Hello,
I am having trouble writing the code to read a binary string. I would
like to extract the values for use in a calculation.
Any help would be great.
Here is my function that takes in a string.
def parseSequence(d ata, start):
group_num = data[start:start+2]
element_num = data[start+2:start+4]
vl_field = data[start+4:start+8]
length = struct.unpack(' hh', vl_field)[0]
value = data[start+8:(start+ 8+length)]
pos = start+8+length
element = (group_num+elem ent_num)
if element == '\xfe\xff\x00\x e0':
data = value
while start < length:
group_num = data[start:start+2]
element_num = data[start+2:start+4]
vl_field = data[start+4:start+8]
length = struct.unpack(' hh', vl_field)[0]
value = data[start+8:(start+ 8+length)]
start = start+8+length
element = (group_num+elem ent_num)
if element == '\xfe\xff\x00\x e0':
data = value
while start < length:
group_num = data[start:start+2]
element_num = data[start+2:start+4]
vl_field = data[start+4:start+8]
length = struct.unpack(' hh', vl_field)[0]
value = data[start+8:(start+ 8+length)]
start = start+8+length
element = (group_num+elem ent_num)
return element, start, value
else:
return element, start, value
else:
return element, pos, value
And, here is a sample string (I have split up and indented for
readability). There is an identifier (\xfe\xff\x00\x e0) followed by
the length of the nested values.
'\xfe\xff\x00\x e0\x18\x02\x00\ x00 -length=536
\n0q\x00\x02\x0 0\x00\x001
\n0x\x00\x02\x0 0\x00\x0010
\n0\x80\x00\x02 \x00\x00\x004
\n0\xa0\x00\x02 \x00\x00\x000
\x0c0\x04\x00\x e8\x01\x00\x00
\xfe\xff\x00\xe 0p\x00\x00\x00 -length=112
\n0\x82\x002\x0 0\x00\x0042.906 8704277562\\-392.3545926477\
\189.1821120994 44
\n0\x84\x00\x0c \x00\x00\x008.9 617062e-1
\n0\x86\x00\x10 \x00\x00\x00127 .378510918301
\x0c0\x06\x00\x 02\x00\x00\x001
\xfe\xff\x00\xe 0p\x00\x00\x00 -length=112
\n0\x82\x002\x0 0\x00\x0042.906 8704277562\\-392.3545926477\
\189.1821120994 44
\n0\x84\x00\x0c \x00\x00\x001.6 29998e-1
\n0\x86\x00\x10 \x00\x00\x0023. 159729257873
\x0c0\x06\x00\x 02\x00\x00\x004
\xfe\xff\x00\xe 0t\x00\x00\x00 -length=116
\n0\x82\x002\x0 0\x00\x0042.906 8704277562\\-392.3545926477\
\189.1821120994 44
\n0\x84\x00\x10 \x00\x00\x001.2 6285318894435
\n0\x86\x00\x10 \x00\x00\x00227 .690980638769
\x0c0\x06\x00\x 02\x00\x00\x003
\xfe\xff\x00\xe 0t\x00\x00\x00 -length=116
\n0\x82\x002\x0 0\x00\x0042.906 8704277562\\-392.3545926477\
\189.1821120994 44
\n0\x84\x00\x10 \x00\x00\x001.5 2797639111557
\n0\x86\x00\x10 \x00\x00\x00263 .433384670643
\x0c0\x06\x00\x 02\x00\x00\x002 ')
8  1937  Br***********@g mail.com wrote:
Hello,
I am having trouble writing the code to read a binary string. I would
like to extract the values for use in a calculation.
Any help would be great.
Without having looked at your code an any detail, may I humbly suggest
that you throw it all out and use the struct module: http://docs.python.org/lib/module-struct.html
It is meant to solve this kind of problem, and it is quite easy to use.
