Hexadecimal: how to convert 'ED6F3C01' to "\xED\x6F\x3C\x 01" inpython coding?

[zxo102]

Hi,
how to change the hexadecimal 'ED6F3C01' (or 'ED 6F 3C 01') to
"\xED\x6F\x3C\x 01" in python coding?
When I take 'ED6F3C01' as a string and insert '\x' into it, I just got
the error information : invalid \x escape.
Thanks.

ouyang

[Sebastian 'lunar' Wiesner]

-----BEGIN PGP SIGNED MESSAGE-----
Hash: SHA1

[ zxo102 <zx****@gmail.c om]

how to change the hexadecimal 'ED6F3C01' (or 'ED 6F 3C 01') to
"\xED\x6F\x3C\x 01" in python coding?
When I take 'ED6F3C01' as a string and insert '\x' into it, I just got
the error information : invalid \x escape.

[1]--'ED6F3C01'.deco de('hex')
Out[1]: '\xedo<\x01'

- --
Freedom is always the freedom of dissenters.
(Rosa Luxemburg)
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Version: GnuPG v2.0.9 (GNU/Linux)

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[zxo102]

But this is not "\xED\x6F\x3C\x 01". I need it for
struct.unpack(' f',"\xED\x6F\x3 C\x01") to calculate the decimal value
(IEEE 754).
Any other suggestions?

ouyang

On 5ÔÂ25ÈÕ, ÉÏÎç6ʱ46·Ö, Sebastian 'lunar' Wiesner <basti.wies...@ gmx.net>
wrote:

-----BEGIN PGP SIGNED MESSAGE-----
Hash: SHA1

[ zxo102 <zxo...@gmail.c om]

how to change the hexadecimal 'ED6F3C01' (or 'ED 6F 3C 01') to
"\xED\x6F\x3C\x 01" in python coding?
When I take 'ED6F3C01' as a string and insert '\x' into it, I just got
the error information : invalid \x escape.

[1]--'ED6F3C01'.deco de('hex')
Out[1]: '\xedo<\x01'

- --
Freedom is always the freedom of dissenters.
(Rosa Luxemburg)
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Version: GnuPG v2.0.9 (GNU/Linux)

iEYEARECAAYFAkg 4mtEACgkQn3IEGI Lecb7W6ACeNwr/vavkaXluvc0zeSa 4cy1N
YFIAoJjMsrRcLhq APRxKktUqt7miMT rs
=jxll
-----END PGP SIGNATURE-----

[zxo102]

On 5ÔÂ25ÈÕ, ÉÏÎç6ʱ59·Ö, zxo102 <zxo...@gmail.c omwrote:

But this is not "\xED\x6F\x3C\x 01". I need it for
struct.unpack(' f',"\xED\x6F\x3 C\x01") to calculate the decimal value
(IEEE 754).
Any other suggestions?

ouyang

On 5ÔÂ25ÈÕ, ÉÏÎç6ʱ46·Ö, Sebastian 'lunar' Wiesner<basti.w [e-mail]>
wrote:

-----BEGIN PGP SIGNED MESSAGE-----
Hash: SHA1

[ zxo102 <zxo...@gmail.c om]

how to change the hexadecimal 'ED6F3C01' (or 'ED 6F 3C 01') to
"\xED\x6F\x3C\x 01" in python coding?
When I take 'ED6F3C01' as a string and insert '\x' into it, I just got
the error information : invalid \x escape.

[1]--'ED6F3C01'.deco de('hex')
Out[1]: '\xedo<\x01'

- --
Freedom is always the freedom of dissenters.
(Rosa Luxemburg)
-----BEGIN PGP SIGNATURE-----
Version: GnuPG v2.0.9 (GNU/Linux)

iEYEARECAAYFAkg 4mtEACgkQn3IEGI Lecb7W6ACeNwr/vavkaXluvc0zeSa 4cy1N
YFIAoJjMsrRcLhq APRxKktUqt7miMT rs
=jxll
-----END PGP SIGNATURE------ Òþ²Ø±»ÒýÓÃÎÄ×Ö -

- ÏÔʾÒýÓõÄÎÄ×Ö -

Hash: SHA1
I got it. Just simply use it like
struct.unpack(' f',"ED6F3C01".d ecode('hex')). It works now.

