How to pass in argument to timeit.Timer

[silverburgh.meryl]

Hi,

I have a function in my python like this:
def callFunc(line, no):
# some code

And I want to do a performance test like this:
for line in f:
for i in range(int(count )):
t1 = timeit.Timer("c allFunc(line, i)","from __main__
import callFunc")
r1 = t1.timeit();
print r1;

but when I run it, it can't recognize the parameter 'line' and 'i',
can you please tell me how to fix it? i get this error:

File "/usr/lib/python2.4/timeit.py", line 161, in timeit
timing = self.inner(it, self.timer)
File "<timeit-src>", line 6, in inner
NameError: global name 'line' is not defined

Thank you.

[Gabriel Genellina]

En Sat, 28 Apr 2007 15:48:11 -0300, si************* **@gmail.com
<si************ ***@gmail.comes cribió:

I have a function in my python like this:
def callFunc(line, no):
# some code

And I want to do a performance test like this:
for line in f:
for i in range(int(count )):
t1 = timeit.Timer("c allFunc(line, i)","from __main__
import callFunc")
r1 = t1.timeit();
print r1;

but when I run it, it can't recognize the parameter 'line' and 'i',
can you please tell me how to fix it? i get this error:

They go in the "setup" parameter, like this:

t1 = timeit.Timer("c allFunc(line, i)","from __main__ import callFunc;
line=%r; i=%d" % (line, i))

If it gets much longer, try this:

setup = """
from __main__ import callFunc
line = %r
i = %d""" % (line, i)
stmt = "callFunc(l ine, i)"
t1 = timeit.Timer(st mt, setup)

--
Gabriel Genellina

PS: Please leave out the final ; - this is Python, not C nor ...
PS2: Perhaps the only place where I've used ; is with timeit. And even
then you can avoid them as in the last example.

[silverburgh.meryl]

On Apr 28, 3:37 pm, "Gabriel Genellina" <[e-mail].a r>
wrote:

En Sat, 28 Apr 2007 15:48:11 -0300, silverburgh.me. [e-mail]
<silverburgh.me [e-mail] cribió:

I have a function in my python like this:
def callFunc(line, no):
# some code

And I want to do a performance test like this:
for line in f:
for i in range(int(count )):
t1 = timeit.Timer("c allFunc(line, i)","from __main__
import callFunc")
r1 = t1.timeit();
print r1;

but when I run it, it can't recognize the parameter 'line' and 'i',
can you please tell me how to fix it? i get this error:

They go in the "setup" parameter, like this:

t1 = timeit.Timer("c allFunc(line, i)","from __main__ import callFunc;
line=%r; i=%d" % (line, i))

Thanks I try it:

def stressTest():
for line in f:
for i in range(int(count )):
print i;
t1 = timeit.Timer("c allFunc(line, i)","from __main__
import callFunc; line=%r; i=%d" % (line, i))
r1 = t1.timeit();
times.append(r1 );
print r1;

But it keeps calling callFunc() and it never returns from my loop. The
value of 'count' is 2.

Thank you.

If it gets much longer, try this:

setup = """
from __main__ import callFunc
line = %r
i = %d""" % (line, i)
stmt = "callFunc(l ine, i)"
t1 = timeit.Timer(st mt, setup)

--
Gabriel Genellina

PS: Please leave out the final ; - this is Python, not C nor ...
PS2: Perhaps the only place where I've used ; is with timeit. And even
then you can avoid them as in the last example.

[silverburgh.meryl]

On Apr 30, 1:24 pm, "silverburgh.me [e-mail]"
<silverburgh.me [e-mail] ote:

On Apr 28, 3:37 pm, "Gabriel Genellina" <[e-mail].a r>
wrote:

En Sat, 28 Apr 2007 15:48:11 -0300, silverburgh.me. [e-mail]
<silverburgh.me [e-mail] cribió:

I have a function in my python like this:
def callFunc(line, no):
# some code

And I want to do a performance test like this:
for line in f:
for i in range(int(count )):
t1 = timeit.Timer("c allFunc(line, i)","from __main__
import callFunc")
r1 = t1.timeit();
print r1;

but when I run it, it can't recognize the parameter 'line' and 'i',
can you please tell me how to fix it? i get this error:

They go in the "setup" parameter, like this:

t1 = timeit.Timer("c allFunc(line, i)","from __main__ import callFunc;
line=%r; i=%d" % (line, i))

Thanks I try it:

def stressTest():
for line in f:
for i in range(int(count )):
print i;
t1 = timeit.Timer("c allFunc(line, i)","from __main__
import callFunc; line=%r; i=%d" % (line, i))
r1 = t1.timeit();
times.append(r1 );
print r1;

But it keeps calling callFunc() and it never returns from my loop. The
value of 'count' is 2.

Thank you.

If it gets much longer, try this:

setup = """
from __main__ import callFunc
line = %r
i = %d""" % (line, i)
stmt = "callFunc(l ine, i)"
t1 = timeit.Timer(st mt, setup)

--
Gabriel Genellina

PS: Please leave out the final ; - this is Python, not C nor ...
PS2: Perhaps the only place where I've used ; is with timeit. And even
then you can avoid them as in the last example.

I think I solve the problem by putting a number in timeit() function.
thank you.