Gary Herron
Here is my function that takes in a string.
def parseSequence(d ata, start):
group_num = data[start:start+2]
element_num = data[start+2:start+4]
vl_field = data[start+4:start+8]
length = struct.unpack(' hh', vl_field)[0]
value = data[start+8:(start+ 8+length)]
pos = start+8+length
element = (group_num+elem ent_num)
if element == '\xfe\xff\x00\x e0':
data = value
while start < length:
group_num = data[start:start+2]
element_num = data[start+2:start+4]
vl_field = data[start+4:start+8]
length = struct.unpack(' hh', vl_field)[0]
value = data[start+8:(start+ 8+length)]
start = start+8+length
element = (group_num+elem ent_num)
if element == '\xfe\xff\x00\x e0':
data = value
while start < length:
group_num = data[start:start+2]
element_num = data[start+2:start+4]
vl_field = data[start+4:start+8]
length = struct.unpack(' hh', vl_field)[0]
value = data[start+8:(start+ 8+length)]
start = start+8+length
element = (group_num+elem ent_num)
return element, start, value
else:
return element, start, value
else:
return element, pos, value
And, here is a sample string (I have split up and indented for
readability). There is an identifier (\xfe\xff\x00\x e0) followed by
the length of the nested values.
'\xfe\xff\x00\x e0\x18\x02\x00\ x00 -length=536
\n0q\x00\x02\x0 0\x00\x001
\n0x\x00\x02\x0 0\x00\x0010
\n0\x80\x00\x02 \x00\x00\x004
\n0\xa0\x00\x02 \x00\x00\x000
\x0c0\x04\x00\x e8\x01\x00\x00
\xfe\xff\x00\xe 0p\x00\x00\x00 -length=112
\n0\x82\x002\x0 0\x00\x0042.906 8704277562\\-392.3545926477\
\189.1821120994 44
\n0\x84\x00\x0c \x00\x00\x008.9 617062e-1
\n0\x86\x00\x10 \x00\x00\x00127 .378510918301
\x0c0\x06\x00\x 02\x00\x00\x001
\xfe\xff\x00\xe 0p\x00\x00\x00 -length=112
\n0\x82\x002\x0 0\x00\x0042.906 8704277562\\-392.3545926477\
\189.1821120994 44
\n0\x84\x00\x0c \x00\x00\x001.6 29998e-1
\n0\x86\x00\x10 \x00\x00\x0023. 159729257873
\x0c0\x06\x00\x 02\x00\x00\x004
\xfe\xff\x00\xe 0t\x00\x00\x00 -length=116
\n0\x82\x002\x0 0\x00\x0042.906 8704277562\\-392.3545926477\
\189.1821120994 44
\n0\x84\x00\x10 \x00\x00\x001.2 6285318894435
\n0\x86\x00\x10 \x00\x00\x00227 .690980638769
\x0c0\x06\x00\x 02\x00\x00\x003
\xfe\xff\x00\xe 0t\x00\x00\x00 -length=116
\n0\x82\x002\x0 0\x00\x0042.906 8704277562\\-392.3545926477\
\189.1821120994 44
\n0\x84\x00\x10 \x00\x00\x001.5 2797639111557
\n0\x86\x00\x10 \x00\x00\x00263 .433384670643
\x0c0\x06\x00\x 02\x00\x00\x002 ')
On Mar 29, 3:44 pm, "Bryan.Fodn...@ gmail.com"
<Bryan.Fodn...@ gmail.comwrote:
Hello,
I am having trouble writing the code to read a binary string. I would
like to extract the values for use in a calculation.
Any help would be great.
I'm too lazy to debug your binary string, but I suggest that you
completely throw away the binary file and restart with a database or
structured text. See, for example: http://pyyaml.org/wiki/PyYAML
If you have some legacy binary file that you need to process, try
creating a C program that freads the binary file and printfs a text
equivalent.
If the decision of using binary files is not yours, then
>
Here is my function that takes in a string.
def parseSequence(d ata, start):
group_num = data[start:start+2]
element_num = data[start+2:start+4]
vl_field = data[start+4:start+8]
length = struct.unpack(' hh', vl_field)[0]
value = data[start+8:(start+ 8+length)]
pos = start+8+length
element = (group_num+elem ent_num)
if element == '\xfe\xff\x00\x e0':
data = value
while start < length:
group_num = data[start:start+2]
element_num = data[start+2:start+4]
vl_field = data[start+4:start+8]
length = struct.unpack(' hh', vl_field)[0]
value = data[start+8:(start+ 8+length)]
start = start+8+length
element = (group_num+elem ent_num)
if element == '\xfe\xff\x00\x e0':
data = value
while start < length:
group_num = data[start:start+2]
element_num = data[start+2:start+4]
vl_field = data[start+4:start+8]
length = struct.unpack(' hh', vl_field)[0]
value = data[start+8:(start+ 8+length)]
start = start+8+length
element = (group_num+elem ent_num)
return element, start, value
else:
return element, start, value
else:
return element, pos, value
And, here is a sample string (I have split up and indented for
readability). There is an identifier (\xfe\xff\x00\x e0) followed by
the length of the nested values.
