I'm pretty new to Python, but this has really bugged me. I can't find a
way around it.
The problem is that, when I use raw_input("sajf asjdf") whatever, or
input("dsjfadsj fa"), you can only have numerical values as answers.
Any help would be appreciated. Thanks.
7  1662 
Collin wrote:
I'm pretty new to Python, but this has really bugged me. I can't find a
way around it.
The problem is that, when I use raw_input("sajf asjdf") whatever, or
input("dsjfadsj fa"), you can only have numerical values as answers.
Any help would be appreciated. Thanks.
Oh, wow. I feel so stupid. Please disregard this message. <_<
I read the error message just now a bit more carefully, and I tried
something. I tried defining "yes" as some random numerical value. Then
when I did:
(example code)
yes = 123123983 #some number
test = input("Test test test ")
if test == yes:
print "It worked."
else:
print "failed"
(example code off)
Collin
En Mon, 12 May 2008 01:54:28 -0300, Collin <co*********@sh aw.caescribió:
Collin wrote:
>I'm pretty new to Python, but this has really bugged me. I can't find a
way around it.
The problem is that, when I use raw_input("sajf asjdf") whatever, or
input("dsjfads jfa"), you can only have numerical values as answers.
Any help would be appreciated. Thanks.
Oh, wow. I feel so stupid. Please disregard this message. <_<
No need to apologize...
I read the error message just now a bit more carefully, and I tried
something. I tried defining "yes" as some random numerical value. Then
when I did:
(example code)
yes = 123123983 #some number
test = input("Test test test ")
if test == yes:
print "It worked."
else:
print "failed"
(example code off)
The usual way for Python<3.0 is:
answer = raw_input("Test test test ").lower()
if answer == "yes":
...
The input() function evaluates user input as an expression: if he types 2+5 the input() function returns the integer 7. I would never use input() in a program - it's way too unsafe; use always raw_input instead.
--
Gabriel Genellina
Gabriel Genellina wrote:
En Mon, 12 May 2008 01:54:28 -0300, Collin <co*********@sh aw.caescribió:
>Collin wrote:
>>I'm pretty new to Python, but this has really bugged me. I can't find a
way around it.
The problem is that, when I use raw_input("sajf asjdf") whatever, or
input("dsjfad sjfa"), you can only have numerical values as answers.
Any help would be appreciated. Thanks.
Oh, wow. I feel so stupid. Please disregard this message. <_<
No need to apologize...
>I read the error message just now a bit more carefully, and I tried
something. I tried defining "yes" as some random numerical value. Then
when I did:
(example code)
yes = 123123983 #some number
test = input("Test test test ")
if test == yes:
print "It worked."
else:
print "failed"
(example code off)
The usual way for Python<3.0 is:
answer = raw_input("Test test test ").lower()
if answer == "yes":
...
The input() function evaluates user input as an expression: if he types 2+5 the input() function returns the integer 7. I would never use input() in a program - it's way too unsafe; use always raw_input instead.
If I use it like that, do I have to import anything to have the .lower()
work? And if I do, what does the .lower() signify?
On Wed, 14 May 2008 11:02:36 +1000, Collin <co*********@sh aw.cawrote:
Gabriel Genellina wrote:
>En Mon, 12 May 2008 01:54:28 -0300, Collin <co*********@sh aw.ca
escribió:
>>Collin wrote:
I'm pretty new to Python, but this has really bugged me. I can't find
a
way around it.
The problem is that, when I use raw_input("sajf asjdf") whatever, or
input("dsjfa dsjfa"), you can only have numerical values as answers.
Any help would be appreciated. Thanks.
Oh, wow. I feel so stupid. Please disregard this message. <_<
No need to apologize...
>>I read the error message just now a bit more carefully, and I tried
something. I tried defining "yes" as some random numerical value. Then
when I did:
(example code)
yes = 123123983 #some number
test = input("Test test test ")
if test == yes:
print "It worked."
else:
print "failed"
(example code off)
The usual way for Python<3.0 is:
answer = raw_input("Test test test ").lower()
if answer == "yes":
...
The input() function evaluates user input as an expression: if he
types 2+5 the input() function returns the integer 7. I would never use
input() in a program - it's way too unsafe; use always raw_input
instead.
If I use it like that, do I have to import anything to have the .lower()
work? And if I do, what does the .lower() signify?
--
http://mail.python.org/mailman/listinfo/python-list
You don't need to import any module to use ".lower()"; it is a method ofa
string. raw_input() returns a string, so you can use methods of a string.