Thank you very much.
ouyang

[J. Clifford Dyer]

On Sat, 2008-05-24 at 15:59 -0700, zxo102 wrote:

But this is not "\xED\x6F\x3C\x 01". I need it for
struct.unpack(' f',"\xED\x6F\x3 C\x01") to calculate the decimal value
(IEEE 754).
Any other suggestions?

ouyang

In fact it is exactly the same string. The repr of a string always
substitutes ascii values for their numeric equivalent, but those bytes
are still the underlying representation of the string.

>>[hex(ord(c)) for c in "\xefo<\x01 "]

['0xef', '0x6f', '0x3c', '0x1']

Cheers,
Cliff

On 5月25日, 上�6时46分 , Sebastian 'lunar' Wiesner <basti.wies...@ gmx.net>
wrote:

-----BEGIN PGP SIGNED MESSAGE-----
Hash: SHA1

[ zxo102 <zxo...@gmail.c om]

how to change the hexadecimal 'ED6F3C01' (or 'ED 6F 3C 01') to
"\xED\x6F\x3C\x 01" in python coding?
When I take 'ED6F3C01' as a string and insert '\x' into it, I just got
the error information : invalid \x escape.

[1]--'ED6F3C01'.deco de('hex')
Out[1]: '\xedo<\x01'

- --
Freedom is always the freedom of dissenters.
(Rosa Luxemburg)
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Version: GnuPG v2.0.9 (GNU/Linux)

iEYEARECAAYFAkg 4mtEACgkQn3IEGI Lecb7W6ACeNwr/vavkaXluvc0zeSa 4cy1N
YFIAoJjMsrRcLhq APRxKktUqt7miMT rs
=jxll
-----END PGP SIGNATURE-----

--
http://mail.python.org/mailman/listinfo/python-list

[John Machin]

zxo102 wrote:

Hi,
how to change the hexadecimal 'ED6F3C01' (or 'ED 6F 3C 01') to
"\xED\x6F\x3C\x 01" in python coding?

If by "in python coding" you mean "in Python source code", then just
type it in with \x in front of each pair of hex digits, like you did above.

However if you mean e.g. how to change a data string x into a data
string y, something like this is what you want

>>import binascii
x = 'ED 6F 3C 01'
y = binascii.unhexl ify(x.replace(' ', ''))
y

'\xedo<\x01'

.... which is correct ('o' == '\x6f' and '<' == '\x3c'); see below:

>>' '.join(['%02x' % ord(c) for c in y])

'ed 6f 3c 01'

>>>len(y)

4

Does (len(y) == 4) surprise you?

When I take 'ED6F3C01' as a string and insert '\x' into it, I just got
the error information : invalid \x escape.

It's rather difficult to guess what you mean here ... insert how many
'\x'? where?? what gave you the error information??? Consider showing us
a copy/paste of exactly what you did and what was the response, like I
did above.
HTH,
John

[John Machin]

Sebastian 'lunar' Wiesner wrote:

-----BEGIN PGP SIGNED MESSAGE-----
Hash: SHA1

[ zxo102 <zx****@gmail.c om]

> how to change the hexadecimal 'ED6F3C01' (or 'ED 6F 3C 01') to
"\xED\x6F\x3C\ x01" in python coding?
When I take 'ED6F3C01' as a string and insert '\x' into it, I just got
the error information : invalid \x escape.

[1]--'ED6F3C01'.deco de('hex')
Out[1]: '\xedo<\x01'

FWIW the 'hex' codec is just a big fat Python-coded wrapper around the
routines in the C-coded binascii module; here's the evidence:

>>'123'.decode( 'hex')

Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "c:\python25\li b\encodings\hex _codec.py", line 42, in hex_decode
output = binascii.a2b_he x(input)
TypeError: Odd-length string