'\xfe\xff\x00\x e0\x18\x02\x00\ x00 -length=536
\n0q\x00\x02\x0 0\x00\x001
\n0x\x00\x02\x0 0\x00\x0010
\n0\x80\x00\x02 \x00\x00\x004
\n0\xa0\x00\x02 \x00\x00\x000
\x0c0\x04\x00\x e8\x01\x00\x00
\xfe\xff\x00\xe 0p\x00\x00\x00 -length=112
\n0\x82\x002\x0 0\x00\x0042.906 8704277562\\-392.3545926477\
\189.1821120994 44
\n0\x84\x00\x0c \x00\x00\x008.9 617062e-1
\n0\x86\x00\x10 \x00\x00\x00127 .378510918301
\x0c0\x06\x00\x 02\x00\x00\x001
\xfe\xff\x00\xe 0p\x00\x00\x00 -length=112
\n0\x82\x002\x0 0\x00\x0042.906 8704277562\\-392.3545926477\
\189.1821120994 44
\n0\x84\x00\x0c \x00\x00\x001.6 29998e-1
\n0\x86\x00\x10 \x00\x00\x0023. 159729257873
\x0c0\x06\x00\x 02\x00\x00\x004
\xfe\xff\x00\xe 0t\x00\x00\x00 -length=116
\n0\x82\x002\x0 0\x00\x0042.906 8704277562\\-392.3545926477\
\189.1821120994 44
\n0\x84\x00\x10 \x00\x00\x001.2 6285318894435
\n0\x86\x00\x10 \x00\x00\x00227 .690980638769
\x0c0\x06\x00\x 02\x00\x00\x003
\xfe\xff\x00\xe 0t\x00\x00\x00 -length=116
\n0\x82\x002\x0 0\x00\x0042.906 8704277562\\-392.3545926477\
\189.1821120994 44
\n0\x84\x00\x10 \x00\x00\x001.5 2797639111557
\n0\x86\x00\x10 \x00\x00\x00263 .433384670643
\x0c0\x06\x00\x 02\x00\x00\x002 ')
On Mar 30, 3:58 pm, hdante <hda...@gmail.c omwrote:
On Mar 29, 3:44 pm, "Bryan.Fodn...@ gmail.com"
<Bryan.Fodn...@ gmail.comwrote:
Hello,
I am having trouble writing the code to read a binary string. I would
like to extract the values for use in a calculation.
Any help would be great.
I'm too lazy to debug your binary string, but I suggest that you
completely throw away the binary file and restart with a database or
structured text. See, for example:
http://pyyaml.org/wiki/PyYAML
If you have some legacy binary file that you need to process, try
creating a C program that freads the binary file and printfs a text
equivalent.
.... and that couldn't be done faster and better in Python??
On Mar 30, 4:31 am, John Machin <sjmac...@lexic on.netwrote:
On Mar 30, 3:58 pm, hdante <hda...@gmail.c omwrote:
On Mar 29, 3:44 pm, "Bryan.Fodn...@ gmail.com"
<Bryan.Fodn...@ gmail.comwrote:
Hello,
I am having trouble writing the code to read a binary string. I would
like to extract the values for use in a calculation.
Any help would be great.
I'm too lazy to debug your binary string, but I suggest that you
completely throw away the binary file and restart with a database or
structured text. See, for example:
http://pyyaml.org/wiki/PyYAML
If you have some legacy binary file that you need to process, try
creating a C program that freads the binary file and printfs a text
equivalent.
... and that couldn't be done faster and better in Python??