Try the following statement to see what happens:
"ABCDE".low er()
--
Kam-Hung Soh <a href="http://kamhungsoh.com/blog">Software Salariman</a>
Kam-Hung Soh wrote:
On Wed, 14 May 2008 11:02:36 +1000, Collin <co*********@sh aw.cawrote:
>Gabriel Genellina wrote:
>>En Mon, 12 May 2008 01:54:28 -0300, Collin <co*********@sh aw.ca>
escribió:
Collin wrote:
I'm pretty new to Python, but this has really bugged me. I can't
find a
way around it.
>
>
The problem is that, when I use raw_input("sajf asjdf") whatever, or
input("dsjf adsjfa"), you can only have numerical values as answers.
>
Any help would be appreciated. Thanks.
Oh, wow. I feel so stupid. Please disregard this message. <_<
No need to apologize...
I read the error message just now a bit more carefully, and I tried
something. I tried defining "yes" as some random numerical value. Then
when I did:
(example code)
yes = 123123983 #some number
test = input("Test test test ")
if test == yes:
print "It worked."
else:
print "failed"
(example code off)
The usual way for Python<3.0 is:
answer = raw_input("Test test test ").lower()
if answer == "yes":
...
The input() function evaluates user input as an expression: if he
types 2+5 the input() function returns the integer 7. I would never
use input() in a program - it's way too unsafe; use always raw_input
instead.
If I use it like that, do I have to import anything to have the
.lower() work? And if I do, what does the .lower() signify?
--
http://mail.python.org/mailman/listinfo/python-list
You don't need to import any module to use ".lower()"; it is a method of
a string. raw_input() returns a string, so you can use methods of a
string.
Try the following statement to see what happens:
"ABCDE".low er()
So the .lower() string method is just to convert the string to lowercase
letters so that you don't have to type a bunch of if - then statements
in both cases, I'm assuming?
On Thu, 15 May 2008 02:36:29 GMT
Collin <co*********@sh aw.cawrote:
So the .lower() string method is just to convert the string to lowercase
letters so that you don't have to type a bunch of if - then statements
in both cases, I'm assuming?
You can also type:
dir(str)
to get a list of all the methods you can call on a string object. If you see anything interesting, then type:
help(str.<metho d_name>) # e.g. help(str.split)
to find out how it works. :)
On Thu, 15 May 2008 12:36:29 +1000, Collin <co*********@sh aw.cawrote:
Kam-Hung Soh wrote:
>On Wed, 14 May 2008 11:02:36 +1000, Collin <co*********@sh aw.cawrote:
>>Gabriel Genellina wrote:
En Mon, 12 May 2008 01:54:28 -0300, Collin <co*********@sh aw.ca
escribió:
Collin wrote:
>I'm pretty new to Python, but this has really bugged me. I can't
>find a
>way around it.
>>
>>
>The problem is that, when I use raw_input("sajf asjdf") whatever, or
>input("dsj fadsjfa"), you can only have numerical values as answers.
>>
>Any help would be appreciated. Thanks.
>
Oh, wow. I feel so stupid. Please disregard this message. <_<
No need to apologize...
I read the error message just now a bit more carefully, and I tried
something . I tried defining "yes" as some random numerical value.
Then
when I did:
(example code)
>
yes = 123123983 #some number
test = input("Test test test ")
if test == yes:
print "It worked."
else:
print "failed"
>
(example code off)
The usual way for Python<3.0 is:
answer = raw_input("Test test test ").lower()
if answer == "yes":
...
The input() function evaluates user input as an expression: if he
types 2+5 the input() function returns the integer 7. I would never
use input() in a program - it's way too unsafe; use always raw_input
instead.
If I use it like that, do I have to import anything to have the
.lower() work? And if I do, what does the .lower() signify?
-- http://mail.python.org/mailman/listinfo/python-list
You don't need to import any module to use ".lower()"; it is a method
of a string. raw_input() returns a string, so you can use methods ofa
string.
Try the following statement to see what happens:
"ABCDE".lower( )
So the .lower() string method is just to convert the string to lowercase
letters so that you don't have to type a bunch of if - then statements
in both cases, I'm assuming?
--
http://mail.python.org/mailman/listinfo/python-list
That's right. If you normalize your input to all lower case or upper
case, you make it easier to process user input.
Regards,
--
Kam-Hung Soh <a href="http://kamhungsoh.com/blog">Software Salariman</a> This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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