck inside the retr() method and
does not come out.
Probably the server stopped responding. By default, sockets have no
timeout value set - that is, a recv() call may block forever.
Try using socket.setdefau lttimeout
<http://docs.python.org/lib/module-socket.htmlbefo re creating the
connection, or search this group for past responses to this same problem.
--
Gabriel Genellina
Thanks for the help.
At present I have modified the poplib code as follows (In POP3 and
POP3_SSL classes): Is it the correct way?
def __init__(self, host, port = POP3_PORT):
self.host = host
self.port = port
msg = "getaddrinf o returns an empty list"
self.sock = None
socket.setdefau lttimeout(30)
for res in socket.getaddri nfo(self.host, self.port, 0,
socket.SOCK_STR EAM):
af, socktype, proto, canonname, sa = res
try:
self.sock = socket.socket(a f, socktype, proto)
self.sock.conne ct(sa)
except socket.error, msg:
Thanks
Roopesh This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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