No. A C struct is done faster and better than python (thus, the
correctness check is faster in C). Also, chances are high that there's
already an include file with the binary structure.
hdante schrieb:
On Mar 30, 4:31 am, John Machin <sjmac...@lexic on.netwrote:
>On Mar 30, 3:58 pm, hdante <hda...@gmail.c omwrote:
>>On Mar 29, 3:44 pm, "Bryan.Fodn...@ gmail.com"
<Bryan.Fodn.. .@gmail.comwrot e:
Hello,
I am having trouble writing the code to read a binary string. I would
like to extract the values for use in a calculation.
Any help would be great.
I'm too lazy to debug your binary string, but I suggest that you
completely throw away the binary file and restart with a database or
structured text. See, for example:
http://pyyaml.org/wiki/PyYAML
If you have some legacy binary file that you need to process, try
creating a C program that freads the binary file and printfs a text
equivalent.
... and that couldn't be done faster and better in Python??
No. A C struct is done faster and better than python (thus, the
correctness check is faster in C). Also, chances are high that there's
already an include file with the binary structure.
That is utter nonsense. There is no "correctnes s check" in C. and using
printf & thus creating strings that you then need to parse in python
just doubles the effort needlessly.
The standard-lib module "struct" is exactly what you need, nothing else.
it sure is faster than any parsing of preprocessed data, doesn't
introduce a language-mixture and is prototyped/tested much faster
because of it being python - and not C-compiler and C-debugger.
Alternatively, *IF* there were C-structure-declarations available for
the binary format, the usage of ctypes would allow for roughly the same,
even reducing the effort to create the structure definition a great deal.
Diez
On Mar 30, 9:23 am, "Diez B. Roggisch" <de...@nospam.w eb.dewrote:
hdante schrieb:
On Mar 30, 4:31 am, John Machin <sjmac...@lexic on.netwrote:
On Mar 30, 3:58 pm, hdante <hda...@gmail.c omwrote:
>On Mar 29, 3:44 pm, "Bryan.Fodn...@ gmail.com"
<Bryan.Fodn... @gmail.comwrote :
Hello,
I am having trouble writing the code to read a binary string. I would
like to extract the values for use in a calculation.
Any help would be great.
I'm too lazy to debug your binary string, but I suggest that you
completely throw away the binary file and restart with a database or
structured text. See, for example:
http://pyyaml.org/wiki/PyYAML
If you have some legacy binary file that you need to process, try
creating a C program that freads the binary file and printfs a text
equivalent.
... and that couldn't be done faster and better in Python??
No. A C struct is done faster and better than python (thus, the
correctness check is faster in C). Also, chances are high that there's
already an include file with the binary structure.
That is utter nonsense. There is no "correctnes s check" in C. and using
printf & thus creating strings that you then need to parse in python
just doubles the effort needlessly.
The standard-lib module "struct" is exactly what you need, nothing else.
it sure is faster than any parsing of preprocessed data, doesn't
introduce a language-mixture and is prototyped/tested much faster
because of it being python - and not C-compiler and C-debugger.
Alternatively, *IF* there were C-structure-declarations available for
the binary format, the usage of ctypes would allow for roughly the same,
even reducing the effort to create the structure definition a great deal.
Diez
Whatever you say.
>
Whatever you say.
Can't express what your approval means to me!
Diez
On Sun, 30 Mar 2008 04:48:59 -0700 (PDT), hdante <hd****@gmail.c omwrote:
On Mar 30, 4:31 am, John Machin <sjmac...@lexic on.netwrote:
>On Mar 30, 3:58 pm, hdante <hda...@gmail.c omwrote:
If you have some legacy binary file that you need to process, try
creating a C program that freads the binary file and printfs a text
equivalent.
... and that couldn't be done faster and better in Python??
No. A C struct is done faster and better than python (thus, the
correctness check is faster in C). Also, chances are high that there's
already an include file with the binary structure.
If a C struct defines the file format, he is probably screwed already.
There are no guarantees that even different compilers on the same
machine have the same struct layout.
I have never seen this done by a serious program.
/Jorgen
--
// Jorgen Grahn <grahn@ Ph'nglui mglw'nafh Cthulhu
\X/ snipabacken.se R'lyeh wgah'nagl fhtagn! This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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