Following is the code in python that opens all files under a directories and puts a comma in place of whitespace, I can see the output on the command line, but I am not sure what to do in order to write the output of each file read in the directory into a separate file.
# whitespace by comma in every line
import fileinput, string, sys, os
from os.path import join
if len(sys.argv) != 2:
print "Enter: python %s input_directory " % os.path.basenam e(sys.argv[0])
sys.exit(0)
#Getting input from the command line
directory= sys.argv[1]
for root, dirs, files in os.walk(directo ry):
for name in files:
filename= os.path.join(ro ot,name)
file= open(filename, 'r')
#putting comma wherever there is occurence of whitespace in line
for line in file:
x= line.split()
str = ''
for i in x:
str+=(","+i)
str1= str.lstrip(',')
print( str1)
file.close()
Please make the changes to the above code so that if there r 3 files under the given directory it weill create 3 separate output files with the result stored in them.
1 2555 bvdet 2,851
Recognized Expert Moderator Specialist
Please use code tags when posting code. The following will open a file, read each line, split each line into a list, rejoin the list with commas, then write the list to disk. - filename = 'input_file.txt'
-
outname = 'output_file.txt'
-
-
f = open(filename)
-
lineList = [','.join(items) for items in [line.split() for line in f]]
-
f.close()
-
-
f = open(outname, 'w')
-
f.write('\n'.join(lineList))
-
f.close()
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